Proof of Theorem mulresr
| Step | Hyp | Ref
| Expression |
| 1 | | 0r 3983 |
. . . 4
⊢ 0R ∈
R |
| 2 | 1, 1 | pm3.2i 234 |
. . 3
⊢ (0R ∈
R ∧ 0R ∈
R) |
| 3 | | mulcnsr 4048 |
. . . 4
⊢ (((A
∈ R ∧ 0R ∈
R) ∧ (B ∈
R ∧ 0R ∈ R))
→ (〈A,
0R〉 · 〈B, 0R〉) =
〈((A
·R B)
+R (-1R
·R (0R
·R 0R))),
((0R ·R B) +R (A ·R
0R))〉) |
| 4 | 3 | an4s 390 |
. . 3
⊢ (((A
∈ R ∧ B ∈
R) ∧ (0R ∈ R
∧ 0R ∈ R)) →
(〈A, 0R〉
· 〈B,
0R〉) = 〈((A ·R B) +R
(-1R ·R
(0R ·R
0R))), ((0R
·R B)
+R (A
·R
0R))〉) |
| 5 | 2, 4 | mpan2 519 |
. 2
⊢ ((A
∈ R ∧ B ∈
R) → (〈A,
0R〉 · 〈B, 0R〉) =
〈((A
·R B)
+R (-1R
·R (0R
·R 0R))),
((0R ·R B) +R (A ·R
0R))〉) |
| 6 | | opeq12 1878 |
. . 3
⊢ ((((A
·R B)
+R (-1R
·R (0R
·R 0R))) = (A ·R B) ∧ ((0R
·R B)
+R (A
·R 0R)) =
0R) → 〈((A ·R B) +R
(-1R ·R
(0R ·R
0R))), ((0R
·R B)
+R (A
·R 0R))〉 =
〈(A ·R
B),
0R〉) |
| 7 | | mulclsr 3987 |
. . . . 5
⊢ ((A
∈ R ∧ B ∈
R) → (A
·R B)
∈ R) |
| 8 | | 0idsr 4000 |
. . . . 5
⊢ ((A
·R B)
∈ R → ((A
·R B)
+R 0R) = (A ·R B)) |
| 9 | 7, 8 | syl 12 |
. . . 4
⊢ ((A
∈ R ∧ B ∈
R) → ((A
·R B)
+R 0R) = (A ·R B)) |
| 10 | | 00sr 4002 |
. . . . . . . 8
⊢ (0R ∈
R → (0R
·R 0R) =
0R) |
| 11 | 1, 10 | ax-mp 6 |
. . . . . . 7
⊢ (0R
·R 0R) =
0R |
| 12 | 11 | opreq2i 3010 |
. . . . . 6
⊢ (-1R
·R (0R
·R 0R)) =
(-1R ·R
0R) |
| 13 | | m1r 3985 |
. . . . . . 7
⊢ -1R ∈
R |
| 14 | | 00sr 4002 |
. . . . . . 7
⊢ (-1R ∈
R → (-1R
·R 0R) =
0R) |
| 15 | 13, 14 | ax-mp 6 |
. . . . . 6
⊢ (-1R
·R 0R) =
0R |
| 16 | 12, 15 | eqtr 1119 |
. . . . 5
⊢ (-1R
·R (0R
·R 0R)) =
0R |
| 17 | 16 | opreq2i 3010 |
. . . 4
⊢ ((A
·R B)
+R (-1R
·R (0R
·R 0R))) = ((A ·R B) +R
0R) |
| 18 | 9, 17 | syl5eq 1136 |
. . 3
⊢ ((A
∈ R ∧ B ∈
R) → ((A
·R B)
+R (-1R
·R (0R
·R 0R))) = (A ·R B)) |
| 19 | | 00sr 4002 |
. . . . . 6
⊢ (B
∈ R → (B
·R 0R) =
0R) |
| 20 | 1 | elisseti 1355 |
. . . . . . 7
⊢ 0R ∈
V |
| 21 | | mulresr.1 |
. . . . . . 7
⊢ B
∈ V |
| 22 | 20, 21 | mulcomsr 3992 |
. . . . . 6
⊢ (0R
·R B) =
(B ·R
0R) |
| 23 | 19, 22 | syl5eq 1136 |
. . . . 5
⊢ (B
∈ R → (0R
·R B) =
0R) |
| 24 | | 00sr 4002 |
. . . . 5
⊢ (A
∈ R → (A
·R 0R) =
0R) |
| 25 | 23, 24 | opreqan12rd 3016 |
. . . 4
⊢ ((A
∈ R ∧ B ∈
R) → ((0R
·R B)
+R (A
·R 0R)) =
(0R +R
0R)) |
| 26 | | 0idsr 4000 |
. . . . 5
⊢ (0R ∈
R → (0R +R
0R) = 0R) |
| 27 | 1, 26 | ax-mp 6 |
. . . 4
⊢ (0R
+R 0R) =
0R |
| 28 | 25, 27 | syl6eq 1140 |
. . 3
⊢ ((A
∈ R ∧ B ∈
R) → ((0R
·R B)
+R (A
·R 0R)) =
0R) |
| 29 | 6, 18, 28 | sylanc 361 |
. 2
⊢ ((A
∈ R ∧ B ∈
R) → 〈((A
·R B)
+R (-1R
·R (0R
·R 0R))),
((0R ·R B) +R (A ·R
0R))〉 = 〈(A ·R B), 0R〉) |
| 30 | 5, 29 | eqtrd 1128 |
1
⊢ ((A
∈ R ∧ B ∈
R) → (〈A,
0R〉 · 〈B, 0R〉) =
〈(A ·R
B),
0R〉) |