Proof of Theorem rdglem2
| Step | Hyp | Ref
| Expression |
| 1 | | opeq1 1876 |
. . . . . . 7
⊢ (x =
z → 〈x, y〉 =
〈z, y〉) |
| 2 | 1 | cleq2d 1112 |
. . . . . 6
⊢ (x =
z → (w = 〈x,
y〉 ↔ w = 〈z,
y〉)) |
| 3 | | cleq1 1107 |
. . . . . . . 8
⊢ (x =
z → (x = ∅ ↔ z = ∅)) |
| 4 | 3 | anbi1d 469 |
. . . . . . 7
⊢ (x =
z → ((x = ∅ ∧ y = A) ↔
(z = ∅ ∧ y = A))) |
| 5 | | dmeq 2531 |
. . . . . . . . . . 11
⊢ (x =
z → dom x = dom z) |
| 6 | | limeq 2211 |
. . . . . . . . . . 11
⊢ (dom x
= dom z → (Lim dom x ↔ Lim dom z)) |
| 7 | 5, 6 | syl 12 |
. . . . . . . . . 10
⊢ (x =
z → (Lim dom x ↔ Lim dom z)) |
| 8 | 3, 7 | orbi12d 475 |
. . . . . . . . 9
⊢ (x =
z → ((x = ∅ ∨ Lim dom x) ↔ (z =
∅ ∨ Lim dom z))) |
| 9 | 8 | negbid 463 |
. . . . . . . 8
⊢ (x =
z → (¬ (x = ∅ ∨ Lim dom x) ↔ ¬ (z = ∅ ∨ Lim dom z))) |
| 10 | | unieq 1927 |
. . . . . . . . . . . 12
⊢ (dom x
= dom z → ∪dom x = ∪dom z) |
| 11 | | fveq2 2832 |
. . . . . . . . . . . 12
⊢ (∪dom x = ∪dom z → (x
‘∪dom x) =
(x ‘∪dom
z)) |
| 12 | 5, 10, 11 | 3syl 21 |
. . . . . . . . . . 11
⊢ (x =
z → (x ‘∪dom x) = (x
‘∪dom z)) |
| 13 | | fveq1 2831 |
. . . . . . . . . . 11
⊢ (x =
z → (x ‘∪dom z) = (z
‘∪dom z)) |
| 14 | 12, 13 | eqtrd 1128 |
. . . . . . . . . 10
⊢ (x =
z → (x ‘∪dom x) = (z
‘∪dom z)) |
| 15 | 14 | fveq2d 2836 |
. . . . . . . . 9
⊢ (x =
z → (H ‘(x
‘∪dom x))
= (H ‘(z ‘∪dom z))) |
| 16 | 15 | cleq2d 1112 |
. . . . . . . 8
⊢ (x =
z → (y = (H
‘(x ‘∪dom x)) ↔
y = (H
‘(z ‘∪dom z)))) |
| 17 | 9, 16 | anbi12d 476 |
. . . . . . 7
⊢ (x =
z → ((¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ↔ (¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))))) |
| 18 | | rneq 2555 |
. . . . . . . . . 10
⊢ (x =
z → ran x = ran z) |
| 19 | 18 | unieqd 1929 |
. . . . . . . . 9
⊢ (x =
z → ∪ran
x = ∪ran
z) |
| 20 | 19 | cleq2d 1112 |
. . . . . . . 8
⊢ (x =
z → (y = ∪ran x ↔ y =
∪ran z)) |
| 21 | 7, 20 | anbi12d 476 |
. . . . . . 7
⊢ (x =
z → ((Lim dom x ∧ y =
∪ran x) ↔
(Lim dom z ∧ y = ∪ran z))) |
| 22 | 4, 17, 21 | bi3ord 635 |
. . . . . 6
⊢ (x =
z → (((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x)) ↔
((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z)))) |
| 23 | 2, 22 | anbi12d 476 |
. . . . 5
⊢ (x =
z → ((w = 〈x,
y〉 ∧ ((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x))) ↔
(w = 〈z, y〉 ∧
((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z))))) |
| 24 | 23 | biexdv 936 |
. . . 4
⊢ (x =
z → (∃y(w =
〈x, y〉 ∧ ((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x))) ↔
∃y(w = 〈z,
y〉 ∧ ((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z))))) |
| 25 | 24 | cbvexv 973 |
. . 3
⊢ (∃x∃y(w =
〈x, y〉 ∧ ((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x))) ↔
∃z∃y(w =
〈z, y〉 ∧ ((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z)))) |
| 26 | 25 | biabi 1181 |
. 2
⊢ {w∣∃x∃y(w =
〈x, y〉 ∧ ((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x)))} =
{w∣∃z∃y(w =
〈z, y〉 ∧ ((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z)))} |
| 27 | | df-opab 2098 |
. 2
⊢ {〈x, y〉∣((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x))} =
{w∣∃x∃y(w =
〈x, y〉 ∧ ((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x)))} |
| 28 | | df-opab 2098 |
. 2
⊢ {〈z, y〉∣((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z))} =
{w∣∃z∃y(w =
〈z, y〉 ∧ ((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z)))} |
| 29 | 26, 27, 28 | 3eqtr4 1126 |
1
⊢ {〈x, y〉∣((x = ∅ ∧ y = A) ∨
(¬ (x = ∅ ∨ Lim dom x) ∧ y =
(H ‘(x ‘∪dom x))) ∨ (Lim dom x ∧ y =
∪ran x))} =
{〈z, y〉∣((z = ∅ ∧ y = A) ∨
(¬ (z = ∅ ∨ Lim dom z) ∧ y =
(H ‘(z ‘∪dom z))) ∨ (Lim dom z ∧ y =
∪ran z))} |