Proof of Theorem onmindif
| Step | Hyp | Ref
| Expression |
| 1 | | ontri1 2232 |
. . . . . . . . . . 11
⊢ ((x
∈ On ∧ B ∈ On) →
(x ⊆ B ↔ ¬ B
∈ x)) |
| 2 | | onsssuc 2311 |
. . . . . . . . . . 11
⊢ ((x
∈ On ∧ B ∈ On) →
(x ⊆ B ↔ x
∈ suc B)) |
| 3 | 1, 2 | bitr3d 408 |
. . . . . . . . . 10
⊢ ((x
∈ On ∧ B ∈ On) → (¬
B ∈ x ↔ x
∈ suc B)) |
| 4 | 3 | bicon1d 405 |
. . . . . . . . 9
⊢ ((x
∈ On ∧ B ∈ On) → (¬
x ∈ suc B ↔ B
∈ x)) |
| 5 | | ssel2 1503 |
. . . . . . . . 9
⊢ ((A
⊆ On ∧ x ∈ A) → x
∈ On) |
| 6 | 4, 5 | sylan 343 |
. . . . . . . 8
⊢ (((A
⊆ On ∧ x ∈ A) ∧ B
∈ On) → (¬ x ∈ suc
B ↔ B ∈ x)) |
| 7 | 6 | biimpd 135 |
. . . . . . 7
⊢ (((A
⊆ On ∧ x ∈ A) ∧ B
∈ On) → (¬ x ∈ suc
B → B ∈ x)) |
| 8 | 7 | exp31 293 |
. . . . . 6
⊢ (A
⊆ On → (x ∈ A → (B
∈ On → (¬ x ∈ suc
B → B ∈ x)))) |
| 9 | 8 | com23 32 |
. . . . 5
⊢ (A
⊆ On → (B ∈ On →
(x ∈ A → (¬ x ∈ suc B
→ B ∈ x)))) |
| 10 | 9 | imp4b 283 |
. . . 4
⊢ ((A
⊆ On ∧ B ∈ On) →
((x ∈ A ∧ ¬ x
∈ suc B) → B ∈ x)) |
| 11 | | eldif 1496 |
. . . 4
⊢ (x
∈ (A ∖ suc B) ↔ (x
∈ A ∧ ¬ x ∈ suc B)) |
| 12 | 10, 11 | syl5ib 181 |
. . 3
⊢ ((A
⊆ On ∧ B ∈ On) →
(x ∈ (A ∖ suc B)
→ B ∈ x)) |
| 13 | 12 | r19.21aiv 1259 |
. 2
⊢ ((A
⊆ On ∧ B ∈ On) →
∀x ∈ (A ∖ suc B)B ∈
x) |
| 14 | | elintg 1973 |
. . 3
⊢ (B
∈ On → (B ∈ ∩(A ∖ suc
B) ↔ ∀x ∈ (A
∖ suc B)B ∈ x)) |
| 15 | 14 | adantl 305 |
. 2
⊢ ((A
⊆ On ∧ B ∈ On) →
(B ∈ ∩(A ∖ suc
B) ↔ ∀x ∈ (A
∖ suc B)B ∈ x)) |
| 16 | 13, 15 | mpbird 171 |
1
⊢ ((A
⊆ On ∧ B ∈ On) →
B ∈ ∩(A ∖ suc
B)) |