Proof of Theorem pjthlem8
| Step | Hyp | Ref
| Expression |
| 1 | | pjthlem6.1 |
. . . 4
⊢ D
∈ ℋ |
| 2 | | pjthlem6.2 |
. . . 4
⊢ R = (1
/ (D ·i
D)) |
| 3 | | pjthlem6.3 |
. . . 4
⊢ C
∈ ℋ |
| 4 | | pjthlem6.4 |
. . . 4
⊢ S =
(R · (C ·i D)) |
| 5 | 1, 2, 3, 4 | pjthlem4 5228 |
. . 3
⊢ (¬ D = 0v → S ∈ ℂ) |
| 6 | | opreq1 3006 |
. . . . . . . 8
⊢ (S =
if(S ∈ ℂ, S, 0) → (S
·s D) =
(if(S ∈ ℂ, S, 0) ·s D)) |
| 7 | 6 | opreq2d 3013 |
. . . . . . 7
⊢ (S =
if(S ∈ ℂ, S, 0) → (C
−v (S
·s D)) =
(C −v (if(S ∈ ℂ, S, 0) ·s D))) |
| 8 | 7 | fveq2d 2836 |
. . . . . 6
⊢ (S =
if(S ∈ ℂ, S, 0) → (norm ‘(C −v (S ·s D))) = (norm ‘(C −v (if(S ∈ ℂ, S, 0) ·s D)))) |
| 9 | 8 | opreq1d 3012 |
. . . . 5
⊢ (S =
if(S ∈ ℂ, S, 0) → ((norm ‘(C −v (S ·s D)))↑2) = ((norm ‘(C −v (if(S ∈ ℂ, S, 0) ·s D)))↑2)) |
| 10 | | opreq1 3006 |
. . . . . . . 8
⊢ (S =
if(S ∈ ℂ, S, 0) → (S
· (D
·i C)) =
(if(S ∈ ℂ, S, 0) · (D ·i C))) |
| 11 | 10 | fveq2d 2836 |
. . . . . . 7
⊢ (S =
if(S ∈ ℂ, S, 0) → (∗ ‘(S · (D
·i C))) =
(∗ ‘(if(S ∈ ℂ,
S, 0) · (D ·i C)))) |
| 12 | 11 | opreq2d 3013 |
. . . . . 6
⊢ (S =
if(S ∈ ℂ, S, 0) → (((norm ‘C)↑2) − (∗ ‘(S · (D
·i C)))) =
(((norm ‘C)↑2) − (∗
‘(if(S ∈ ℂ, S, 0) · (D ·i C))))) |
| 13 | | id 9 |
. . . . . . . . 9
⊢ (S =
if(S ∈ ℂ, S, 0) → S =
if(S ∈ ℂ, S, 0)) |
| 14 | | fveq2 2832 |
. . . . . . . . 9
⊢ (S =
if(S ∈ ℂ, S, 0) → (∗ ‘S) = (∗ ‘if(S ∈ ℂ, S, 0))) |
| 15 | 13, 14 | opreq12d 3014 |
. . . . . . . 8
⊢ (S =
if(S ∈ ℂ, S, 0) → (S
· (∗ ‘S)) =
(if(S ∈ ℂ, S, 0) · (∗ ‘if(S ∈ ℂ, S, 0)))) |
| 16 | 15 | opreq1d 3012 |
. . . . . . 7
⊢ (S =
if(S ∈ ℂ, S, 0) → ((S
· (∗ ‘S)) ·
(D ·i
D)) = ((if(S ∈ ℂ, S, 0) · (∗ ‘if(S ∈ ℂ, S, 0))) · (D ·i D))) |
| 17 | 16, 10 | opreq12d 3014 |
. . . . . 6
⊢ (S =
if(S ∈ ℂ, S, 0) → (((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C))) = (((if(S
∈ ℂ, S, 0) · (∗
‘if(S ∈ ℂ, S, 0))) · (D ·i D)) − (if(S ∈ ℂ, S, 0) · (D ·i C)))) |
| 18 | 12, 17 | opreq12d 3014 |
. . . . 5
⊢ (S =
if(S ∈ ℂ, S, 0) → ((((norm ‘C)↑2) − (∗ ‘(S · (D
·i C)))) +
(((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C)))) = ((((norm ‘C)↑2) − (∗ ‘(if(S ∈ ℂ, S, 0) · (D ·i C)))) + (((if(S
∈ ℂ, S, 0) · (∗
‘if(S ∈ ℂ, S, 0))) · (D ·i D)) − (if(S ∈ ℂ, S, 0) · (D ·i C))))) |
| 19 | 9, 18 | cleq12d 1115 |
. . . 4
⊢ (S =
if(S ∈ ℂ, S, 0) → (((norm ‘(C −v (S ·s D)))↑2) = ((((norm ‘C)↑2) − (∗ ‘(S · (D
·i C)))) +
(((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C)))) ↔ ((norm ‘(C −v (if(S ∈ ℂ, S, 0) ·s D)))↑2) = ((((norm ‘C)↑2) − (∗ ‘(if(S ∈ ℂ, S, 0) · (D ·i C)))) + (((if(S
∈ ℂ, S, 0) · (∗
‘if(S ∈ ℂ, S, 0))) · (D ·i D)) − (if(S ∈ ℂ, S, 0) · (D ·i C)))))) |
| 20 | | 0cn 4100 |
. . . . . 6
⊢ 0 ∈ ℂ |
| 21 | 20 | elimel 1793 |
. . . . 5
⊢ if(S
∈ ℂ, S, 0) ∈
ℂ |
| 22 | 1, 3, 21 | pjthlem5 5229 |
. . . 4
⊢ ((norm ‘(C −v (if(S ∈ ℂ, S, 0) ·s D)))↑2) = ((((norm ‘C)↑2) − (∗ ‘(if(S ∈ ℂ, S, 0) · (D ·i C)))) + (((if(S
∈ ℂ, S, 0) · (∗
‘if(S ∈ ℂ, S, 0))) · (D ·i D)) − (if(S ∈ ℂ, S, 0) · (D ·i C)))) |
| 23 | 19, 22 | dedth 1784 |
. . 3
⊢ (S
∈ ℂ → ((norm ‘(C
−v (S
·s D)))↑2) = ((((norm ‘C)↑2) − (∗ ‘(S · (D
·i C)))) +
(((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C))))) |
| 24 | 5, 23 | syl 12 |
. 2
⊢ (¬ D = 0v → ((norm
‘(C −v
(S ·s
D)))↑2) = ((((norm ‘C)↑2) − (∗ ‘(S · (D
·i C)))) +
(((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C))))) |
| 25 | 1, 2, 3, 4 | pjthlem6 5230 |
. . . . . 6
⊢ (¬ D = 0v → (S · (D
·i C)) =
(R · ((abs ‘(C ·i D))↑2))) |
| 26 | 25 | fveq2d 2836 |
. . . . 5
⊢ (¬ D = 0v → (∗
‘(S · (D ·i C))) = (∗ ‘(R · ((abs ‘(C ·i D))↑2)))) |
| 27 | 1, 2 | pjthlem2 5226 |
. . . . . 6
⊢ (¬ D = 0v → R ∈ ℝ) |
| 28 | 3, 1 | hicl 5044 |
. . . . . . . . 9
⊢ (C
·i D)
∈ ℂ |
| 29 | 28 | abscl 4840 |
. . . . . . . 8
⊢ (abs ‘(C ·i D)) ∈ ℝ |
| 30 | 29 | sqrecl 4699 |
. . . . . . 7
⊢ ((abs ‘(C ·i D))↑2) ∈ ℝ |
| 31 | | axmulrcl 4069 |
. . . . . . 7
⊢ ((R
∈ ℝ ∧ ((abs ‘(C
·i D))↑2) ∈ ℝ) → (R · ((abs ‘(C ·i D))↑2)) ∈ ℝ) |
| 32 | 30, 31 | mpan2 519 |
. . . . . 6
⊢ (R
∈ ℝ → (R · ((abs
‘(C
·i D))↑2)) ∈ ℝ) |
| 33 | | cjret 4829 |
. . . . . 6
⊢ ((R
· ((abs ‘(C
·i D))↑2)) ∈ ℝ → (∗
‘(R · ((abs ‘(C ·i D))↑2))) = (R · ((abs ‘(C ·i D))↑2))) |
| 34 | 27, 32, 33 | 3syl 21 |
. . . . 5
⊢ (¬ D = 0v → (∗
‘(R · ((abs ‘(C ·i D))↑2))) = (R · ((abs ‘(C ·i D))↑2))) |
| 35 | 26, 34 | eqtrd 1128 |
. . . 4
⊢ (¬ D = 0v → (∗
‘(S · (D ·i C))) = (R
· ((abs ‘(C
·i D))↑2))) |
| 36 | 35 | opreq2d 3013 |
. . 3
⊢ (¬ D = 0v → (((norm
‘C)↑2) − (∗
‘(S · (D ·i C)))) = (((norm ‘C)↑2) − (R · ((abs ‘(C ·i D))↑2)))) |
| 37 | 1, 2, 3, 4 | pjthlem7 5231 |
. . . . 5
⊢ (¬ D = 0v → ((S · (∗ ‘S)) · (D
·i D)) =
(R · ((abs ‘(C ·i D))↑2))) |
| 38 | 37, 25 | opreq12d 3014 |
. . . 4
⊢ (¬ D = 0v → (((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C))) = ((R
· ((abs ‘(C
·i D))↑2)) − (R · ((abs ‘(C ·i D))↑2)))) |
| 39 | 27, 32 | syl 12 |
. . . . . 6
⊢ (¬ D = 0v → (R · ((abs ‘(C ·i D))↑2)) ∈ ℝ) |
| 40 | 39 | recnd 4099 |
. . . . 5
⊢ (¬ D = 0v → (R · ((abs ‘(C ·i D))↑2)) ∈ ℂ) |
| 41 | | subidt 4159 |
. . . . 5
⊢ ((R
· ((abs ‘(C
·i D))↑2)) ∈ ℂ → ((R · ((abs ‘(C ·i D))↑2)) − (R · ((abs ‘(C ·i D))↑2))) = 0) |
| 42 | 40, 41 | syl 12 |
. . . 4
⊢ (¬ D = 0v → ((R · ((abs ‘(C ·i D))↑2)) − (R · ((abs ‘(C ·i D))↑2))) = 0) |
| 43 | 38, 42 | eqtrd 1128 |
. . 3
⊢ (¬ D = 0v → (((S · (∗ ‘S)) · (D
·i D))
− (S · (D ·i C))) = 0) |
| 44 | 36, 43 | opreq12d 3014 |
. 2
⊢ (¬ D = 0v → ((((norm
‘C)↑2) − (∗
‘(S · (D ·i C)))) + (((S
· (∗ ‘S)) ·
(D ·i
D)) − (S · (D
·i C)))) =
((((norm ‘C)↑2) −
(R · ((abs ‘(C ·i D))↑2))) + 0)) |
| 45 | 3 | normcl 5081 |
. . . . . 6
⊢ (norm ‘C) ∈ ℝ |
| 46 | 45 | sqrecl 4699 |
. . . . 5
⊢ ((norm ‘C)↑2) ∈ ℝ |
| 47 | 46 | recn 4098 |
. . . 4
⊢ ((norm ‘C)↑2) ∈ ℂ |
| 48 | | subclt 4140 |
. . . 4
⊢ ((((norm ‘C)↑2) ∈ ℂ ∧ (R · ((abs ‘(C ·i D))↑2)) ∈ ℂ) → (((norm
‘C)↑2) − (R · ((abs ‘(C ·i D))↑2))) ∈ ℂ) |
| 49 | 47, 48 | mpan 518 |
. . 3
⊢ ((R
· ((abs ‘(C
·i D))↑2)) ∈ ℂ → (((norm
‘C)↑2) − (R · ((abs ‘(C ·i D))↑2))) ∈ ℂ) |
| 50 | | ax0id 4076 |
. . 3
⊢ ((((norm ‘C)↑2) − (R · ((abs ‘(C ·i D))↑2))) ∈ ℂ → ((((norm
‘C)↑2) − (R · ((abs ‘(C ·i D))↑2))) + 0) = (((norm ‘C)↑2) − (R · ((abs ‘(C ·i D))↑2)))) |
| 51 | 40, 49, 50 | 3syl 21 |
. 2
⊢ (¬ D = 0v → ((((norm
‘C)↑2) − (R · ((abs ‘(C ·i D))↑2))) + 0) = (((norm ‘C)↑2) − (R · ((abs ‘(C ·i D))↑2)))) |
| 52 | 24, 44, 51 | 3eqtrd 1132 |
1
⊢ (¬ D = 0v → ((norm
‘(C −v
(S ·s
D)))↑2) = (((norm ‘C)↑2) − (R · ((abs ‘(C ·i D))↑2)))) |