HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem reseq2 2576
Description: Equality theorem for restrictions.
Assertion
Ref Expression
reseq2 (A = B → (CA) = (CB))

Proof of Theorem reseq2
StepHypRef Expression
1 xpeq1 2440 . . 3 (A = B → (A × V) = (B × V))
21ineq2d 1645 . 2 (A = B → (C ∩ (A × V)) = (C ∩ (B × V)))
3 df-res 2430 . 2 (CA) = (C ∩ (A × V))
4 df-res 2430 . 2 (CB) = (C ∩ (B × V))
52, 3, 43eqtr4g 1147 1 (A = B → (CA) = (CB))
Colors of variables: wff set class
Syntax hints:   → wi 2   = wceq 1091  Vcvv 1348   ∩ cin 1486   × cxp 2408   ↾ cres 2412
This theorem is referenced by:  imaeq2 2603  funcnvres 2710  f1ococnv2 2817  fnressn 2897  fressnfv 2898  tfrlem11 2959  tfr2 2963  tz7.44-1 2966  tz7.44-2 2967  tz7.44-3 2968  rdglem1 2975  sbthlem4 3352
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-in 1491  df-opab 2098  df-xp 2424  df-res 2430
metamath.org