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GIF version

Theorem relun 2490
Description: The union of two relations is a relation. Compare Exercise 5 of [TakeutiZaring] p. 25.
Assertion
Ref Expression
relun (Rel (AB) ↔ (Rel A ∧ Rel B))

Proof of Theorem relun
StepHypRef Expression
1 unss 1632 . 2 ((A ⊆ (V × V) ∧ B ⊆ (V × V)) ↔ (AB) ⊆ (V × V))
2 df-rel 2425 . . 3 (Rel AA ⊆ (V × V))
3 df-rel 2425 . . 3 (Rel BB ⊆ (V × V))
42, 3anbi12i 369 . 2 ((Rel A ∧ Rel B) ↔ (A ⊆ (V × V) ∧ B ⊆ (V × V)))
5 df-rel 2425 . 2 (Rel (AB) ↔ (AB) ⊆ (V × V))
61, 4, 53bitr4r 159 1 (Rel (AB) ↔ (Rel A ∧ Rel B))
Colors of variables: wff set class
Syntax hints:   ↔ wb 127   ∧ wa 196  Vcvv 1348   ∪ cun 1485   ⊆ wss 1487   × cxp 2408  Rel wrel 2415
This theorem is referenced by:  cnvun 2642  funun 2700
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-un 1490  df-in 1491  df-ss 1492  df-rel 2425
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