Proof of Theorem mulcant
| Step | Hyp | Ref
| Expression |
| 1 | | opreq1 3006 |
. . . 4
⊢ (A =
if(A ∈ ℂ, A, 1) → (A
· B) = (if(A ∈ ℂ, A, 1) · B)) |
| 2 | | opreq1 3006 |
. . . 4
⊢ (A =
if(A ∈ ℂ, A, 1) → (A
· C) = (if(A ∈ ℂ, A, 1) · C)) |
| 3 | 1, 2 | cleq12d 1115 |
. . 3
⊢ (A =
if(A ∈ ℂ, A, 1) → ((A
· B) = (A · C)
↔ (if(A ∈ ℂ, A, 1) · B) = (if(A
∈ ℂ, A, 1) · C))) |
| 4 | 3 | bibi1d 471 |
. 2
⊢ (A =
if(A ∈ ℂ, A, 1) → (((A · B) =
(A · C) ↔ B =
C) ↔ ((if(A ∈ ℂ, A, 1) · B) = (if(A
∈ ℂ, A, 1) · C) ↔ B =
C))) |
| 5 | | opreq2 3007 |
. . . 4
⊢ (B =
if(B ∈ ℂ, B, 1) → (if(A ∈ ℂ, A, 1) · B) = (if(A
∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1))) |
| 6 | 5 | cleq1d 1109 |
. . 3
⊢ (B =
if(B ∈ ℂ, B, 1) → ((if(A ∈ ℂ, A, 1) · B) = (if(A
∈ ℂ, A, 1) · C) ↔ (if(A
∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · C))) |
| 7 | | cleq1 1107 |
. . 3
⊢ (B =
if(B ∈ ℂ, B, 1) → (B
= C ↔ if(B ∈ ℂ, B, 1) = C)) |
| 8 | 6, 7 | bibi12d 477 |
. 2
⊢ (B =
if(B ∈ ℂ, B, 1) → (((if(A ∈ ℂ, A, 1) · B) = (if(A
∈ ℂ, A, 1) · C) ↔ B =
C) ↔ ((if(A ∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · C) ↔ if(B
∈ ℂ, B, 1) = C))) |
| 9 | | opreq2 3007 |
. . . 4
⊢ (C =
if(C ∈ ℂ, C, 1) → (if(A ∈ ℂ, A, 1) · C) = (if(A
∈ ℂ, A, 1) · if(C ∈ ℂ, C, 1))) |
| 10 | 9 | cleq2d 1112 |
. . 3
⊢ (C =
if(C ∈ ℂ, C, 1) → ((if(A ∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · C) ↔ (if(A
∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · if(C ∈ ℂ, C, 1)))) |
| 11 | | cleq2 1110 |
. . 3
⊢ (C =
if(C ∈ ℂ, C, 1) → (if(B ∈ ℂ, B, 1) = C ↔
if(B ∈ ℂ, B, 1) = if(C
∈ ℂ, C, 1))) |
| 12 | 10, 11 | bibi12d 477 |
. 2
⊢ (C =
if(C ∈ ℂ, C, 1) → (((if(A ∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · C) ↔ if(B
∈ ℂ, B, 1) = C) ↔ ((if(A
∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · if(C ∈ ℂ, C, 1)) ↔ if(B ∈ ℂ, B, 1) = if(C
∈ ℂ, C, 1)))) |
| 13 | | 1cn 4101 |
. . . 4
⊢ 1 ∈ ℂ |
| 14 | 13 | elimel 1793 |
. . 3
⊢ if(A
∈ ℂ, A, 1) ∈
ℂ |
| 15 | 13 | elimel 1793 |
. . 3
⊢ if(B
∈ ℂ, B, 1) ∈
ℂ |
| 16 | 13 | elimel 1793 |
. . 3
⊢ if(C
∈ ℂ, C, 1) ∈
ℂ |
| 17 | | neeq1 1194 |
. . . 4
⊢ (A =
if(A ∈ ℂ, A, 1) → (A
≠ 0 ↔ if(A ∈ ℂ, A, 1) ≠ 0)) |
| 18 | | neeq1 1194 |
. . . 4
⊢ (1 = if(A ∈ ℂ, A, 1) → (1 ≠ 0 ↔ if(A ∈ ℂ, A, 1) ≠ 0)) |
| 19 | | mulcant.1 |
. . . 4
⊢ A ≠
0 |
| 20 | | ax1ne0 4075 |
. . . 4
⊢ 1 ≠ 0 |
| 21 | 17, 18, 19, 20 | keephyp 1794 |
. . 3
⊢ if(A
∈ ℂ, A, 1) ≠ 0 |
| 22 | 14, 15, 16, 21 | mulcan 4207 |
. 2
⊢ ((if(A
∈ ℂ, A, 1) · if(B ∈ ℂ, B, 1)) = (if(A
∈ ℂ, A, 1) · if(C ∈ ℂ, C, 1)) ↔ if(B ∈ ℂ, B, 1) = if(C
∈ ℂ, C, 1)) |
| 23 | 4, 8, 12, 22 | dedth3h 1788 |
1
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → ((A · B) =
(A · C) ↔ B =
C)) |