Proof of Theorem prsspw
| Step | Hyp | Ref
| Expression |
| 1 | | dfss2 1497 |
. 2
⊢ ({A,
B} ⊆ ℘C ↔ ∀x(x ∈
{A, B}
→ x ∈ ℘C)) |
| 2 | | visset 1350 |
. . . . . 6
⊢ x
∈ V |
| 3 | 2 | elpr 1823 |
. . . . 5
⊢ (x
∈ {A, B} ↔ (x =
A ∨ x = B)) |
| 4 | 2 | elpw 1801 |
. . . . 5
⊢ (x
∈ ℘C ↔ x ⊆ C) |
| 5 | 3, 4 | imbi12i 163 |
. . . 4
⊢ ((x
∈ {A, B} → x
∈ ℘C) ↔ ((x = A ∨
x = B)
→ x ⊆ C)) |
| 6 | | jaob 328 |
. . . 4
⊢ (((x =
A ∨ x = B) →
x ⊆ C) ↔ ((x =
A → x ⊆ C)
∧ (x = B → x
⊆ C))) |
| 7 | 5, 6 | bitr 151 |
. . 3
⊢ ((x
∈ {A, B} → x
∈ ℘C) ↔ ((x = A →
x ⊆ C) ∧ (x =
B → x ⊆ C))) |
| 8 | 7 | bial 695 |
. 2
⊢ (∀x(x ∈
{A, B}
→ x ∈ ℘C) ↔ ∀x((x = A → x
⊆ C) ∧ (x = B →
x ⊆ C))) |
| 9 | | 19.26 749 |
. . 3
⊢ (∀x((x = A → x
⊆ C) ∧ (x = B →
x ⊆ C)) ↔ (∀x(x = A → x
⊆ C) ∧ ∀x(x = B → x
⊆ C))) |
| 10 | | prsspw.1 |
. . . . 5
⊢ A
∈ V |
| 11 | | sseq1 1521 |
. . . . 5
⊢ (x =
A → (x ⊆ C
↔ A ⊆ C)) |
| 12 | 10, 11 | ceqsalv 1364 |
. . . 4
⊢ (∀x(x = A → x
⊆ C) ↔ A ⊆ C) |
| 13 | | prsspw.2 |
. . . . 5
⊢ B
∈ V |
| 14 | | sseq1 1521 |
. . . . 5
⊢ (x =
B → (x ⊆ C
↔ B ⊆ C)) |
| 15 | 13, 14 | ceqsalv 1364 |
. . . 4
⊢ (∀x(x = B → x
⊆ C) ↔ B ⊆ C) |
| 16 | 12, 15 | anbi12i 369 |
. . 3
⊢ ((∀x(x = A → x
⊆ C) ∧ ∀x(x = B → x
⊆ C)) ↔ (A ⊆ C
∧ B ⊆ C)) |
| 17 | 9, 16 | bitr 151 |
. 2
⊢ (∀x((x = A → x
⊆ C) ∧ (x = B →
x ⊆ C)) ↔ (A
⊆ C ∧ B ⊆ C)) |
| 18 | 1, 8, 17 | 3bitr 155 |
1
⊢ ({A,
B} ⊆ ℘C ↔ (A
⊆ C ∧ B ⊆ C)) |