| Metamath Proof Explorer |
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Related theorems GIF version |
| Description: Deduction rule for proof by contradiction. |
| Ref | Expression |
|---|---|
| pm2.65d.1 | ⊢ (φ → (ψ → χ)) |
| pm2.65d.2 | ⊢ (φ → (ψ → ¬ χ)) |
| Ref | Expression |
|---|---|
| pm2.65d | ⊢ (φ → ¬ ψ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | pm2.65 115 | . 2 ⊢ ((ψ → χ) → ((ψ → ¬ χ) → ¬ ψ)) | |
| 2 | pm2.65d.1 | . 2 ⊢ (φ → (ψ → χ)) | |
| 3 | pm2.65d.2 | . 2 ⊢ (φ → (ψ → ¬ χ)) | |
| 4 | 1, 2, 3 | sylc 62 | 1 ⊢ (φ → ¬ ψ) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 1 → wi 2 |
| This theorem is referenced by: cardlim 3657 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 |