HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem reueq 1326
Description: Equality theorem for restricted uniqueness quantifier.
Assertion
Ref Expression
reueq (A = B → (∃!xA φ ↔ ∃!xB φ))
Distinct variable group(s):   x,A   x,B

Proof of Theorem reueq
StepHypRef Expression
1 ax-17 925 . 2 (yA → ∀x yA)
2 ax-17 925 . 2 (yB → ∀x yB)
31, 2reueqf 1323 1 (A = B → (∃!xA φ ↔ ∃!xB φ))
Colors of variables: wff set class
Syntax hints:   → wi 2   ↔ wb 127   = wceq 1091   ∈ wcel 1092  ∃!wreu 1203
This theorem is referenced by:  reueqd 1329
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-9 799  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-eu 1009  df-cleq 1097  df-clel 1099  df-reu 1207
metamath.org