Proof of Theorem moabex
| Step | Hyp | Ref
| Expression |
| 1 | | ax-17 925 |
. . 3
⊢ (φ
→ ∀yφ) |
| 2 | 1 | mo2 1026 |
. 2
⊢ (∃*xφ ↔
∃y∀x(φ →
x = y)) |
| 3 | | df-sn 1811 |
. . . . . 6
⊢ {y} =
{x∣x = y} |
| 4 | | snex 1859 |
. . . . . 6
⊢ {y}
∈ V |
| 5 | 3, 4 | eqeltrr 1160 |
. . . . 5
⊢ {x∣x =
y} ∈ V |
| 6 | | pm3.26 256 |
. . . . . 6
⊢ ((x =
y ∧ φ) → x = y) |
| 7 | 6 | ss2abi 1552 |
. . . . 5
⊢ {x∣(x =
y ∧ φ)} ⊆ {x∣x =
y} |
| 8 | 5, 7 | ssexi 1701 |
. . . 4
⊢ {x∣(x =
y ∧ φ)} ∈ V |
| 9 | | hba1 698 |
. . . . . 6
⊢ (∀x(φ →
x = y)
→ ∀x∀x(φ →
x = y)) |
| 10 | | pm4.71 481 |
. . . . . . . . 9
⊢ ((φ → x = y) ↔
(φ ↔ (φ ∧ x
= y))) |
| 11 | 10 | biimp 133 |
. . . . . . . 8
⊢ ((φ → x = y) →
(φ ↔ (φ ∧ x
= y))) |
| 12 | 11 | a4s 682 |
. . . . . . 7
⊢ (∀x(φ →
x = y)
→ (φ ↔ (φ ∧ x
= y))) |
| 13 | | ancom 333 |
. . . . . . 7
⊢ ((φ ∧ x
= y) ↔ (x = y ∧
φ)) |
| 14 | 12, 13 | syl6bb 414 |
. . . . . 6
⊢ (∀x(φ →
x = y)
→ (φ ↔ (x = y ∧
φ))) |
| 15 | 9, 14 | biabd 1182 |
. . . . 5
⊢ (∀x(φ →
x = y)
→ {x∣φ} = {x∣(x =
y ∧ φ)}) |
| 16 | 15 | eleq1d 1155 |
. . . 4
⊢ (∀x(φ →
x = y)
→ ({x∣φ} ∈ V ↔ {x∣(x =
y ∧ φ)} ∈ V)) |
| 17 | 8, 16 | mpbiri 169 |
. . 3
⊢ (∀x(φ →
x = y)
→ {x∣φ} ∈ V) |
| 18 | 17 | 19.23aiv 952 |
. 2
⊢ (∃y∀x(φ → x = y) →
{x∣φ} ∈ V) |
| 19 | 2, 18 | sylbi 174 |
1
⊢ (∃*xφ →
{x∣φ} ∈ V) |