Proof of Theorem ralcom
| Step | Hyp | Ref
| Expression |
| 1 | | ancom 333 |
. . . . 5
⊢ ((x
∈ A ∧ y ∈ B)
↔ (y ∈ B ∧ x ∈
A)) |
| 2 | 1 | imbi1i 161 |
. . . 4
⊢ (((x
∈ A ∧ y ∈ B)
→ φ) ↔ ((y ∈ B ∧
x ∈ A) → φ)) |
| 3 | 2 | bi2al 696 |
. . 3
⊢ (∀x∀y((x ∈
A ∧ y ∈ B)
→ φ) ↔ ∀x∀y((y ∈
B ∧ x ∈ A)
→ φ)) |
| 4 | | alcom 715 |
. . 3
⊢ (∀x∀y((y ∈
B ∧ x ∈ A)
→ φ) ↔ ∀y∀x((y ∈
B ∧ x ∈ A)
→ φ)) |
| 5 | 3, 4 | bitr 151 |
. 2
⊢ (∀x∀y((x ∈
A ∧ y ∈ B)
→ φ) ↔ ∀y∀x((y ∈
B ∧ x ∈ A)
→ φ)) |
| 6 | | r2al 1231 |
. 2
⊢ (∀x ∈ A
∀y ∈ B φ ↔
∀x∀y((x ∈
A ∧ y ∈ B)
→ φ)) |
| 7 | | r2al 1231 |
. 2
⊢ (∀y ∈ B
∀x ∈ A φ ↔
∀y∀x((y ∈
B ∧ x ∈ A)
→ φ)) |
| 8 | 5, 6, 7 | 3bitr4 158 |
1
⊢ (∀x ∈ A
∀y ∈ B φ ↔
∀y ∈ B ∀x
∈ A φ) |