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Statement List for Metamath Proof Explorer - 5401-5500 - Page 55 of 58
TypeLabelDescription
Statement
 
Theoremchdmm4 5401 DeMorgan's law for meet in a Hilbert lattice.
AC    &   BC    ⇒   (⊥ ‘((⊥ ‘A) ∩ (⊥ ‘B))) = (A B)
 
Theoremchdmj1 5402 DeMorgan's law for join in a Hilbert lattice.
AC    &   BC    ⇒   (⊥ ‘(A B)) = ((⊥ ‘A) ∩ (⊥ ‘B))
 
Theoremchdmj2 5403 DeMorgan's law for join in a Hilbert lattice.
AC    &   BC    ⇒   (⊥ ‘((⊥ ‘A) ∨ B)) = (A ∩ (⊥ ‘B))
 
Theoremchdmj3 5404 DeMorgan's law for join in a Hilbert lattice.
AC    &   BC    ⇒   (⊥ ‘(A (⊥ ‘B))) = ((⊥ ‘A) ∩ B)
 
Theoremchdmj4 5405 DeMorgan's law for join in a Hilbert lattice.
AC    &   BC    ⇒   (⊥ ‘((⊥ ‘A) ∨ (⊥ ‘B))) = (AB)
 
Theoremchnle 5406 Equivalent expressions for "not less than" in the Hilbert lattice.
AC    &   BC    ⇒   BAA ⊂ (A B))
 
Theoremchjass 5407 Associative law for Hilbert lattice join. From definition of lattice in [Kalmbach] p. 14.
AC    &   BC    &   CC    ⇒   ((A B) ∨ C) = (A (B C))
 
Theoremchj00 5408 Two Hilbert lattice elements are zero iff their join is zero.
AC    &   BC    ⇒   ((A = 0B = 0) ↔ (A B) = 0)
 
Theoremchjo 5409 The join of a closed subspace and its orthocomplement.
AC    ⇒   (A (⊥ ‘A)) = ℋ
 
Theoremchj1 5410 Join with Hilbert lattice unit.
AC    ⇒   (A ℋ ) = ℋ
 
Theoremchm0 5411 Meet with Hilbert lattice zero.
AC    ⇒   (A ∩ 0) = 0
 
Theoremshjshs 5412 Hilbert lattice join equals the double orthocomplement of subspace sum.
AS    &   BS    ⇒   (A B) = (⊥ ‘(⊥ ‘(A + B)))
 
Theoremshjshsel 5413 A closed subspace sum equals Hilbert lattice join. Part of Lemma 31.1.5 of [MaedaMaeda] p. 136.
AS    &   BS    ⇒   ((A + B) ∈ C ↔ (A + B) = (A B))
 
Theoremchj0t 5414 Join with Hilbert lattice zero.
(AC → (A 0) = A)
 
Theoremchslejt 5415 Subspace sum is smaller than subspace join. Remark of [Kalmbach] p. 65.
((ACBC ) → (A + B) ⊆ (A B))
 
Theoremchinclt 5416 Closure of Hilbert lattice intersection.
((ACBC ) → (AB) ∈ C )
 
Theoremchsscon3t 5417 Hilbert lattice contraposition law.
((ACBC ) → (AB ↔ (⊥ ‘B) ⊆ (⊥ ‘A)))
 
Theoremchsscon1t 5418 Hilbert lattice contraposition law.
((ACBC ) → ((⊥ ‘A) ⊆ B ↔ (⊥ ‘B) ⊆ A))
 
Theoremchsscon2t 5419 Hilbert lattice contraposition law.
((ACBC ) → (A ⊆ (⊥ ‘B) ↔ B ⊆ (⊥ ‘A)))
 
Theoremchpsscon3t 5420 Hilbert lattice contraposition law for strict ordering.
((ACBC ) → (AB ↔ (⊥ ‘B) ⊂ (⊥ ‘A)))
 
Theoremchpsscon1t 5421 Hilbert lattice contraposition law for strict ordering.
((ACBC ) → ((⊥ ‘A) ⊂ B ↔ (⊥ ‘B) ⊂ A))
 
Theoremchpsscon2t 5422 Hilbert lattice contraposition law for strict ordering.
((ACBC ) → (A ⊂ (⊥ ‘B) ↔ B ⊂ (⊥ ‘A)))
 
Theoremchjcomt 5423 Commutative law for Hilbert lattice join.
((ACBC ) → (A B) = (B A))
 
Theoremchub1t 5424 Hilbert lattice join is greater than or equal to its first argument.
((ACBC ) → A ⊆ (A B))
 
Theoremchub2t 5425 Hilbert lattice join is greater than or equal to its second argument.
((ACBC ) → A ⊆ (B A))
 
Theoremchlubt 5426 Hilbert lattice join is the least upper bound of two elements.
((ACBCCC ) → ((ACBC) ↔ (A B) ⊆ C))
 
Theoremchlej1t 5427 Add join to both sides of Hilbert lattice ordering.
((ACBCCC ) → (AB → (A C) ⊆ (B C)))
 
Theoremchlej2t 5428 Add join to both sides of Hilbert lattice ordering.
((ACBCCC ) → (AB → (C A) ⊆ (C B)))
 
Theoremchlejb1t 5429 Hilbert lattice ordering in terms of join.
((ACBC ) → (AB ↔ (A B) = B))
 
Theoremchlejb2t 5430 Hilbert lattice ordering in terms of join.
((ACBC ) → (AB ↔ (B A) = B))
 
Theoremchnlet 5431 Equivalent expressions for "not less than" in the Hilbert lattice.
((ACBC ) → (¬ BAA ⊂ (A B)))
 
Theoremchabs1t 5432 Hilbert lattice absorption law. From definition of lattice in [Kalmbach] p. 14.
((ACBC ) → (A (AB)) = A)
 
Theoremchabs2t 5433 Hilbert lattice absorption law. From definition of lattice in [Kalmbach] p. 14.
((ACBC ) → (A ∩ (A B)) = A)
 
Theoremchabs1 5434 Hilbert lattice absorption law. From definition of lattice in [Kalmbach] p. 14.
AC    &   BC    ⇒   (A (AB)) = A
 
Theoremchabs2 5435 Hilbert lattice absorption law. From definition of lattice in [Kalmbach] p. 14.
AC    &   BC    ⇒   (A ∩ (A B)) = A
 
Theoremchjidmt 5436 Idempotent law for Hilbert lattice join.
(AC → (A A) = A)
 
Theoremchjidm 5437 Idempotent law for Hilbert lattice join.
AC    ⇒   (A A) = A
 
Theoremchdmm1t 5438 DeMorgan's law for meet in a Hilbert lattice.
((ACBC ) → (⊥ ‘(AB)) = ((⊥ ‘A) ∨ (⊥ ‘B)))
 
Theoremchdmm2t 5439 DeMorgan's law for meet in a Hilbert lattice.
((ACBC ) → (⊥ ‘((⊥ ‘A) ∩ B)) = (A (⊥ ‘B)))
 
Theoremchdmm3t 5440 DeMorgan's law for meet in a Hilbert lattice.
((ACBC ) → (⊥ ‘(A ∩ (⊥ ‘B))) = ((⊥ ‘A) ∨ B))
 
Theoremchdmm4t 5441 DeMorgan's law for meet in a Hilbert lattice.
((ACBC ) → (⊥ ‘((⊥ ‘A) ∩ (⊥ ‘B))) = (A B))
 
Theoremchdmj1t 5442 DeMorgan's law for join in a Hilbert lattice.
((ACBC ) → (⊥ ‘(A B)) = ((⊥ ‘A) ∩ (⊥ ‘B)))
 
Theoremchdmj2t 5443 DeMorgan's law for join in a Hilbert lattice.
((ACBC ) → (⊥ ‘((⊥ ‘A) ∨ B)) = (A ∩ (⊥ ‘B)))
 
Theoremchdmj3t 5444 DeMorgan's law for join in a Hilbert lattice.
((ACBC ) → (⊥ ‘(A (⊥ ‘B))) = ((⊥ ‘A) ∩ B))
 
Theoremchdmj4t 5445 DeMorgan's law for join in a Hilbert lattice.
((ACBC ) → (⊥ ‘((⊥ ‘A) ∨ (⊥ ‘B))) = (AB))
 
Theoremchjasst 5446 Associative law for Hilbert lattice join. From definition of lattice in [Kalmbach] p. 14.
((ACBCCC ) → ((A B) ∨ C) = (A (B C)))
 
Theoremledi 5447 An ortholattice is distributive in one ordering direction.
AC    &   BC    &   CC    ⇒   ((AB) ∨ (AC)) ⊆ (A ∩ (B C))
 
Theoremspan0 5448 The span of the empty set is the zero subspace. Remark 11.6.e of [Schechter] p. 276.
(span ‘∅) = 0
 
Theoremelspan 5449 Membership in the span of a subset of Hilbert space.
BV    ⇒   (A ⊆ ℋ → (B ∈ (span ‘A) ↔ ∀xS (AxBx)))
 
Theoremspanun 5450 The span of a union is the subspace sum of spans.
A ⊆ ℋ    &   B ⊆ ℋ    ⇒   (span ‘(AB)) = ((span ‘A) + (span ‘B))
 
Theoremsshhococ 5451 The join of two Hilbert space subsets (not necessarily closed subspaces) equals the join of their closures (double orthocomplements).
A ⊆ ℋ    &   B ⊆ ℋ    ⇒   (A B) = ((⊥ ‘(⊥ ‘A)) ∨ (⊥ ‘(⊥ ‘B)))
 
Theoremchne0t 5452 A non-zero closed subspace has a non-zero vector.
(AC → (¬ A = 0 ↔ ∃xA ¬ x = 0v))
 
Theoremchsup0 5453 The supremum of the empty set.
( ‘∅) = 0
 
Theoremh1deot 5454 Membership in orthocomplement of 1-dimensional subspace.
B ∈ ℋ    ⇒   (A ∈ (⊥ ‘{B}) ↔ (A ∈ ℋ ∧ (A ·i B) = 0))
 
Theoremh1det 5455 Membership in 1-dimensional subspace.
B ∈ ℋ    ⇒   (A ∈ (⊥ ‘(⊥ ‘{B})) ↔ (A ∈ ℋ ∧ ∀x ∈ ℋ ((B ·i x) = 0 → (A ·i x) = 0)))
 
Theoremh1did 5456 A generating vector belongs to the 1-dimensional subspace it generates.
(A ∈ ℋ → A ∈ (⊥ ‘(⊥ ‘{A})))
 
Theoremh1dn0 5457 A non-zero vector generates a (non-zero) 1-dimensional subspace.
((A ∈ ℋ ∧ ¬ A = 0v) → ¬ (⊥ ‘(⊥ ‘{A})) = 0)
 
Theoremh1de2 5458 Membership in 1-dimensional subspace. All members are collinear with the generating vector.
A ∈ ℋ    &   B ∈ ℋ    ⇒   (A ∈ (⊥ ‘(⊥ ‘{B})) → ((B ·i B) ·s A) = ((A ·i B) ·s B))
 
Theoremh1de2b 5459 Membership in 1-dimensional subspace. All members are collinear with the generating vector.
A ∈ ℋ    &   B ∈ ℋ    ⇒   B = 0v → (A ∈ (⊥ ‘(⊥ ‘{B})) ↔ A = (((A ·i B) / (B ·i B)) ·s B)))
 
Theoremh1de2ctlem 5460 Lemma for h1de2ct 5461.
A ∈ ℋ    &   B ∈ ℋ    ⇒   (A ∈ (⊥ ‘(⊥ ‘{B})) ↔ ∃x ∈ ℂ A = (x ·s B))
 
Theoremh1de2ct 5461 Membership in 1-dimensional subspace. All members are collinear with the generating vector.
B ∈ ℋ    ⇒   (A ∈ (⊥ ‘(⊥ ‘{B})) ↔ ∃x ∈ ℂ A = (x ·s B))
 
Theoremspansn 5462 The span of a singleton in Hilbert space equals its closure.
A ∈ ℋ    ⇒   (span ‘{A}) = (⊥ ‘(⊥ ‘{A}))
 
Theoremelspansn 5463 Membership in the span of a singleton.
A ∈ ℋ    ⇒   (B ∈ (span ‘{A}) ↔ ∃x ∈ ℂ B = (x ·s A))
 
Theoremspansnt 5464 The span of a singleton in Hilbert space equals its closure.
(A ∈ ℋ → (span ‘{A}) = (⊥ ‘(⊥ ‘{A})))
 
Theoremspansncht 5465 The span of a Hilbert space singleton belongs to the Hilbert lattice.
(A ∈ ℋ → (span ‘{A}) ∈ C )
 
Theoremspansnsht 5466 The span of a Hilbert space singleton is a subspace.
(A ∈ ℋ → (span ‘{A}) ∈ S )
 
Theoremspansnch 5467 The span of a singleton in Hilbert space is a closed subspace.
A ∈ ℋ    ⇒   (span ‘{A}) ∈ C
 
Theoremspansnid 5468 A vector belongs to the span of its singleton.
(A ∈ ℋ → A ∈ (span ‘{A}))
 
Theoremspansnmul 5469 A scalar product with a vector belongs to the span of its singleton.
((A ∈ ℋ ∧ B ∈ ℂ) → (B ·s A) ∈ (span ‘{A}))
 
Theoremelspansnclt 5470 A member of a span of a singleton is a vector.
((A ∈ ℋ ∧ B ∈ (span ‘{A})) → B ∈ ℋ )
 
Theoremelspansnt 5471 Membership in the span of a singleton.
(A ∈ ℋ → (B ∈ (span ‘{A}) ↔ ∃x ∈ ℂ B = (x ·s A)))
 
Theoremelspansn2t 5472 Membership in the span of a singleton. All members are collinear with the generating vector.
((A ∈ ℋ ∧ B ∈ ℋ ∧ ¬ B = 0v) → (A ∈ (span ‘{B}) ↔ A = (((A ·i B) / (B ·i B)) ·s B)))
 
Theoremspansncol 5473 The singletons of collinear vectors have the same span.
((A ∈ ℋ ∧ B ∈ ℂ ∧ B ≠ 0) → (span ‘{(B ·s A)}) = (span ‘{A}))
 
Theoremspansneleqi 5474 Membership relation implied by equality of spans.
(A ∈ ℋ → ((span ‘{A}) = (span ‘{B}) → A ∈ (span ‘{B})))
 
Theoremspansneleq 5475 Membership relation that implies equality of spans.
((B ∈ ℋ ∧ ¬ A = 0v) → (A ∈ (span ‘{B}) → (span ‘{A}) = (span ‘{B})))
 
Theoremspansnsst 5476 The span of the singleton of an element of a subspace is included in the subspace.
((ASBA) → (span ‘{B}) ⊆ A)
 
Theoremelspansn3t 5477 A member of the span of the singleton of a vector is a member of a subspace containing the vector.
(AS → ((BAC ∈ (span ‘{B})) → CA))
 
Theoremelspansn4t 5478 A span membership condition implying two vectors belong to the same subspace.
(((ASB ∈ ℋ ) ∧ (C ∈ (span ‘{B}) ∧ ¬ C = 0v)) → (BACA))
 
Theoremelspansn5t 5479 A vector belonging to both a subspace and the span of the singleton of a vector not in it must be zero.
(AS → (((B ∈ ℋ ∧ ¬ BA) ∧ (C ∈ (span ‘{B}) ∧ CA)) → C = 0v))
 
Theoremspansnss2t 5480 The span of the singleton of an element of a subspace is included in the subspace.
((ASB ∈ ℋ ) → (BA ↔ (span ‘{B}) ⊆ A))
 
Theoremspansnpj 5481 A subset of Hilbert space is orthogonal to the span of the singleton of a projection onto its orthocomplement.
A ⊆ ℋ    &   B ∈ ℋ    ⇒   A ⊆ (⊥ ‘(span ‘{((Proj ‘(⊥ ‘A)) ‘B)}))
 
Theoremspanunsn 5482 The span of the union of a closed subspace with a singleton equals the span of its union with an orthogonal singleton.
AC    &   B ∈ ℋ    ⇒   (span ‘(A ∪ {B})) = (span ‘(A ∪ {((Proj ‘(⊥ ‘A)) ‘B)}))
 
Theoremh1datom 5483 A 1-dimensional subspace is an atom.
AC    &   B ∈ ℋ    ⇒   (A ⊆ (⊥ ‘(⊥ ‘{B})) → (A = (⊥ ‘(⊥ ‘{B})) ∨ A = 0))
 
Theoremh1datomt 5484 A 1-dimensional subspace is an atom.
((ACB ∈ ℋ ) → (A ⊆ (⊥ ‘(⊥ ‘{B})) → (A = (⊥ ‘(⊥ ‘{B})) ∨ A = 0)))
 
Definitiondf-hosum 5485 Define the sum of two Hilbert space operators. Definition of [Beran] p. 111.
+P = {⟨⟨f, g⟩, h⟩∣((f: ℋ –→ ℋ ∧ g: ℋ –→ ℋ ) ∧ h = {⟨x, y⟩∣(x ∈ ℋ ∧ y = ((fx) +v (gx)))})}
 
Definitiondf-pjdif 5486 Define the difference of two Hilbert space operators. Definition of [Beran] p. 111.
P = {⟨⟨f, g⟩, h⟩∣((f: ℋ –→ ℋ ∧ g: ℋ –→ ℋ ) ∧ h = {⟨x, y⟩∣(x ∈ ℋ ∧ y = ((fx) −v (gx)))})}
 
Theoremhosmvalt 5487 Value of sum of two Hilbert space operators.
((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) → (S +P T) = {⟨x, y⟩∣(x ∈ ℋ ∧ y = ((Sx) +v (Tx)))})
 
Theoremhodmvalt 5488 Value of difference of two Hilbert space operators.
((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) → (SP T) = {⟨x, y⟩∣(x ∈ ℋ ∧ y = ((Sx) −v (Tx)))})
 
Theoremhosvalt 5489 Value of sum of two Hilbert space operators.
(((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) ∧ A ∈ ℋ ) → ((S +P T) ‘A) = ((SA) +v (TA)))
 
Theoremhodvalt 5490 Value of difference of two Hilbert space operators.
(((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) ∧ A ∈ ℋ ) → ((SP T) ‘A) = ((SA) −v (TA)))
 
Theoremhosclt 5491 Closure of sum of two Hilbert space operators.
(((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) ∧ A ∈ ℋ ) → ((S +P T) ‘A) ∈ ℋ )
 
Theoremhodclt 5492 Closure of difference of two Hilbert space operators.
(((S: ℋ –→ ℋ ∧ T: ℋ –→ ℋ ) ∧ A ∈ ℋ ) → ((SP T) ‘A) ∈ ℋ )
 
Definitiondf-cm 5493 Define the commutes relation (on the Hilbert lattice). Definition of commutes in [Kalmbach] p. 20, who uses the notation xCy for "x commutes with y." See cmbr 5499 for membership relation.
Com = {⟨x, y⟩∣((xCyC ) ∧ x = ((xy) ∨ (x ∩ (⊥ ‘y))))}
 
Theoremcmbrt 5494 Binary relation expressing A commutes with B. Definition of commutes in [Kalmbach] p. 20.
((ACBC ) → (A Com BA = ((AB) ∨ (A ∩ (⊥ ‘B)))))
 
Theorempjoml2 5495 Variation of orthomodular law. Definition in [Kalmbach] p. 22.
AC    &   BC    ⇒   (AB → (A ((⊥ ‘A) ∩ B)) = B)
 
Theorempjoml3 5496 Variation of orthomodular law.
AC    &   BC    ⇒   (BA → (A ∩ ((⊥ ‘A) ∨ B)) = B)
 
Theorempjoml4 5497 Variation of orthomodular law.
AC    &   BC    ⇒   (A (B ∩ ((⊥ ‘A) ∨ (⊥ ‘B)))) = (A B)
 
Theorempjoml5 5498 An equivalent of the orthomodular law. Theorem 29.13(e) of [MaedaMaeda] p. 132.
AC    &   BC    ⇒   (AB → ∃xC (A ⊆ (⊥ ‘x) ∧ (A x) = B))
 
Theoremcmbr 5499 Binary relation expressing the commutes relation. Definition of commutes in [Kalmbach] p. 20.
AC    &   BC    ⇒   (A Com BA = ((AB) ∨ (A ∩ (⊥ ‘B))))
 
Theoremcmcmlem 5500 Commutation is symmetric. Theorem 3.4 of [Beran] p. 45.
AC    &   BC    ⇒   (A Com BB Com A)

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