Proof of Theorem reuss
| Step | Hyp | Ref
| Expression |
| 1 | | ssel 1502 |
. . . . . . . 8
⊢ (A
⊆ B → (x ∈ A
→ x ∈ B)) |
| 2 | 1 | anim1d 432 |
. . . . . . 7
⊢ (A
⊆ B → ((x ∈ A ∧
φ) → (x ∈ B ∧
φ))) |
| 3 | 2 | 19.21aiv 943 |
. . . . . 6
⊢ (A
⊆ B → ∀x((x ∈
A ∧ φ) → (x ∈ B ∧
φ))) |
| 4 | | euimmo 1045 |
. . . . . 6
⊢ (∀x((x ∈
A ∧ φ) → (x ∈ B ∧
φ)) → (∃!x(x ∈
B ∧ φ) → ∃*x(x ∈
A ∧ φ))) |
| 5 | 3, 4 | syl 12 |
. . . . 5
⊢ (A
⊆ B → (∃!x(x ∈
B ∧ φ) → ∃*x(x ∈
A ∧ φ))) |
| 6 | | eu5 1035 |
. . . . . . 7
⊢ (∃!x(x ∈
A ∧ φ) ↔ (∃x(x ∈
A ∧ φ) ∧ ∃*x(x ∈
A ∧ φ))) |
| 7 | 6 | biimpr 134 |
. . . . . 6
⊢ ((∃x(x ∈
A ∧ φ) ∧ ∃*x(x ∈
A ∧ φ)) → ∃!x(x ∈
A ∧ φ)) |
| 8 | 7 | exp 291 |
. . . . 5
⊢ (∃x(x ∈
A ∧ φ) → (∃*x(x ∈
A ∧ φ) → ∃!x(x ∈
A ∧ φ))) |
| 9 | 5, 8 | syl9 55 |
. . . 4
⊢ (A
⊆ B → (∃x(x ∈
A ∧ φ) → (∃!x(x ∈
B ∧ φ) → ∃!x(x ∈
A ∧ φ)))) |
| 10 | 9 | imp32 281 |
. . 3
⊢ ((A
⊆ B ∧ (∃x(x ∈
A ∧ φ) ∧ ∃!x(x ∈
B ∧ φ))) → ∃!x(x ∈
A ∧ φ)) |
| 11 | | df-reu 1207 |
. . 3
⊢ (∃!x ∈ A φ ↔ ∃!x(x ∈
A ∧ φ)) |
| 12 | 10, 11 | sylibr 175 |
. 2
⊢ ((A
⊆ B ∧ (∃x(x ∈
A ∧ φ) ∧ ∃!x(x ∈
B ∧ φ))) → ∃!x ∈ A φ) |
| 13 | | df-rex 1206 |
. . 3
⊢ (∃x ∈ A φ ↔ ∃x(x ∈
A ∧ φ)) |
| 14 | | df-reu 1207 |
. . 3
⊢ (∃!x ∈ B φ ↔ ∃!x(x ∈
B ∧ φ)) |
| 15 | 13, 14 | anbi12i 369 |
. 2
⊢ ((∃x ∈ A φ ∧ ∃!x ∈ B φ) ↔ (∃x(x ∈
A ∧ φ) ∧ ∃!x(x ∈
B ∧ φ))) |
| 16 | 12, 15 | sylan2b 347 |
1
⊢ ((A
⊆ B ∧ (∃x ∈ A φ ∧ ∃!x ∈ B φ)) → ∃!x ∈ A φ) |