HomeHome Metamath Proof Explorer < Previous   Next >
Bad symbols? Use Mozilla
(or GIF version for IE).

Jump to page: 1 1-100 2 101-200 3 201-300 4 301-400 5 401-500 6 501-600 7 601-700 8 701-800 9 801-900 10 901-1000 11 1001-1100 12 1101-1200 13 1201-1300 14 1301-1400 15 1401-1500 16 1501-1600 17 1601-1700 18 1701-1800 19 1801-1900 20 1901-2000 21 2001-2100 22 2101-2200 23 2201-2300 24 2301-2400 25 2401-2500 26 2501-2600 27 2601-2700 28 2701-2800 29 2801-2900 30 2901-3000 31 3001-3100 32 3101-3200 33 3201-3300 34 3301-3400 35 3401-3500 36 3501-3600 37 3601-3700 38 3701-3800 39 3801-3900 40 3901-4000 41 4001-4100 42 4101-4200 43 4201-4300 44 4301-4400 45 4401-4500 46 4501-4600 47 4601-4700 48 4701-4800 49 4801-4900 50 4901-5000 51 5001-5100 52 5101-5200 53 5201-5300 54 5301-5400 55 5401-5500 56 5501-5600 57 5601-5700 58 5701-5787

Color key:    Metamath Proof
Explorer  Metamath Proof Explorer (1-4957)   Hilbert Space Explorer  Hilbert Space Explorer (4958-5787)  

Statement List for Metamath Proof Explorer - 5501-5600 - Page 56 of 58
TypeLabelDescription
Statement
 
Theoremcmcm 5501 Commutation is symmetric. Theorem 2(v) of [Kalmbach] p. 22.
AC    &   BC    ⇒   (A Com BB Com A)
 
Theoremcmcm2 5502 Commutation with orthocomplement. Theorem 2.3(i) of [Beran] p. 39.
AC    &   BC    ⇒   (A Com BA Com (⊥ ‘B))
 
Theoremcmcm3 5503 Commutation with orthocomplement. Remark in [Kalmbach] p. 23.
AC    &   BC    ⇒   (A Com B ↔ (⊥ ‘A) Com B)
 
Theoremcmcm4 5504 Commutation with orthocomplement. Remark in [Kalmbach] p. 23.
AC    &   BC    ⇒   (A Com B ↔ (⊥ ‘A) Com (⊥ ‘B))
 
Theoremcmbr2 5505 Alternate definition of the commutes relation. Remark in [Kalmbach] p. 23.
AC    &   BC    ⇒   (A Com BA = ((A B) ∩ (A (⊥ ‘B))))
 
Theoremcmcmi 5506 Commutation is symmetric. Theorem 2(v) of [Kalmbach] p. 22.
AC    &   BC    &   A Com B    ⇒   B Com A
 
Theoremcmcm2i 5507 Commutation with orthocomplement. Theorem 2.3(i) of [Beran] p. 39.
AC    &   BC    &   A Com B    ⇒   A Com (⊥ ‘B)
 
Theoremcmcm3i 5508 Commutation with orthocomplement. Remark of [Kalmbach] p. 23.
AC    &   BC    &   A Com B    ⇒   (⊥ ‘A) Com B
 
Theoremcmbr3 5509 Alternate definition for the commutes relation. Lemma 3 of [Kalmbach] p. 23.
AC    &   BC    ⇒   (A Com B ↔ (A ∩ ((⊥ ‘A) ∨ B)) = (AB))
 
Theoremcmbr4 5510 Alternate definition for the commutes relation.
AC    &   BC    ⇒   (A Com B ↔ (A ∩ ((⊥ ‘A) ∨ B)) ⊆ B)
 
Theoremcmle 5511 Comparable Hilbert lattice elements commute. Theorem 2.3(iii) of [Beran] p. 40.
AC    &   BC    &   AB    ⇒   A Com B
 
Theoremcmj1 5512 A Hilbert lattice element commutes with its join.
AC    &   BC    ⇒   A Com (A B)
 
Theoremcmj2 5513 A Hilbert lattice element commutes with its join.
AC    &   BC    ⇒   B Com (A B)
 
Theoremcmm1 5514 A Hilbert lattice element commutes with its meet.
AC    &   BC    ⇒   A Com (AB)
 
Theoremcmm2 5515 A Hilbert lattice element commutes with its meet.
AC    &   BC    ⇒   B Com (AB)
 
Theoremcmid 5516 The commutes relation is reflexive.
AC    ⇒   A Com A
 
Theorempjoml3t 5517 Variation of orthomodular law.
((ACBC ) → (BA → (A ∩ ((⊥ ‘A) ∨ B)) = B))
 
Theoremfh1 5518 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. First of two parts. Theorem 5 of [Kalmbach] p. 25.
AC    &   BC    &   CC    &   A Com B    &   A Com C    ⇒   (A ∩ (B C)) = ((AB) ∨ (AC))
 
Theoremfh2 5519 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. Second of two parts. Theorem 5 of [Kalmbach] p. 25.
AC    &   BC    &   CC    &   A Com B    &   A Com C    ⇒   (B ∩ (A C)) = ((BA) ∨ (BC))
 
Theoremqlax1 5520 One of the equations showing C is an ortholattice. (This corresponds to axiom "ax-1" in the Quantum Logic Explorer.)
AC    ⇒   A = (⊥ ‘(⊥ ‘A))
 
Theoremqlax2 5521 One of the equations showing C is an ortholattice. (This corresponds to axiom "ax-2" in the Quantum Logic Explorer.)
AC    &   BC    ⇒   (A B) = (B A)
 
Theoremqlax3 5522 One of the equations showing C is an ortholattice. (This corresponds to axiom "ax-3" in the Quantum Logic Explorer.)
AC    &   BC    &   CC    ⇒   ((A B) ∨ C) = (A (B C))
 
Theoremqlax4 5523 One of the equations showing C is an ortholattice. (This corresponds to axiom "ax-4" in the Quantum Logic Explorer.)
AC    &   BC    ⇒   (A (B (⊥ ‘B))) = (B (⊥ ‘B))
 
Theoremqlax5 5524 One of the equations showing C is an ortholattice. (This corresponds to axiom "ax-5" in the Quantum Logic Explorer.)
AC    &   BC    ⇒   (A (⊥ ‘((⊥ ‘A) ∨ B))) = A
 
Theoremqlaxr1 5525 One of the conditions showing C is an ortholattice. (This corresponds to axiom "ax-r1" in the Quantum Logic Explorer.)
AC    &   BC    &   A = B    ⇒   B = A
 
Theoremqlaxr2 5526 One of the conditions showing C is an ortholattice. (This corresponds to axiom "ax-r2" in the Quantum Logic Explorer.)
AC    &   BC    &   CC    &   A = B    &   B = C    ⇒   A = C
 
Theoremqlaxr4 5527 One of the conditions showing C is an ortholattice. (This corresponds to axiom "ax-r4" in the Quantum Logic Explorer.)
AC    &   BC    &   A = B    ⇒   (⊥ ‘A) = (⊥ ‘B)
 
Theoremqlaxr5 5528 One of the conditions showing C is an ortholattice. (This corresponds to axiom "ax-r5" in the Quantum Logic Explorer.)
AC    &   BC    &   CC    &   A = B    ⇒   (A C) = (B C)
 
Theoremqlaxr3 5529 A variation of the orthomodular law, showing C is an orthomodular lattice. (This corresponds to axiom "ax-r3" in the Quantum Logic Explorer.)
AC    &   BC    &   CC    &   (C (⊥ ‘C)) = ((⊥ ‘((⊥ ‘A) ∨ (⊥ ‘B))) ∨ (⊥ ‘(A B)))    ⇒   A = B
 
Theoremosumlem1 5530 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    &   (φ ↔ (((CADB) ∧ R = (C +v D)) ∧ ((xAy ∈ (⊥ ‘A)) ∧ z = (x +v y))))    ⇒   (φ → (((C ∈ ℋ ∧ D ∈ ℋ ) ∧ R ∈ ℋ ) ∧ ((x ∈ ℋ ∧ y ∈ ℋ ) ∧ z ∈ ℋ )))
 
Theoremosumlem2 5531 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    &   (φ ↔ (((CADB) ∧ R = (C +v D)) ∧ ((xAy ∈ (⊥ ‘A)) ∧ z = (x +v y))))    ⇒   (φ → (((norm ‘(Cv x))↑2) + ((norm ‘(Dv y))↑2)) = ((norm ‘(Rv z))↑2))
 
Theoremosumlem3 5532 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    &   (φ ↔ (((CADB) ∧ R = (C +v D)) ∧ ((xAy ∈ (⊥ ‘A)) ∧ z = (x +v y))))    ⇒   (φ → (norm ‘(Dv y)) ≤ (norm ‘(Rv z)))
 
Theoremosumlem4 5533 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    &   GV    &   HV    ⇒   ((((F:ℕ–→AG:ℕ–→B) ∧ ∀w ∈ ℕ (Hw) = ((Fw) +v (Gw))) ∧ ((xAy ∈ (⊥ ‘A)) ∧ z = (x +v y))) → (Hv zGv y))
 
Theoremosumlem5 5534 Lemma for osum 5538.
AC    &   BC    ⇒   (H:ℕ–→(A + B) → ∃fg((f:ℕ–→Ag:ℕ–→B) ∧ ∀w ∈ ℕ (Hw) = ((fw) +v (gw))))
 
Theoremosumlem6 5535 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    &   HV    ⇒   (((H:ℕ–→(A + B) ∧ Hv z) ∧ ((xAy ∈ (⊥ ‘A)) ∧ z = (x +v y))) → yB)
 
Theoremosumlem7 5536 Lemma for osum 5538.
AC    &   BC    &   B ⊆ (⊥ ‘A)    ⇒   (A + B) ∈ C
 
Theoremosumlem8 5537 Lemma for osum 5538.
AC    &   BC    ⇒   (B ⊆ (⊥ ‘A) → (A + B) ∈ C )
 
Theoremosum 5538 If two closed subspaces of a Hilbert space are orthogonal, their subspace sum equals their subspace join. Lemma 3 of [Kalmbach] p. 67. Note that the Axiom of Choice is used for this proof (in osumlem5 5534 and via pjpjtht 5262 in osumlem7 5536).
AC    &   BC    ⇒   (A ⊆ (⊥ ‘B) → (A + B) = (A B))
 
Theoremspansnj 5539 The subspace sum of a closed subspace and a one-dimensional subspace equals their join. (Proof suggested by Eric Schechter 1-Jun-04.)
AC    &   B ∈ ℋ    ⇒   (A + (span ‘{B})) = (A (span ‘{B}))
 
Theoremspansnjt 5540 The subspace sum of a closed subspace and a one-dimensional subspace equals their join.
((ACB ∈ ℋ ) → (A + (span ‘{B})) = (A (span ‘{B})))
 
Theoremspansnsclt 5541 The subspace sum of a closed subspace and a one-dimensional subspace is closed.
((ACB ∈ ℋ ) → (A + (span ‘{B})) ∈ C )
 
Theoremspansncv 5542 Hilbert space has the covering property (using spans of singletons to represent atoms). Exercise 5 of [Kalmbach] p. 153.
AC    &   BC    &   C ∈ ℋ    ⇒   ((ABB ⊆ (A (span ‘{C}))) → B = (A (span ‘{C})))
 
Theoremspansncvt 5543 Hilbert space has the covering property (using spans of singletons to represent atoms). Exercise 5 of [Kalmbach] p. 153.
((ACBCC ∈ ℋ ) → ((ABB ⊆ (A (span ‘{C}))) → B = (A (span ‘{C}))))
 
Theorem5oalem1 5544 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   RS    ⇒   ((((xAyB) ∧ v = (x +v y)) ∧ (zC ∧ (xv z) ∈ R)) → v ∈ (B + (A ∩ (C + R))))
 
Theorem5oalem2 5545 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    ⇒   ((((xAyB) ∧ (zCwD)) ∧ (x +v y) = (z +v w)) → (xv z) ∈ ((A + C) ∩ (B + D)))
 
Theorem5oalem3 5546 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    &   FS    &   GS    ⇒   (((((xAyB) ∧ (zCwD)) ∧ (fFgG)) ∧ ((x +v y) = (f +v g) ∧ (z +v w) = (f +v g))) → (xv z) ∈ (((A + F) ∩ (B + G)) + ((C + F) ∩ (D + G))))
 
Theorem5oalem4 5547 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    &   FS    &   GS    ⇒   (((((xAyB) ∧ (zCwD)) ∧ (fFgG)) ∧ ((x +v y) = (f +v g) ∧ (z +v w) = (f +v g))) → (xv z) ∈ (((A + C) ∩ (B + D)) ∩ (((A + F) ∩ (B + G)) + ((C + F) ∩ (D + G)))))
 
Theorem5oalem5 5548 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    &   FS    &   GS    &   RS    &   SS    ⇒   (((((xAyB) ∧ (zCwD)) ∧ ((fFgG) ∧ (vRuS))) ∧ (((x +v y) = (v +v u) ∧ (z +v w) = (v +v u)) ∧ (f +v g) = (v +v u))) → (xv z) ∈ ((((A + C) ∩ (B + D)) ∩ (((A + R) ∩ (B + S)) + ((C + R) ∩ (D + S)))) ∩ ((((A + F) ∩ (B + G)) ∩ (((A + R) ∩ (B + S)) + ((F + R) ∩ (G + S)))) + (((C + F) ∩ (D + G)) ∩ (((C + R) ∩ (D + S)) + ((F + R) ∩ (G + S)))))))
 
Theorem5oalem6 5549 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    &   FS    &   GS    &   RS    &   SS    ⇒   (((((xAyB) ∧ h = (x +v y)) ∧ ((zCwD) ∧ h = (z +v w))) ∧ (((fFgG) ∧ h = (f +v g)) ∧ ((vRuS) ∧ h = (v +v u)))) → h ∈ (B + (A ∩ (C + ((((A + C) ∩ (B + D)) ∩ (((A + R) ∩ (B + S)) + ((C + R) ∩ (D + S)))) ∩ ((((A + F) ∩ (B + G)) ∩ (((A + R) ∩ (B + S)) + ((F + R) ∩ (G + S)))) + (((C + F) ∩ (D + G)) ∩ (((C + R) ∩ (D + S)) + ((F + R) ∩ (G + S))))))))))
 
Theorem5oalem7 5550 Lemma for orthoarguesian law 5OA.
AS    &   BS    &   CS    &   DS    &   FS    &   GS    &   RS    &   SS    ⇒   (((A + B) ∩ (C + D)) ∩ ((F + G) ∩ (R + S))) ⊆ (B + (A ∩ (C + ((((A + C) ∩ (B + D)) ∩ (((A + R) ∩ (B + S)) + ((C + R) ∩ (D + S)))) ∩ ((((A + F) ∩ (B + G)) ∩ (((A + R) ∩ (B + S)) + ((F + R) ∩ (G + S)))) + (((C + F) ∩ (D + G)) ∩ (((C + R) ∩ (D + S)) + ((F + R) ∩ (G + S)))))))))
 
Theorem5oa 5551 Orthoarguesian law 5OA. This 8-variable inference is called 5OA because it can be converted to a 5-variable equation (see Quantum Logic Explorer).
AC    &   BC    &   CC    &   DC    &   FC    &   GC    &   RC    &   SC    &   A ⊆ (⊥ ‘B)    &   C ⊆ (⊥ ‘D)    &   F ⊆ (⊥ ‘G)    &   R ⊆ (⊥ ‘S)    ⇒   (((A B) ∩ (C D)) ∩ ((F G) ∩ (R S))) ⊆ (B (A ∩ (C ((((A C) ∩ (B D)) ∩ (((A R) ∩ (B S)) ∨ ((C R) ∩ (D S)))) ∩ ((((A F) ∩ (B G)) ∩ (((A R) ∩ (B S)) ∨ ((F R) ∩ (G S)))) ∨ (((C F) ∩ (D G)) ∩ (((C R) ∩ (D S)) ∨ ((F R) ∩ (G S)))))))))
 
Theorem3oalem1 5552 Lemma for 3OA (weak) orthoarguesian law.
BC    &   CC    &   RC    &   SC    ⇒   ((((xByR) ∧ v = (x +v y)) ∧ ((zCwS) ∧ v = (z +v w))) → (((x ∈ ℋ ∧ y ∈ ℋ ) ∧ v ∈ ℋ ) ∧ (z ∈ ℋ ∧ w ∈ ℋ )))
 
Theorem3oalem2 5553 Lemma for 3OA (weak) orthoarguesian law.
BC    &   CC    &   RC    &   SC    ⇒   ((((xByR) ∧ v = (x +v y)) ∧ ((zCwS) ∧ v = (z +v w))) → v ∈ (B + (R ∩ (S + ((B + C) ∩ (R + S))))))
 
Theorem3oalem3 5554 Lemma for 3OA (weak) orthoarguesian law.
BC    &   CC    &   RC    &   SC    ⇒   ((B + R) ∩ (C + S)) ⊆ (B + (R ∩ (S + ((B + C) ∩ (R + S)))))
 
Theorem3oalem4 5555 Lemma for 3OA (weak) orthoarguesian law.
R = ((⊥ ‘B) ∩ (B A))    ⇒   R ⊆ (⊥ ‘B)
 
Theorem3oalem5 5556 Lemma for 3OA (weak) orthoarguesian law.
AC    &   BC    &   CC    &   R = ((⊥ ‘B) ∩ (B A))    &   S = ((⊥ ‘C) ∩ (C A))    ⇒   ((B + R) ∩ (C + S)) = ((B R) ∩ (C S))
 
Theorem3oalem6 5557 Lemma for 3OA (weak) orthoarguesian law.
AC    &   BC    &   CC    &   R = ((⊥ ‘B) ∩ (B A))    &   S = ((⊥ ‘C) ∩ (C A))    ⇒   (B + (R ∩ (S + ((B + C) ∩ (R + S))))) ⊆ (B (R ∩ (S ((B C) ∩ (R S)))))
 
Theorem3oa 5558 3OA (weak) orthoarguesian law. Equation (IV) of [GodowskiGreechie] p. 249.
AC    &   BC    &   CC    &   R = ((⊥ ‘B) ∩ (B A))    &   S = ((⊥ ‘C) ∩ (C A))    ⇒   ((B R) ∩ (C S)) ⊆ (B (R ∩ (S ((B C) ∩ (R S)))))
 
Theorempjorth 5559 Projection components on orthocomplemented subspaces are orthogonal.
A ∈ ℋ    &   B ∈ ℋ    ⇒   (HC → (((Proj ‘H) ‘A) ·i ((Proj ‘(⊥ ‘H)) ‘B)) = 0)
 
Theorempjch1t 5560 Property of identity projection. Remark of [Beran] p. 111.
(A ∈ ℋ → ((Proj ‘ ℋ ) ‘A) = A)
 
Theorempjot 5561 The orthogonal projection. Lemma 4.4(i) of [Beran] p. 111.
((HCA ∈ ℋ ) → ((Proj ‘(⊥ ‘H)) ‘A) = (((Proj ‘ ℋ ) ‘A) −v ((Proj ‘H) ‘A)))
 
Theorempjch0t 5562 Property of the null projection. Remark of [Beran] p. 111.
(A ∈ ℋ → ((Proj ‘0) ‘A) = 0v)
 
Theorempjidm 5563 A projection is idempotent. Property (ii) of [Beran] p. 109.
HC    &   A ∈ ℋ    ⇒   ((Proj ‘H) ‘((Proj ‘H) ‘A)) = ((Proj ‘H) ‘A)
 
Theorempjadj 5564 A projection is self-adjoint. Property (i) of [Beran] p. 109.
HC    &   A ∈ ℋ    &   B ∈ ℋ    ⇒   (((Proj ‘H) ‘A) ·i B) = (A ·i ((Proj ‘H) ‘B))
 
Theorempjcomp 5565 Component of a projection.
HC    &   A ∈ ℋ    &   B ∈ ℋ    ⇒   ((AHB ∈ (⊥ ‘H)) → ((Proj ‘H) ‘(A +v B)) = A)
 
Theorempjadd 5566 Projection of vector sum is sum of projections.
HC    &   A ∈ ℋ    &   B ∈ ℋ    ⇒   ((Proj ‘H) ‘(A +v B)) = (((Proj ‘H) ‘A) +v ((Proj ‘H) ‘B))
 
Theorempjinorm 5567 The inner product of a projection and its argument is the square of the norm of the projection.
HC    &   A ∈ ℋ    ⇒   (((Proj ‘H) ‘A) ·i A) = ((norm ‘((Proj ‘H) ‘A))↑2)
 
Theorempjmul 5568 Projection of (scalar) product is product of projection.
HC    &   A ∈ ℋ    &   C ∈ ℂ    ⇒   ((Proj ‘H) ‘(C ·s A)) = (C ·s ((Proj ‘H) ‘A))
 
Theorempjsub 5569 Projection of vector difference is difference of projections.
HC    &   A ∈ ℋ    &   B ∈ ℋ    ⇒   ((Proj ‘H) ‘(Av B)) = (((Proj ‘H) ‘A) −v ((Proj ‘H) ‘B))
 
Theorempjsslem 5570 Lemma for subset relationships of projections.
HC    &   A ∈ ℋ    &   GC    ⇒   (((Proj ‘(⊥ ‘H)) ‘A) −v ((Proj ‘(⊥ ‘G)) ‘A)) = (((Proj ‘G) ‘A) −v ((Proj ‘H) ‘A))
 
Theorempjss2 5571 Subset relationship for projections. Theorem 4.5(i)->(ii) of [Beran] p. 112.
HC    &   A ∈ ℋ    &   GC    ⇒   (HG → ((Proj ‘H) ‘((Proj ‘G) ‘A)) = ((Proj ‘H) ‘A))
 
Theorempjssm 5572 Projection meet property. Remark of [Kalmbach] p. 66. Also Theorem 4.5(i)->(iv) of [Beran] p. 112.
HC    &   A ∈ ℋ    &   GC    ⇒   (HG → (((Proj ‘G) ‘A) −v ((Proj ‘H) ‘A)) = ((Proj ‘(G ∩ (⊥ ‘H))) ‘A))
 
Theorempjssge0 5573 Theorem 4.5(iv)->(v) of [Beran] p. 112.
HC    &   A ∈ ℋ    &   GC    ⇒   ((((Proj ‘G) ‘A) −v ((Proj ‘H) ‘A)) = ((Proj ‘(G ∩ (⊥ ‘H))) ‘A) → 0 ≤ ((((Proj ‘G) ‘A) −v ((Proj ‘H) ‘A)) ·i A))
 
Theorempjdifnorm 5574 Theorem 4.5(v)<->(vi) of [Beran] p. 112.
HC    &   A ∈ ℋ    &   GC    ⇒   (0 ≤ ((((Proj ‘G) ‘A) −v ((Proj ‘H) ‘A)) ·i A) ↔ (norm ‘((Proj ‘H) ‘A)) ≤ (norm ‘((Proj ‘G) ‘A)))
 
Theorempjcj 5575 The projection on a subspace join is the sum of the projections.
HC    &   A ∈ ℋ    &   GC    ⇒   (H ⊆ (⊥ ‘G) → ((Proj ‘(H G)) ‘A) = (((Proj ‘H) ‘A) +v ((Proj ‘G) ‘A)))
 
Theorempjadjt 5576 A projection is self-adjoint. Property (i) of [Beran] p. 109.
HC    ⇒   ((A ∈ ℋ ∧ B ∈ ℋ ) → (((Proj ‘H) ‘A) ·i B) = (A ·i ((Proj ‘H) ‘B)))
 
Theorempjaddt 5577 Projection of vector sum is sum of projections.
HC    ⇒   ((A ∈ ℋ ∧ B ∈ ℋ ) → ((Proj ‘H) ‘(A +v B)) = (((Proj ‘H) ‘A) +v ((Proj ‘H) ‘B)))
 
Theorempjsubt 5578 Projection of vector difference is difference of projections.
HC    ⇒   ((A ∈ ℋ ∧ B ∈ ℋ ) → ((Proj ‘H) ‘(Av B)) = (((Proj ‘H) ‘A) −v ((Proj ‘H) ‘B)))
 
Theorempjmult 5579 Projection of scalar product is scalar product of projection.
HC    ⇒   ((A ∈ ℂ ∧ B ∈ ℋ ) → ((Proj ‘H) ‘(A ·s B)) = (A ·s ((Proj ‘H) ‘B)))
 
Theorempjcjt2 5580 The projection on a subspace join is the sum of the projections.
((HCGCA ∈ ℋ ) → (H ⊆ (⊥ ‘G) → ((Proj ‘(H G)) ‘A) = (((Proj ‘H) ‘A) +v ((Proj ‘G) ‘A))))
 
Theorempj0 5581 The projection of the zero vector.
HC<