Proof of Theorem oalim
| Step | Hyp | Ref
| Expression |
| 1 | | rdglim2a 2988 |
. . . 4
⊢ ((B
∈ On ∧ Lim B) →
(rec({〈y, z〉∣z
= suc y}, A) ‘B) =
∪x ∈
B (rec({〈y, z〉∣z
= suc y}, A) ‘x)) |
| 2 | 1 | adantl 305 |
. . 3
⊢ ((A
∈ On ∧ (B ∈ On ∧ Lim
B)) → (rec({〈y, z〉∣z
= suc y}, A) ‘B) =
∪x ∈
B (rec({〈y, z〉∣z
= suc y}, A) ‘x)) |
| 3 | | oav 3119 |
. . . . 5
⊢ ((A
∈ On ∧ B ∈ On) →
(A +o B) = (rec({〈y, z〉∣z
= suc y}, A) ‘B)) |
| 4 | | oav 3119 |
. . . . . . . . 9
⊢ ((A
∈ On ∧ x ∈ On) →
(A +o x) = (rec({〈y, z〉∣z
= suc y}, A) ‘x)) |
| 5 | | onelon 2223 |
. . . . . . . . 9
⊢ ((B
∈ On ∧ x ∈ B) → x
∈ On) |
| 6 | 4, 5 | sylan2 346 |
. . . . . . . 8
⊢ ((A
∈ On ∧ (B ∈ On ∧ x ∈ B))
→ (A +o x) = (rec({〈y, z〉∣z
= suc y}, A) ‘x)) |
| 7 | 6 | anassrs 338 |
. . . . . . 7
⊢ (((A
∈ On ∧ B ∈ On) ∧ x ∈ B)
→ (A +o x) = (rec({〈y, z〉∣z
= suc y}, A) ‘x)) |
| 8 | 7 | exp 291 |
. . . . . 6
⊢ ((A
∈ On ∧ B ∈ On) →
(x ∈ B → (A
+o x) =
(rec({〈y, z〉∣z
= suc y}, A) ‘x))) |
| 9 | 8 | iuneq2dv 2010 |
. . . . 5
⊢ ((A
∈ On ∧ B ∈ On) → ∪x ∈ B (A
+o x) = ∪x ∈ B (rec({〈y,
z〉∣z = suc y},
A) ‘x)) |
| 10 | 3, 9 | cleq12d 1115 |
. . . 4
⊢ ((A
∈ On ∧ B ∈ On) →
((A +o B) = ∪x ∈ B
(A +o x) ↔ (rec({〈y, z〉∣z
= suc y}, A) ‘B) =
∪x ∈
B (rec({〈y, z〉∣z
= suc y}, A) ‘x))) |
| 11 | 10 | adantrr 312 |
. . 3
⊢ ((A
∈ On ∧ (B ∈ On ∧ Lim
B)) → ((A +o B) = ∪x ∈ B
(A +o x) ↔ (rec({〈y, z〉∣z
= suc y}, A) ‘B) =
∪x ∈
B (rec({〈y, z〉∣z
= suc y}, A) ‘x))) |
| 12 | 2, 11 | mpbird 171 |
. 2
⊢ ((A
∈ On ∧ (B ∈ On ∧ Lim
B)) → (A +o B) = ∪x ∈ B
(A +o x)) |
| 13 | | limelon 2286 |
. . 3
⊢ ((B
∈ C ∧ Lim B) → B
∈ On) |
| 14 | | pm3.27 260 |
. . 3
⊢ ((B
∈ C ∧ Lim B) → Lim B) |
| 15 | 13, 14 | jca 236 |
. 2
⊢ ((B
∈ C ∧ Lim B) → (B
∈ On ∧ Lim B)) |
| 16 | 12, 15 | sylan2 346 |
1
⊢ ((A
∈ On ∧ (B ∈ C ∧ Lim B))
→ (A +o B) = ∪x ∈ B
(A +o x)) |