| Metamath Proof Explorer |
< Previous
Next >
Related theorems GIF version |
| Description: Two ways to say "A belongs to B". |
| Ref | Expression |
|---|---|
| risset | ⊢ (A ∈ B ↔ ∃x ∈ B x = A) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | exancom 736 | . 2 ⊢ (∃x(x ∈ B ∧ x = A) ↔ ∃x(x = A ∧ x ∈ B)) | |
| 2 | df-rex 1206 | . 2 ⊢ (∃x ∈ B x = A ↔ ∃x(x ∈ B ∧ x = A)) | |
| 3 | df-clel 1099 | . 2 ⊢ (A ∈ B ↔ ∃x(x = A ∧ x ∈ B)) | |
| 4 | 1, 2, 3 | 3bitr4r 159 | 1 ⊢ (A ∈ B ↔ ∃x ∈ B x = A) |
| Colors of variables: wff set class |
| Syntax hints: ↔ wb 127 ∧ wa 196 ∃wex 678 = wceq 1091 ∈ wcel 1092 ∃wrex 1202 |
| This theorem is referenced by: 0el 1720 sucel 2296 qsid 3237 zorn2 3612 negeu 4124 receu 4215 zqt 4632 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 ax-4 673 ax-5 674 ax-gen 677 |
| This theorem depends on definitions: df-bi 128 df-an 198 df-ex 679 df-clel 1099 df-rex 1206 |