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Theorem resabs1 2592
Description: Absorption law for restriction. Exercise 17 of [TakeutiZaring] p. 25.
Assertion
Ref Expression
resabs1 (BC → ((AC) ↾ B) = (AB))

Proof of Theorem resabs1
StepHypRef Expression
1 sseqin2 1656 . . . . . 6 (BC ↔ (CB) = B)
2 xpeq1 2440 . . . . . 6 ((CB) = B → ((CB) × V) = (B × V))
31, 2sylbi 174 . . . . 5 (BC → ((CB) × V) = (B × V))
4 inxp 2496 . . . . . 6 ((C × V) ∩ (B × V)) = ((CB) × (VV))
5 inidm 1649 . . . . . . 7 (VV) = V
6 xpeq2 2441 . . . . . . 7 ((VV) = V → ((CB) × (VV)) = ((CB) × V))
75, 6ax-mp 6 . . . . . 6 ((CB) × (VV)) = ((CB) × V)
84, 7eqtr2 1120 . . . . 5 ((CB) × V) = ((C × V) ∩ (B × V))
93, 8syl5reqr 1139 . . . 4 (BC → (B × V) = ((C × V) ∩ (B × V)))
109ineq2d 1645 . . 3 (BC → (A ∩ (B × V)) = (A ∩ ((C × V) ∩ (B × V))))
11 inass 1650 . . 3 ((A ∩ (C × V)) ∩ (B × V)) = (A ∩ ((C × V) ∩ (B × V)))
1210, 11syl6reqr 1143 . 2 (BC → ((A ∩ (C × V)) ∩ (B × V)) = (A ∩ (B × V)))
13 df-res 2430 . . 3 ((AC) ↾ B) = ((AC) ∩ (B × V))
14 df-res 2430 . . . 4 (AC) = (A ∩ (C × V))
1514ineq1i 1641 . . 3 ((AC) ∩ (B × V)) = ((A ∩ (C × V)) ∩ (B × V))
1613, 15eqtr 1119 . 2 ((AC) ↾ B) = ((A ∩ (C × V)) ∩ (B × V))
17 df-res 2430 . 2 (AB) = (A ∩ (B × V))
1812, 16, 173eqtr4g 1147 1 (BC → ((AC) ↾ B) = (AB))
Colors of variables: wff set class
Syntax hints:   → wi 2   = wceq 1091  Vcvv 1348   ∩ cin 1486   ⊆ wss 1487   × cxp 2408   ↾ cres 2412
This theorem is referenced by:  fun2ssres 2699  fvres 2840  tfrlem5 2953
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-opab 2098  df-xp 2424  df-rel 2425  df-res 2430
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