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Statement List for Metamath Proof Explorer - 5101-5200 - Page 52 of 58
TypeLabelDescription
Statement
 
Theorembcs 5101 Bunjakovaskij-Cauchy-Schwarz inequality. Remark 3.4 of [Beran] p. 98.
A ∈ ℋ    &   B ∈ ℋ    ⇒   (abs ‘(A ·i B)) ≤ ((norm ‘A) · (norm ‘B))
 
Definitiondf-cauchy 5102 Define the set of Cauchy sequences on a Hilbert space. See hcauchy 5103 for its membership relation. Note that f:ℕ–→ ℋ is an infinite sequence of vectors, i.e. a mapping from integers to vectors. Definition of Cauchy sequence in [Beran] p. 96.
Cauchy = {f∣(f:ℕ–→ ℋ ∧ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ ∀w ∈ ℕ ((yzyw) → (norm ‘((Fz) −v (Fw))) < x)))}
 
Theoremhcauchy 5103 Member of the set of Cauchy sequences on a Hilbert space. Definition for Cauchy sequence in [Beran] p. 96.
(F ∈ Cauchy ↔ (F:ℕ–→ ℋ ∧ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ ∀w ∈ ℕ ((yzyw) → (norm ‘((Fz) −v (Fw))) < x))))
 
Theoremcauchyseq 5104 A Cauchy sequences on a Hilbert space is a sequence.
(F ∈ Cauchy → F:ℕ–→ ℋ )
 
Theoremcauchyconv 5105 A Cauchy sequence on a Hilbert space converges.
(F ∈ Cauchy → ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ ∀w ∈ ℕ ((yzyw) → (norm ‘((Fz) −v (Fw))) < x)))
 
Theoremseqcauchy 5106 A sequence on a Hilbert space is a Cauchy sequence if it converges.
(F:ℕ–→ ℋ → (F ∈ Cauchy ↔ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ ∀w ∈ ℕ ((yzyw) → (norm ‘((Fz) −v (Fw))) < x))))
 
Definitiondf-hlim 5107 Define the limit relation for Hilbert space. See hlim 5108 for its relational expression. Note that f:ℕ–→ ℋ is an infinite sequence of vectors, i.e. a mapping from integers to vectors. Definition of converge in [Beran] p. 96.
v = {⟨f, w⟩∣((f:ℕ–→ ℋ ∧ w ∈ ℋ ) ∧ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ (yz → (norm ‘((fz) −v w)) < x)))}
 
Theoremhlim 5108 Express the predicate: The limit of vector sequence F in a Hilbert space is A, i.e. F converges to A. This means that for any real x, no matter how small, there always exists an integer y such that the norm of any later vector in the sequence minus the limit is less than x. Definition of converge in [Beran] p. 96.
FV    &   AV    ⇒   (Fv A ↔ ((F:ℕ–→ ℋ ∧ A ∈ ℋ ) ∧ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ (yz → (norm ‘((Fz) −v A)) < x))))
 
Theoremhlimseq 5109 A sequence with a limit on a Hilbert space is a sequence.
FV    &   AV    ⇒   (Fv AF:ℕ–→ ℋ )
 
Theoremhlimvec 5110 Closure of the limit of a sequence on Hilbert space.
FV    &   AV    ⇒   (Fv AA ∈ ℋ )
 
Theoremhlimconv 5111 Convergence of a sequence on a Hilbert space.
FV    &   AV    ⇒   (Fv A → ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ (yz → (norm ‘((Fz) −v A)) < x)))
 
Theoremhlim2 5112 The limit of a sequence on a Hilbert space.
((F:ℕ–→ ℋ ∧ A ∈ ℋ ) → (Fv A ↔ ∀x ∈ ℝ (0 < x → ∃y ∈ ℕ ∀z ∈ ℕ (yz → (norm ‘((Fz) −v A)) < x))))
 
Axiomax-hcompl 5113 Completeness of a Hilbert space.
(F ∈ Cauchy → ∃x ∈ ℋ Fv x)
 
Definitiondf-sh 5114 Define the set of subspaces of a Hilbert space. See sh 5116 for its membership relation. Basically, a subspace is a subset of a Hilbert space that acts like a vector space. From Definition of [Beran] p. 95.
S = {h∣((h ⊆ ℋ ∧ 0vh) ∧ (∀xhyh (x +v y) ∈ h ∧ ∀x ∈ ℂ ∀yh (x ·s y) ∈ h))}
 
Theoremshex 5115 The set of subspaces of a Hilbert space exists (is a set).
SV
 
Theoremsh 5116 Subspace H of a Hilbert space. A subspace is a subset of Hilbert space which contains the zero vector and is closed under vector addition and scalar multiplication. Definition of [Beran] p. 95.
(HS ↔ ((H ⊆ ℋ ∧ 0vH) ∧ (∀xHyH (x +v y) ∈ H ∧ ∀x ∈ ℂ ∀yH (x ·s y) ∈ H)))
 
Theoremshss 5117 A subspace is a subset of Hilbert space.
(HSH ⊆ ℋ )
 
Theoremshelt 5118 A member of a subspace of a Hilbert space is a vector.
((HSAH) → A ∈ ℋ )
 
Theoremshssi 5119 A closed subspace of a Hilbert space is a subset of Hilbert space.
HS    ⇒   H ⊆ ℋ
 
Theoremshel 5120 A member of a subspace of a Hilbert space is a vector.
HS    ⇒   (AHA ∈ ℋ )
 
Theoremsheli 5121 A member of a subspace of a Hilbert space is a vector.
HS    &   AH    ⇒   A ∈ ℋ
 
Theoremsh0 5122 The zero vector belongs to any subspace of a Hilbert space.
(HS → 0vH)
 
Theoremshaddclt 5123 Closure of vector addition in a subspace of a Hilbert space.
(HS → ((AHBH) → (A +v B) ∈ H))
 
Theoremshmulclt 5124 Closure of vector scalar multiplication in a subspace of a Hilbert space.
(HS → ((A ∈ ℂ ∧ BH) → (A ·s B) ∈ H))
 
Theoremshsubclt 5125 Closure of vector subtraction in a subspace of a Hilbert space.
(HS → ((AHBH) → (Av B) ∈ H))
 
Theoremsh2 5126 Subspace H of a Hilbert space.
(H ⊆ ℋ → (HS ↔ (0vH ∧ (∀xHyH (x +v y) ∈ H ∧ ∀x ∈ ℂ ∀yH (x ·s y) ∈ H))))
 
Definitiondf-ch 5127 Define the set of closed subspaces of a Hilbert space. A closed subspace is one in which the limit of every convergent sequence in the subspace belongs to the subspace. For its membership relation, see closedsub 5128. From Definition of [Beran] p. 107. Alternate definitions are given by chcmh 5148 and dfch2 5254.
C = {h∣(hS ∧ ∀fx((f:ℕ–→hfv x) → xh))}
 
Theoremclosedsub 5128 Closed subspace H of a Hilbert space. Definition of [Beran] p. 107.
(HC ↔ (HS ∧ ∀fx((f:ℕ–→Hfv x) → xH)))
 
Theoremchsssh 5129 Closed subspaces are subspaces in a Hilbert space.
CS
 
Theoremchex 5130 The set of closed subspaces of a Hilbert space exists (is a set).
CV
 
Theoremchsh 5131 A closed subspace is a subspace.
(HCHS )
 
Theoremchshi 5132 A closed subspace is a subspace.
HC    ⇒   HS
 
Theoremch0 5133 The zero vector belongs to any closed subspace of a Hilbert space.
(HC → 0vH)
 
Theoremchss 5134 A closed subspace of a Hilbert space is a subset of Hilbert space.
(HCH ⊆ ℋ )
 
Theoremchelt 5135 A member of a closed subspace of a Hilbert space is a vector.
((HCAH) → A ∈ ℋ )
 
Theoremchssi 5136 A closed subspace of a Hilbert space is a subset of Hilbert space.
HC    ⇒   H ⊆ ℋ
 
Theoremchel 5137 A member of a closed subspace of a Hilbert space is a vector.
HC    ⇒   (AHA ∈ ℋ )
 
Theoremcheli 5138 A member of a closed subspace of a Hilbert space is a vector.
HC    &   AH    ⇒   A ∈ ℋ
 
Theoremchlim 5139 The limit property of a closed subspace of a Hilbert space.
AV    ⇒   (HC → ((F:ℕ–→HFv A) → AH))
 
Theoremhlim0 5140 The zero sequence in Hilbert space converges to the zero vector.
(ℕ × {0v}) ⇝v 0v
 
Theoremhlimcaui 5141 If a sequence in Hilbert space subset converges to a limit, it is a Cauchy sequence.
AV    &   FV    &   Fv A    ⇒   F ∈ Cauchy
 
Theoremhlimcau 5142 If a sequence in Hilbert space subset converges to a limit, it is a Cauchy sequence.
AV    &   FV    ⇒   (Fv AF ∈ Cauchy)
 
Theoremhlimunii 5143 A Hilbert space sequence converges to at most one limit.
AV    &   BV    &   FV    &   (Fv AFv B)    ⇒   A = B
 
Theoremhlimuni 5144 A Hilbert space sequence converges to at most one limit.
AV    &   BV    &   FV    ⇒   ((Fv AFv B) → A = B)
 
Theoremhlimreu 5145 The limit of a Hilbert space sequence is unique.
FV    ⇒   (∃xH Fv x ↔ ∃!xH Fv x)
 
Theoremhlimeu 5146 The limit of a Hilbert space sequence is unique.
FV    ⇒   (∃x Fv x ↔ ∃!x Fv x)
 
Theoremchsscm 5147 The hypothesis defines the set of complete subspaces of Hilbert space. A complete subspace is one in which every Cauchy sequence of vectors in the subspace converges to a member of the subspace (Definition of complete subspace in [Beran] p. 96). Any closed subspace of a Hilbert space is complete. Part of Remark 3.12 of [Beran] p. 107.
C = {h∣(hS ∧ ∀f ∈ Cauchy (f:ℕ–→h → ∃xh fv x))}    ⇒    CC
 
Theoremchcmh 5148 The hypothesis defines the set of complete subspaces of Hilbert space (see chsscm 5147). A Hilbert subspace is closed iff it is complete. Remark 3.12(C) of [Beran] p. 107.
C = {h∣(hS ∧ ∀f ∈ Cauchy (f:ℕ–→h → ∃xh fv x))}    ⇒    C = C
 
Theoremch2 5149 A Hilbert subspace is closed iff it is complete. Remark 3.12(C) of [Beran] p. 107.
(HC ↔ (HS ∧ ∀f ∈ Cauchy (f:ℕ–→H → ∃xH fv x)))
 
Theoremchcompl 5150 Completeness of a closed subspace of Hilbert space.
(HC → ((F ∈ Cauchy ∧ F:ℕ–→H) → ∃xH Fv x))
 
Theoremhelch 5151 The unit Hilbert lattice element (which is all of Hilbert space) belongs to the Hilbert lattice. Part of Proposition 1 of [Kalmbach] p. 65.
ℋ ∈ C
 
Theoremhelsh 5152 Hilbert space is a subspace of Hilbert space.
ℋ ∈ S
 
Theoremshsspwh 5153 Subspaces are subsets of Hilbert space.
S ⊆ ℘ ℋ
 
Theoremchsspwh 5154 Closed subspaces are subsets of Hilbert space.
C ⊆ ℘ ℋ
 
Theoremhsn0elch 5155 The zero subspace belongs to the set of closed subspaces of Hilbert space.
{0v} ∈ C
 
Definitiondf-oc 5156 Define orthogonal complement of a subset (usually a subspace) of Hilbert space. The orthogonal complement is the set of all vectors orthogonal to all vectors in the subset. See ocvalt 5161 and chocval 5178 for its value. Textbooks usually denote this unary operation with the symbol ⊥ as a small superscript, although Mittelstaedt uses the symbol as a prefix operation. Here we define a function (prefix operation) ⊥ rather than introducing a new syntactical form. This lets us take advantage of the theorems about functions that we already have proved under set theory. Definition of [Mittelstaedt] p. 9.
⊥ = {⟨x, y⟩∣(x ⊆ ℋ ∧ y = {z ∈ ℋ ∣∀wx (z ·i w) = 0})}
 
Definitiondf-ch0 5157 Define the zero for closed subspaces of Hilbert space. See h0elch 5159 for closure law.
0 = {0v}
 
Theoremelch0 5158 Membership in zero for closed subspaces of Hilbert space.
(A ∈ 0A = 0v)
 
Theoremh0elch 5159 The zero subspace is a closed subspace. Part of Proposition 1 of [Kalmbach] p. 65.
0C
 
Theoremh0elsh 5160 The zero subspace is a subspace of Hilbert space.
0S
 
Theoremocvalt 5161 Value of orthogonal complement of a subset of Hilbert space.
(H ⊆ ℋ → (⊥ ‘H) = {x ∈ ℋ ∣∀yH (x ·i y) = 0})
 
Theoremocelt 5162 Membership in orthogonal complement of H subset.
(H ⊆ ℋ → (A ∈ (⊥ ‘H) ↔ (A ∈ ℋ ∧ ∀xH (A ·i x) = 0)))
 
Theoremshocelt 5163 Membership in orthogonal complement of H subspace.
(HS → (A ∈ (⊥ ‘H) ↔ (A ∈ ℋ ∧ ∀xH (A ·i x) = 0)))
 
Theoremocsh 5164 The orthogonal complement of a subspace is a subspace. Part of Remark 3.12 of [Beran] p. 107.
(A ⊆ ℋ → (⊥ ‘A) ∈ S )
 
Theoremshocsh 5165 The orthogonal complement of a subspace is a subspace. Part of Remark 3.12 of [Beran] p. 107.
(AS → (⊥ ‘A) ∈ S )
 
Theoremocss 5166 An orthogonal complement is a subset of Hilbert space.
(A ⊆ ℋ → (⊥ ‘A) ⊆ ℋ )
 
Theoremshocss 5167 An orthogonal complement is a subset of Hilbert space.
(AS → (⊥ ‘A) ⊆ ℋ )
 
Theoremoccont 5168 Contraposition law for orthogonal complement.
((A ⊆ ℋ ∧ B ⊆ ℋ ) → (AB → (⊥ ‘B) ⊆ (⊥ ‘A)))
 
Theoremoccon2t 5169 Double contraposition for orthogonal complement.
((A ⊆ ℋ ∧ B ⊆ ℋ ) → (AB → (⊥ ‘(⊥ ‘A)) ⊆ (⊥ ‘(⊥ ‘B))))
 
Theoremoccon2 5170 Double contraposition for orthogonal complement.
A ⊆ ℋ    &   B ⊆ ℋ    ⇒   (AB → (⊥ ‘(⊥ ‘A)) ⊆ (⊥ ‘(⊥ ‘B)))
 
Theoremoc0 5171 The zero vector belongs to an orthogonal complement of a Hilbert subspace.
(HS → 0v ∈ (⊥ ‘H))
 
Theoremocorth 5172 Members of a subset and its complement are orthogonal.
(H ⊆ ℋ → ((AHB ∈ (⊥ ‘H)) → (A ·i B) = 0))
 
Theoremshocorth 5173 Members of a subspace and its complement are orthogonal.
(HS → ((AHB ∈ (⊥ ‘H)) → (A ·i B) = 0))
 
Theoremococss 5174 Inclusion in complement of complement. Part of Proposition 1 of [Kalmbach] p. 65.
(A ⊆ ℋ → A ⊆ (⊥ ‘(⊥ ‘A)))
 
Theoremshococss 5175 Inclusion in complement of complement. Part of Proposition 1 of [Kalmbach] p. 65.
(ASA ⊆ (⊥ ‘(⊥ ‘A)))
 
Theoremshorth 5176 Members of orthogonal subspaces are orthogonal.
(HS → (G ⊆ (⊥ ‘H) → ((AGBH) → (A ·i B) = 0)))
 
Theoremocin 5177 Intersection of a Hilbert subspace and its complement. Part of Proposition 1 of [Kalmbach] p. 65.
(AS → (A ∩ (⊥ ‘A)) = 0)
 
Theoremchocval 5178 Value of the orthogonal complement of a Hilbert lattice element. The orthogonal complement of A is the set of vectors that are orthogonal to all vectors in A.
AC    ⇒   (⊥ ‘A) = {x ∈ ℋ ∣∀yA (x ·i y) = 0}
 
Theoremchocuni 5179 Lemma for uniqueness part of Projection Theorem. Theorem 3.7(i) of [Beran] p. 102 (uniqueness part).
HC    ⇒   (((AHB ∈ (⊥ ‘H)) ∧ (CHD ∈ (⊥ ‘H))) → ((R = (A +v B) ∧ R = (C +v D)) → (A = CB = D)))
 
Theoremoccllem1 5180 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
A ∈ ℋ    &   B ∈ ℋ    &   S ∈ ℋ    ⇒   (abs ‘((B ·i S) − (A ·i S))) ≤ ((norm ‘(Bv A)) · (norm ‘S))
 
Theoremoccllem2 5181 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
S ∈ ℋ    ⇒   ((A ∈ ℋ ∧ B ∈ ℋ ) → (abs ‘((B ·i S) − (A ·i S))) ≤ ((norm ‘(Bv A)) · (norm ‘S)))
 
Theoremoccllem3 5182 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
G = {⟨x, y⟩∣(x ∈ ℕ ∧ y = ((Fx) ·i S))}    ⇒   (D ∈ ℕ → (GD) = ((FD) ·i S))
 
Theoremoccllem4 5183 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
G = {⟨x, y⟩∣(x ∈ ℕ ∧ y = ((Fx) ·i S))}    &   S ∈ ℋ    ⇒   (F:ℕ–→ ℋ → G:ℕ–→ℂ)
 
Theoremoccllem5 5184 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
G = {⟨x, y⟩∣(x ∈ ℕ ∧ y = ((Fx) ·i S))}    ⇒   (∀z ∈ ℕ ((Fz) ·i S) = 0 → G ⇝ 0)
 
Theoremoccllem6 5185 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
G = {⟨x, y⟩∣(x ∈ ℕ ∧ y = ((Fx) ·i S))}    &   A ∈ ℋ    &   S ∈ ℋ    &   FV    ⇒   S = 0v → (Fv AG ⇝ (A ·i S)))
 
Theoremoccllem7 5186 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
A ∈ ℋ    &   S ∈ ℋ    &   FV    ⇒   ((Fv A ∧ ∀x ∈ ℕ ((Fx) ·i S) = 0) → (A ·i S) = 0)
 
Theoremoccllem8 5187 Lemma for closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
FV    ⇒   ((A ∈ ℋ ∧ S ∈ ℋ ) → ((Fv A ∧ ∀x ∈ ℕ ((Fx) ·i S) = 0) → (A ·i S) = 0))
 
Theoremoccl 5188 Closure of complement of Hilbert subset. Part of Remark 3.12 of [Beran] p. 107.
A ⊆ ℋ    ⇒   (⊥ ‘A) ∈ C
 
Theoremocclt 5189 Closure of complement of Hilbert subset. Part of Remark 3.12 of [Beran] p. 107.
(A ⊆ ℋ → (⊥ ‘A) ∈ C )
 
Theoremshocclt 5190 Closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
(AS → (⊥ ‘A) ∈ C )
 
Theoremchoclt 5191 Closure of complement of Hilbert subspace. Part of Remark 3.12 of [Beran] p. 107.
(AC → (⊥ ‘A) ∈ C )
 
Theoremchocl 5192 Closure of C orthocomplement.
AC    ⇒   (⊥ ‘A) ∈ C
 
Theoremprojlem1 5193 Part of Lemma 3.6 of [Beran] p. 100: "Choose e > 0. Let n0 be a natural number satisfying the inequality n0 > 4(2i0 + 1) · e ↑ -1." Used by projlem2 5194.
R ∈ ℝ    &   D ∈ ℝ    ⇒   (0 < D → ∃z ∈ ℕ ((4 · ((2 · R) + 1)) / z) < (D↑2))
 
Theoremprojlem2 5194 Part of Lemma 3.6 of [Beran] p. 100. We need the square root for the norm limit. Used by projlem28 5220.
R ∈ ℝ    &   D ∈ ℝ    &   0 ≤ R    ⇒   (0 < D → ∃z ∈ ℕ (√ ‘((4 · ((2 · R) + 1)) / z)) < D)
 
Theoremprojlem3 5195 Part of Lemma 3.6 of [Beran] p. 100, bottom inequality. Used by projlem6 5198.
R ∈ ℝ    &   D ∈ ℕ    &   G ∈ ℕ    ⇒   (((2 · ((R + (1 / D))↑2)) + (2 · ((R + (1 / G))↑2))) − (4 · (R↑2))) ≤ (((4 · R) + 2) · ((1 / D) + (1 / G)))
 
Theoremprojlem4 5196 Part of Lemma 3.6 of [Beran] p. 101, top. Used by projlem6 5198.
R ∈ ℝ    &   0 ≤ R    &   D ∈ ℕ    &   G ∈ ℕ    &   B ∈ ℕ    ⇒   ((BDBG) → (((4 · R) + 2) · ((1 / D) + (1 / G))) ≤ ((4 · ((2 · R) + 1)) / B))
 
Theoremprojlem5 5197 Part of Lemma 3.6 of [Beran] p. 100, bottom. Used by projlem6 5198.
A ∈ ℋ    &   B ∈ ℋ    &   C ∈ ℋ    &   R ∈ ℝ    &   0 ≤ R    &   (4 · (R↑2)) ≤ ((norm ‘((B +v C) −v (2 ·s A)))↑2)    &   D ∈ ℕ    &   G ∈ ℕ    &   N ∈ ℕ    &   (norm ‘(Bv A)) < (R + (1 / D))    &   (norm ‘(Cv A)) < (R + (1 / G))    ⇒   ((norm ‘(Bv C))↑2) < (((2 · ((R + (1 / D))↑2)) + (2 · ((R + (1 / G))↑2))) − (4 · (R↑2)))
 
Theoremprojlem6 5198 Part of Lemma 3.6 of [Beran] p. 101. Used by projlem7 5199.
A ∈ ℋ    &   B ∈ ℋ    &   C ∈ ℋ    &   R ∈ ℝ    &   0 ≤ R    &   (4 · (R↑2)) ≤ ((norm ‘((B +v C) −v (2 ·s A)))↑2)    &   D ∈ ℕ    &   G ∈ ℕ    &   N ∈ ℕ    &   (norm ‘(Bv A)) < (R + (1 / D))    &   (norm ‘(Cv A)) < (R + (1 / G))    ⇒   ((NDNG) → (norm ‘(Bv C)) < (√ ‘((4 · ((2 · R) + 1)) / N)))
 
Theoremprojlem7 5199 Part of Lemma 3.6 of [Beran] p. 101. Applies weak deduction theorem to projlem6 5198. Used by projlem19 5211.
A ∈ ℋ    &   B ∈ ℋ    &   C ∈ ℋ    &   R ∈ ℝ    &   0 ≤ R    &   (4 · (R↑2)) ≤ ((norm ‘((B +v C) −v (2 ·s A)))↑2)    &   D ∈ ℕ    &   G ∈ ℕ    &   N ∈ ℕ    ⇒   (((norm ‘(Bv A)) < (R + (1 / D)) ∧ (norm ‘(Cv A)) < (R + (1 / G))) → ((NDNG) → (norm ‘(Bv C)) < (√ ‘((4 · ((2 · R) + 1)) / N))))
 
Theoremprojlem8 5200 Part of Lemma 3.6 of [Beran] p. 100. The set S is a non-empty set of reals with an upper bound. Part of Lemma 3.6 of [Beran] p. 100. Used by projlem9 5201 projlem12 5204 projlem13 5205 projlem15 5207. Note we use 'supremum'; its negative is the infimum.
A ∈ ℋ    &   HC    &   S = {u ∈ ℝ∣∃vH u = -(norm ‘(vv A))}    ⇒   (S ⊆ ℝ ∧ ¬ S = ∅ ∧ ∃z ∈ ℝ ∀wS wz)

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