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Theorem prsspw 1858
Description: An unordered pair belongs to the power class of a class iff each member belongs to the class.
Hypotheses
Ref Expression
prsspw.1 AV
prsspw.2 BV
Assertion
Ref Expression
prsspw ({A, B} ⊆ ℘C ↔ (ACBC))

Proof of Theorem prsspw
StepHypRef Expression
1 dfss2 1497 . 2 ({A, B} ⊆ ℘C ↔ ∀x(x ∈ {A, B} → x ∈ ℘C))
2 visset 1350 . . . . . 6 xV
32elpr 1823 . . . . 5 (x ∈ {A, B} ↔ (x = Ax = B))
42elpw 1801 . . . . 5 (x ∈ ℘CxC)
53, 4imbi12i 163 . . . 4 ((x ∈ {A, B} → x ∈ ℘C) ↔ ((x = Ax = B) → xC))
6 jaob 328 . . . 4 (((x = Ax = B) → xC) ↔ ((x = AxC) ∧ (x = BxC)))
75, 6bitr 151 . . 3 ((x ∈ {A, B} → x ∈ ℘C) ↔ ((x = AxC) ∧ (x = BxC)))
87bial 695 . 2 (∀x(x ∈ {A, B} → x ∈ ℘C) ↔ ∀x((x = AxC) ∧ (x = BxC)))
9 19.26 749 . . 3 (∀x((x = AxC) ∧ (x = BxC)) ↔ (∀x(x = AxC) ∧ ∀x(x = BxC)))
10 prsspw.1 . . . . 5 AV
11 sseq1 1521 . . . . 5 (x = A → (xCAC))
1210, 11ceqsalv 1364 . . . 4 (∀x(x = AxC) ↔ AC)
13 prsspw.2 . . . . 5 BV
14 sseq1 1521 . . . . 5 (x = B → (xCBC))
1513, 14ceqsalv 1364 . . . 4 (∀x(x = BxC) ↔ BC)
1612, 15anbi12i 369 . . 3 ((∀x(x = AxC) ∧ ∀x(x = BxC)) ↔ (ACBC))
179, 16bitr 151 . 2 (∀x((x = AxC) ∧ (x = BxC)) ↔ (ACBC))
181, 8, 173bitr 155 1 ({A, B} ⊆ ℘C ↔ (ACBC))
Colors of variables: wff set class
Syntax hints:   → wi 2   ↔ wb 127   ∨ wo 195   ∧ wa 196  ∀wal 672   = wceq 1091   ∈ wcel 1092  Vcvv 1348   ⊆ wss 1487  ℘cpw 1798  {cpr 1809
This theorem is referenced by:  dfchj3 5326
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-un 1490  df-in 1491  df-ss 1492  df-pw 1799  df-sn 1811  df-pr 1812
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