HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem moabex 1868
Description: "At most one" existence implies a class abstraction exists.
Assertion
Ref Expression
moabex (∃*xφ → {xφ} ∈ V)

Proof of Theorem moabex
StepHypRef Expression
1 ax-17 925 . . 3 (φ → ∀yφ)
21mo2 1026 . 2 (∃*xφ ↔ ∃yx(φx = y))
3 df-sn 1811 . . . . . 6 {y} = {xx = y}
4 snex 1859 . . . . . 6 {y} ∈ V
53, 4eqeltrr 1160 . . . . 5 {xx = y} ∈ V
6 pm3.26 256 . . . . . 6 ((x = yφ) → x = y)
76ss2abi 1552 . . . . 5 {x∣(x = yφ)} ⊆ {xx = y}
85, 7ssexi 1701 . . . 4 {x∣(x = yφ)} ∈ V
9 hba1 698 . . . . . 6 (∀x(φx = y) → ∀xx(φx = y))
10 pm4.71 481 . . . . . . . . 9 ((φx = y) ↔ (φ ↔ (φx = y)))
1110biimp 133 . . . . . . . 8 ((φx = y) → (φ ↔ (φx = y)))
1211a4s 682 . . . . . . 7 (∀x(φx = y) → (φ ↔ (φx = y)))
13 ancom 333 . . . . . . 7 ((φx = y) ↔ (x = yφ))
1412, 13syl6bb 414 . . . . . 6 (∀x(φx = y) → (φ ↔ (x = yφ)))
159, 14biabd 1182 . . . . 5 (∀x(φx = y) → {xφ} = {x∣(x = yφ)})
1615eleq1d 1155 . . . 4 (∀x(φx = y) → ({xφ} ∈ V ↔ {x∣(x = yφ)} ∈ V))
178, 16mpbiri 169 . . 3 (∀x(φx = y) → {xφ} ∈ V)
181719.23aiv 952 . 2 (∃yx(φx = y) → {xφ} ∈ V)
192, 18sylbi 174 1 (∃*xφ → {xφ} ∈ V)
Colors of variables: wff set class
Syntax hints:   → wi 2   ↔ wb 127   ∧ wa 196  ∀wal 672  ∃wex 678   = weq 797  ∃*wmo 1008  {cab 1090   ∈ wcel 1092  Vcvv 1348  {csn 1808
This theorem is referenced by:  euabex 1869  supex 2157  fvex 2838
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-eu 1009  df-mo 1010  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811
metamath.org