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Theorem pwin 1915
Description: The power class of the intersection of two classes is the intersection of their power classes. Exercise 4.12(j) of [Mendelson] p. 235.
Assertion
Ref Expression
pwin ℘(AB) = (℘A ∩ ℘B)

Proof of Theorem pwin
StepHypRef Expression
1 ssin 1659 . . . 4 ((xAxB) ↔ x ⊆ (AB))
2 visset 1350 . . . . . 6 xV
32elpw 1801 . . . . 5 (x ∈ ℘AxA)
42elpw 1801 . . . . 5 (x ∈ ℘BxB)
53, 4anbi12i 369 . . . 4 ((x ∈ ℘Ax ∈ ℘B) ↔ (xAxB))
62elpw 1801 . . . 4 (x ∈ ℘(AB) ↔ x ⊆ (AB))
71, 5, 63bitr4 158 . . 3 ((x ∈ ℘Ax ∈ ℘B) ↔ x ∈ ℘(AB))
87ineqri 1637 . 2 (℘A ∩ ℘B) = ℘(AB)
98cleqcomi 1105 1 ℘(AB) = (℘A ∩ ℘B)
Colors of variables: wff set class
Syntax hints:   ∧ wa 196   = wceq 1091   ∈ wcel 1092   ∩ cin 1486   ⊆ wss 1487  ℘cpw 1798
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-in 1491  df-ss 1492  df-pw 1799
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