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Theorem nssinpss 1665
Description: Negation of subclass expressed in terms of intersection and proper subclass.
Assertion
Ref Expression
nssinpss AB ↔ (AB) ⊂ A)

Proof of Theorem nssinpss
StepHypRef Expression
1 inss1 1657 . . 3 (AB) ⊆ A
21biantrur 544 . 2 A ⊆ (AB) ↔ ((AB) ⊆ A ∧ ¬ A ⊆ (AB)))
3 ssid 1519 . . . . 5 AA
43biantrur 544 . . . 4 (AB ↔ (AAAB))
5 ssin 1659 . . . 4 ((AAAB) ↔ A ⊆ (AB))
64, 5bitr 151 . . 3 (ABA ⊆ (AB))
76negbii 162 . 2 AB ↔ ¬ A ⊆ (AB))
8 dfpss3 1558 . 2 ((AB) ⊂ A ↔ ((AB) ⊆ A ∧ ¬ A ⊆ (AB)))
92, 7, 83bitr4 158 1 AB ↔ (AB) ⊂ A)
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   ↔ wb 127   ∧ wa 196   ∩ cin 1486   ⊆ wss 1487   ⊂ wpss 1488
This theorem is referenced by:  chrelat2 5758
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-ne 1192  df-v 1349  df-in 1491  df-ss 1492  df-pss 1494
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