Proof of Theorem psslinpr
| Step | Hyp | Ref
| Expression |
| 1 | | prub 3892 |
. . . . . . . . . . . . 13
⊢ (((B
∈ P ∧ y ∈
B) ∧ x ∈ Q) → (¬ x ∈ B
→ y <Q
x)) |
| 2 | | elprpq 3889 |
. . . . . . . . . . . . 13
⊢ ((A
∈ P ∧ x ∈
A) → x ∈ Q) |
| 3 | 1, 2 | sylan2 346 |
. . . . . . . . . . . 12
⊢ (((B
∈ P ∧ y ∈
B) ∧ (A ∈ P ∧ x ∈ A))
→ (¬ x ∈ B → y
<Q x)) |
| 4 | | prcdpq 3891 |
. . . . . . . . . . . . 13
⊢ ((A
∈ P ∧ x ∈
A) → (y <Q x → y
∈ A)) |
| 5 | 4 | adantl 305 |
. . . . . . . . . . . 12
⊢ (((B
∈ P ∧ y ∈
B) ∧ (A ∈ P ∧ x ∈ A))
→ (y <Q
x → y ∈ A)) |
| 6 | 3, 5 | syld 27 |
. . . . . . . . . . 11
⊢ (((B
∈ P ∧ y ∈
B) ∧ (A ∈ P ∧ x ∈ A))
→ (¬ x ∈ B → y
∈ A)) |
| 7 | 6 | exp43 301 |
. . . . . . . . . 10
⊢ (B
∈ P → (y ∈
B → (A ∈ P → (x ∈ A
→ (¬ x ∈ B → y
∈ A))))) |
| 8 | 7 | com3r 35 |
. . . . . . . . 9
⊢ (A
∈ P → (B ∈
P → (y ∈ B → (x
∈ A → (¬ x ∈ B
→ y ∈ A))))) |
| 9 | 8 | imp 277 |
. . . . . . . 8
⊢ ((A
∈ P ∧ B ∈
P) → (y ∈ B → (x
∈ A → (¬ x ∈ B
→ y ∈ A)))) |
| 10 | 9 | imp4a 282 |
. . . . . . 7
⊢ ((A
∈ P ∧ B ∈
P) → (y ∈ B → ((x
∈ A ∧ ¬ x ∈ B)
→ y ∈ A))) |
| 11 | 10 | com23 32 |
. . . . . 6
⊢ ((A
∈ P ∧ B ∈
P) → ((x ∈ A ∧ ¬ x
∈ B) → (y ∈ B
→ y ∈ A))) |
| 12 | 11 | 19.21adv 945 |
. . . . 5
⊢ ((A
∈ P ∧ B ∈
P) → ((x ∈ A ∧ ¬ x
∈ B) → ∀y(y ∈
B → y ∈ A))) |
| 13 | 12 | 19.23adv 954 |
. . . 4
⊢ ((A
∈ P ∧ B ∈
P) → (∃x(x ∈ A ∧
¬ x ∈ B) → ∀y(y ∈
B → y ∈ A))) |
| 14 | | sspss 1569 |
. . . . . 6
⊢ (A
⊆ B ↔ (A ⊂ B ∨
A = B)) |
| 15 | 14 | negbii 162 |
. . . . 5
⊢ (¬ A ⊆ B
↔ ¬ (A ⊂ B ∨ A =
B)) |
| 16 | | nss 1550 |
. . . . 5
⊢ (¬ A ⊆ B
↔ ∃x(x ∈ A ∧
¬ x ∈ B)) |
| 17 | 15, 16 | bitr3 153 |
. . . 4
⊢ (¬ (A ⊂ B ∨
A = B)
↔ ∃x(x ∈ A ∧
¬ x ∈ B)) |
| 18 | | sspss 1569 |
. . . . 5
⊢ (B
⊆ A ↔ (B ⊂ A ∨
B = A)) |
| 19 | | dfss2 1497 |
. . . . 5
⊢ (B
⊆ A ↔ ∀y(y ∈
B → y ∈ A)) |
| 20 | 18, 19 | bitr3 153 |
. . . 4
⊢ ((B
⊂ A ∨ B = A) ↔
∀y(y ∈ B
→ y ∈ A)) |
| 21 | 13, 17, 20 | 3imtr4g 426 |
. . 3
⊢ ((A
∈ P ∧ B ∈
P) → (¬ (A ⊂
B ∨ A = B) →
(B ⊂ A ∨ B =
A))) |
| 22 | 21 | orrd 203 |
. 2
⊢ ((A
∈ P ∧ B ∈
P) → ((A ⊂ B ∨ A =
B) ∨ (B ⊂ A ∨
B = A))) |
| 23 | | df-3or 582 |
. . 3
⊢ ((A
⊂ B ∨ A = B ∨
B ⊂ A) ↔ ((A
⊂ B ∨ A = B) ∨
B ⊂ A)) |
| 24 | | or23 219 |
. . 3
⊢ (((A
⊂ B ∨ A = B) ∨
B ⊂ A) ↔ ((A
⊂ B ∨ B ⊂ A) ∨
A = B)) |
| 25 | | orordir 223 |
. . . 4
⊢ (((A
⊂ B ∨ B ⊂ A) ∨
A = B)
↔ ((A ⊂ B ∨ A =
B) ∨ (B ⊂ A ∨
A = B))) |
| 26 | | cleqcom 1103 |
. . . . . 6
⊢ (B =
A ↔ A = B) |
| 27 | 26 | orbi2i 214 |
. . . . 5
⊢ ((B
⊂ A ∨ B = A) ↔
(B ⊂ A ∨ A =
B)) |
| 28 | 27 | orbi2i 214 |
. . . 4
⊢ (((A
⊂ B ∨ A = B) ∨
(B ⊂ A ∨ B =
A)) ↔ ((A ⊂ B ∨
A = B)
∨ (B ⊂ A ∨ A =
B))) |
| 29 | 25, 28 | bitr4 154 |
. . 3
⊢ (((A
⊂ B ∨ B ⊂ A) ∨
A = B)
↔ ((A ⊂ B ∨ A =
B) ∨ (B ⊂ A ∨
B = A))) |
| 30 | 23, 24, 29 | 3bitr 155 |
. 2
⊢ ((A
⊂ B ∨ A = B ∨
B ⊂ A) ↔ ((A
⊂ B ∨ A = B) ∨
(B ⊂ A ∨ B =
A))) |
| 31 | 22, 30 | sylibr 175 |
1
⊢ ((A
∈ P ∧ B ∈
P) → (A ⊂ B ∨ A =
B ∨ B ⊂ A)) |