Proof of Theorem sbthlem5
| Step | Hyp | Ref
| Expression |
| 1 | | sbthlem.1 |
. . . . . . . . 9
⊢ A
∈ V |
| 2 | | sbthlem.2 |
. . . . . . . . 9
⊢ D =
{x∣(x ⊆ A
∧ (g “ (B ∖ (f
“ x))) ⊆ (A ∖ x))} |
| 3 | 1, 2 | sbthlem1 3349 |
. . . . . . . 8
⊢ ∪D ⊆ (A
∖ (g “ (B ∖ (f
“ ∪D)))) |
| 4 | | difss 1596 |
. . . . . . . 8
⊢ (A
∖ (g “ (B ∖ (f
“ ∪D))))
⊆ A |
| 5 | 3, 4 | sstri 1512 |
. . . . . . 7
⊢ ∪D ⊆ A |
| 6 | | sseq2 1522 |
. . . . . . 7
⊢ (dom f
= A → (∪D ⊆ dom
f ↔ ∪D ⊆ A)) |
| 7 | 5, 6 | mpbiri 169 |
. . . . . 6
⊢ (dom f
= A → ∪D ⊆ dom
f) |
| 8 | | dfss 1493 |
. . . . . 6
⊢ (∪D ⊆ dom f
↔ ∪D =
(∪D ∩ dom
f)) |
| 9 | 7, 8 | sylib 173 |
. . . . 5
⊢ (dom f
= A → ∪D = (∪D ∩ dom f)) |
| 10 | 9 | uneq1d 1610 |
. . . 4
⊢ (dom f
= A → (∪D ∪ (A ∖ ∪D)) = ((∪D ∩ dom f)
∪ (A ∖ ∪D))) |
| 11 | | imassrn 2611 |
. . . . . . 7
⊢ (g
“ (B ∖ (f “ ∪D))) ⊆ ran g |
| 12 | 1, 2 | sbthlem3 3351 |
. . . . . . . 8
⊢ (ran g
⊆ A → (g “ (B
∖ (f “ ∪D))) = (A ∖ ∪D)) |
| 13 | 12 | sseq1d 1527 |
. . . . . . 7
⊢ (ran g
⊆ A → ((g “ (B
∖ (f “ ∪D))) ⊆ ran
g ↔ (A ∖ ∪D) ⊆ ran g)) |
| 14 | 11, 13 | mpbii 168 |
. . . . . 6
⊢ (ran g
⊆ A → (A ∖ ∪D) ⊆ ran g) |
| 15 | | dfss 1493 |
. . . . . 6
⊢ ((A
∖ ∪D)
⊆ ran g ↔ (A ∖ ∪D) = ((A ∖
∪D) ∩ ran
g)) |
| 16 | 14, 15 | sylib 173 |
. . . . 5
⊢ (ran g
⊆ A → (A ∖ ∪D) = ((A ∖
∪D) ∩ ran
g)) |
| 17 | 16 | uneq2d 1611 |
. . . 4
⊢ (ran g
⊆ A → ((∪D ∩ dom f) ∪ (A
∖ ∪D)) =
((∪D ∩ dom
f) ∪ ((A ∖ ∪D) ∩ ran g))) |
| 18 | 10, 17 | sylan9eq 1144 |
. . 3
⊢ ((dom f = A ∧ ran
g ⊆ A) → (∪D ∪ (A
∖ ∪D)) =
((∪D ∩ dom
f) ∪ ((A ∖ ∪D) ∩ ran g))) |
| 19 | | sbthlem.3 |
. . . . 5
⊢ H =
((f ↾ ∪D) ∪ (◡g
↾ (A ∖ ∪D))) |
| 20 | 19 | dmeqi 2532 |
. . . 4
⊢ dom H
= dom ((f ↾ ∪D) ∪ (◡g
↾ (A ∖ ∪D))) |
| 21 | | dmun 2536 |
. . . 4
⊢ dom ((f ↾ ∪D) ∪ (◡g
↾ (A ∖ ∪D))) = (dom (f ↾ ∪D) ∪ dom (◡g
↾ (A ∖ ∪D))) |
| 22 | | dmres 2584 |
. . . . 5
⊢ dom (f
↾ ∪D) =
(∪D ∩ dom
f) |
| 23 | | dmres 2584 |
. . . . . 6
⊢ dom (◡g
↾ (A ∖ ∪D)) = ((A ∖ ∪D) ∩ dom ◡g) |
| 24 | | df-rn 2429 |
. . . . . . . 8
⊢ ran g
= dom ◡g |
| 25 | 24 | cleqcomi 1105 |
. . . . . . 7
⊢ dom ◡g = ran
g |
| 26 | 25 | ineq2i 1642 |
. . . . . 6
⊢ ((A
∖ ∪D)
∩ dom ◡g) = ((A ∖
∪D) ∩ ran
g) |
| 27 | 23, 26 | eqtr 1119 |
. . . . 5
⊢ dom (◡g
↾ (A ∖ ∪D)) = ((A ∖ ∪D) ∩ ran g) |
| 28 | 22, 27 | uneq12i 1609 |
. . . 4
⊢ (dom (f ↾ ∪D) ∪ dom (◡g
↾ (A ∖ ∪D))) = ((∪D ∩ dom f) ∪ ((A
∖ ∪D)
∩ ran g)) |
| 29 | 20, 21, 28 | 3eqtr 1123 |
. . 3
⊢ dom H
= ((∪D ∩ dom
f) ∪ ((A ∖ ∪D) ∩ ran g)) |
| 30 | 18, 29 | syl6reqr 1143 |
. 2
⊢ ((dom f = A ∧ ran
g ⊆ A) → dom H
= (∪D ∪
(A ∖ ∪D))) |
| 31 | | ssundif 1764 |
. . 3
⊢ (∪D ⊆ A
↔ (∪D ∪
(A ∖ ∪D)) = A) |
| 32 | 5, 31 | mpbi 164 |
. 2
⊢ (∪D ∪ (A
∖ ∪D)) =
A |
| 33 | 30, 32 | syl6eq 1140 |
1
⊢ ((dom f = A ∧ ran
g ⊆ A) → dom H
= A) |