Proof of Theorem resieq
| Step | Hyp | Ref
| Expression |
| 1 | | breq2 2066 |
. . . . . 6
⊢ (x =
C → (B(I ↾ A)x ↔
B(I ↾ A)C)) |
| 2 | | cleq2 1110 |
. . . . . 6
⊢ (x =
C → (B = x ↔
B = C)) |
| 3 | 1, 2 | bibi12d 477 |
. . . . 5
⊢ (x =
C → ((B(I ↾ A)x ↔
B = x)
↔ (B(I ↾ A)C ↔
B = C))) |
| 4 | 3 | imbi2d 464 |
. . . 4
⊢ (x =
C → ((B ∈ A
→ (B(I ↾ A)x ↔
B = x))
↔ (B ∈ A → (B(I ↾ A)C ↔
B = C)))) |
| 5 | | visset 1350 |
. . . . . . 7
⊢ x
∈ V |
| 6 | 5 | opres 2580 |
. . . . . 6
⊢ (B
∈ A → (〈B, x〉
∈ (I ↾ A) ↔
〈B, x〉 ∈ I)) |
| 7 | | ideqg 2126 |
. . . . . . . 8
⊢ ((B
∈ A ∧ x ∈ V) → (BIx
↔ B = x)) |
| 8 | 5, 7 | mpan2 519 |
. . . . . . 7
⊢ (B
∈ A → (BIx
↔ B = x)) |
| 9 | | df-br 2063 |
. . . . . . 7
⊢ (BIx
↔ 〈B, x〉 ∈ I) |
| 10 | 8, 9 | syl5bbr 412 |
. . . . . 6
⊢ (B
∈ A → (〈B, x〉
∈ I ↔ B = x)) |
| 11 | 6, 10 | bitrd 406 |
. . . . 5
⊢ (B
∈ A → (〈B, x〉
∈ (I ↾ A) ↔ B = x)) |
| 12 | | df-br 2063 |
. . . . 5
⊢ (B(I ↾ A)x ↔
〈B, x〉 ∈ (I ↾ A)) |
| 13 | 11, 12 | syl5bb 410 |
. . . 4
⊢ (B
∈ A → (B(I ↾ A)x ↔
B = x)) |
| 14 | 4, 13 | vtoclg 1383 |
. . 3
⊢ (C
∈ A → (B ∈ A
→ (B(I ↾ A)C ↔
B = C))) |
| 15 | 14 | com12 13 |
. 2
⊢ (B
∈ A → (C ∈ A
→ (B(I ↾ A)C ↔
B = C))) |
| 16 | 15 | imp 277 |
1
⊢ ((B
∈ A ∧ C ∈ A)
→ (B(I ↾ A)C ↔
B = C)) |