Proof of Theorem reuxfr
| Step | Hyp | Ref
| Expression |
| 1 | | reuxfr.2 |
. . . . . 6
⊢ (x
∈ B → ∃!y ∈ B
x = A) |
| 2 | | reurex 1337 |
. . . . . 6
⊢ (∃!y ∈ B
x = A
→ ∃y ∈ B x = A) |
| 3 | 1, 2 | syl 12 |
. . . . 5
⊢ (x
∈ B → ∃y ∈ B
x = A) |
| 4 | 3 | biantrurd 546 |
. . . 4
⊢ (x
∈ B → (φ ↔ (∃y ∈ B
x = A
∧ φ))) |
| 5 | | r19.41v 1302 |
. . . . 5
⊢ (∃y ∈ B
(x = A
∧ φ) ↔ (∃y ∈ B
x = A
∧ φ)) |
| 6 | | reuxfr.3 |
. . . . . . 7
⊢ (x =
A → (φ ↔ ψ)) |
| 7 | 6 | pm5.32i 489 |
. . . . . 6
⊢ ((x =
A ∧ φ) ↔ (x = A ∧
ψ)) |
| 8 | 7 | birex 1224 |
. . . . 5
⊢ (∃y ∈ B
(x = A
∧ φ) ↔ ∃y ∈ B
(x = A
∧ ψ)) |
| 9 | 5, 8 | bitr3 153 |
. . . 4
⊢ ((∃y ∈ B
x = A
∧ φ) ↔ ∃y ∈ B
(x = A
∧ ψ)) |
| 10 | 4, 9 | syl6bb 414 |
. . 3
⊢ (x
∈ B → (φ ↔ ∃y ∈ B
(x = A
∧ ψ))) |
| 11 | 10 | bireua 1319 |
. 2
⊢ (∃!x ∈ B φ ↔ ∃!x ∈ B
∃y ∈ B (x = A ∧ ψ)) |
| 12 | | reuxfr.1 |
. . 3
⊢ (y
∈ B → A ∈ B) |
| 13 | | df-reu 1207 |
. . . . 5
⊢ (∃!y ∈ B
x = A
↔ ∃!y(y ∈ B ∧
x = A)) |
| 14 | | eumo 1037 |
. . . . 5
⊢ (∃!y(y ∈
B ∧ x = A) →
∃*y(y ∈ B ∧
x = A)) |
| 15 | 13, 14 | sylbi 174 |
. . . 4
⊢ (∃!y ∈ B
x = A
→ ∃*y(y ∈ B ∧
x = A)) |
| 16 | 1, 15 | syl 12 |
. . 3
⊢ (x
∈ B → ∃*y(y ∈
B ∧ x = A)) |
| 17 | 12, 16 | reuxfr2 1579 |
. 2
⊢ (∃!x ∈ B
∃y ∈ B (x = A ∧ ψ)
↔ ∃!y ∈ B ψ) |
| 18 | 11, 17 | bitr 151 |
1
⊢ (∃!x ∈ B φ ↔ ∃!y ∈ B ψ) |