| Metamath Proof Explorer |
< Previous
Next >
Related theorems GIF version |
| Description: Distribution of implication over biconditional (reverse inference rule). |
| Ref | Expression |
|---|---|
| pm5.74ri.1 | ⊢ ((φ → ψ) ↔ (φ → χ)) |
| Ref | Expression |
|---|---|
| pm5.74ri | ⊢ (φ → (ψ ↔ χ)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | pm5.74ri.1 | . 2 ⊢ ((φ → ψ) ↔ (φ → χ)) | |
| 2 | pm5.74 442 | . 2 ⊢ ((φ → (ψ ↔ χ)) ↔ ((φ → ψ) ↔ (φ → χ))) | |
| 3 | 1, 2 | mpbir 165 | 1 ⊢ (φ → (ψ ↔ χ)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 2 ↔ wb 127 |
| This theorem is referenced by: iba 486 ibar 487 pm5.1 501 sbco2d 914 cbvald 977 nn0ltp1let 4556 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 |
| This theorem depends on definitions: df-bi 128 df-an 198 |