Proof of Theorem mulcan
| Step | Hyp | Ref
| Expression |
| 1 | | mulcan.1 |
. . . 4
⊢ A
∈ ℂ |
| 2 | | mulcan.4 |
. . . 4
⊢ A ≠
0 |
| 3 | 1, 2 | recex 4117 |
. . 3
⊢ ∃x ∈ ℂ (A · x) =
1 |
| 4 | | mulcan.2 |
. . . . . . . . . . 11
⊢ B
∈ ℂ |
| 5 | | axmulass 4073 |
. . . . . . . . . . 11
⊢ ((x
∈ ℂ ∧ A ∈ ℂ ∧
B ∈ ℂ) → ((x · A)
· B) = (x · (A
· B))) |
| 6 | 4, 5 | mp3an3 641 |
. . . . . . . . . 10
⊢ ((x
∈ ℂ ∧ A ∈ ℂ)
→ ((x · A) · B) =
(x · (A · B))) |
| 7 | | mulcan.3 |
. . . . . . . . . . 11
⊢ C
∈ ℂ |
| 8 | | axmulass 4073 |
. . . . . . . . . . 11
⊢ ((x
∈ ℂ ∧ A ∈ ℂ ∧
C ∈ ℂ) → ((x · A)
· C) = (x · (A
· C))) |
| 9 | 7, 8 | mp3an3 641 |
. . . . . . . . . 10
⊢ ((x
∈ ℂ ∧ A ∈ ℂ)
→ ((x · A) · C) =
(x · (A · C))) |
| 10 | 6, 9 | cleq12d 1115 |
. . . . . . . . 9
⊢ ((x
∈ ℂ ∧ A ∈ ℂ)
→ (((x · A) · B) =
((x · A) · C)
↔ (x · (A · B)) =
(x · (A · C)))) |
| 11 | 1, 10 | mpan2 519 |
. . . . . . . 8
⊢ (x
∈ ℂ → (((x ·
A) · B) = ((x
· A) · C) ↔ (x
· (A · B)) = (x
· (A · C)))) |
| 12 | | opreq2 3007 |
. . . . . . . 8
⊢ ((A
· B) = (A · C)
→ (x · (A · B)) =
(x · (A · C))) |
| 13 | 11, 12 | syl5bir 184 |
. . . . . . 7
⊢ (x
∈ ℂ → ((A · B) = (A ·
C) → ((x · A)
· B) = ((x · A)
· C))) |
| 14 | 13 | adantr 306 |
. . . . . 6
⊢ ((x
∈ ℂ ∧ (A · x) = 1) → ((A · B) =
(A · C) → ((x
· A) · B) = ((x
· A) · C))) |
| 15 | | axmulcom 4071 |
. . . . . . . . . 10
⊢ ((A
∈ ℂ ∧ x ∈ ℂ)
→ (A · x) = (x ·
A)) |
| 16 | 1, 15 | mpan 518 |
. . . . . . . . 9
⊢ (x
∈ ℂ → (A · x) = (x ·
A)) |
| 17 | 16 | cleq1d 1109 |
. . . . . . . 8
⊢ (x
∈ ℂ → ((A · x) = 1 ↔ (x
· A) = 1)) |
| 18 | | opreq1 3006 |
. . . . . . . . . 10
⊢ ((x
· A) = 1 → ((x · A)
· B) = (1 · B)) |
| 19 | 4 | mulid2 4115 |
. . . . . . . . . 10
⊢ (1 · B) = B |
| 20 | 18, 19 | syl6eq 1140 |
. . . . . . . . 9
⊢ ((x
· A) = 1 → ((x · A)
· B) = B) |
| 21 | | opreq1 3006 |
. . . . . . . . . 10
⊢ ((x
· A) = 1 → ((x · A)
· C) = (1 · C)) |
| 22 | 7 | mulid2 4115 |
. . . . . . . . . 10
⊢ (1 · C) = C |
| 23 | 21, 22 | syl6eq 1140 |
. . . . . . . . 9
⊢ ((x
· A) = 1 → ((x · A)
· C) = C) |
| 24 | 20, 23 | cleq12d 1115 |
. . . . . . . 8
⊢ ((x
· A) = 1 → (((x · A)
· B) = ((x · A)
· C) ↔ B = C)) |
| 25 | 17, 24 | syl6bi 187 |
. . . . . . 7
⊢ (x
∈ ℂ → ((A · x) = 1 → (((x · A)
· B) = ((x · A)
· C) ↔ B = C))) |
| 26 | 25 | imp 277 |
. . . . . 6
⊢ ((x
∈ ℂ ∧ (A · x) = 1) → (((x · A)
· B) = ((x · A)
· C) ↔ B = C)) |
| 27 | 14, 26 | sylibd 177 |
. . . . 5
⊢ ((x
∈ ℂ ∧ (A · x) = 1) → ((A · B) =
(A · C) → B =
C)) |
| 28 | 27 | exp 291 |
. . . 4
⊢ (x
∈ ℂ → ((A · x) = 1 → ((A · B) =
(A · C) → B =
C))) |
| 29 | 28 | r19.23aiv 1284 |
. . 3
⊢ (∃x ∈ ℂ (A · x) =
1 → ((A · B) = (A ·
C) → B = C)) |
| 30 | 3, 29 | ax-mp 6 |
. 2
⊢ ((A
· B) = (A · C)
→ B = C) |
| 31 | | opreq2 3007 |
. 2
⊢ (B =
C → (A · B) =
(A · C)) |
| 32 | 30, 31 | impbi 139 |
1
⊢ ((A
· B) = (A · C)
↔ B = C) |