Proof of Theorem shunss
| Step | Hyp | Ref
| Expression |
| 1 | | opreq1 3006 |
. . . . . . 7
⊢ (y =
x → (y +v z) = (x
+v z)) |
| 2 | 1 | cleq2d 1112 |
. . . . . 6
⊢ (y =
x → (x = (y
+v z) ↔ x = (x
+v z))) |
| 3 | | opreq2 3007 |
. . . . . . 7
⊢ (z =
0v → (x
+v z) = (x +v
0v)) |
| 4 | 3 | cleq2d 1112 |
. . . . . 6
⊢ (z =
0v → (x = (x +v z) ↔ x =
(x +v
0v))) |
| 5 | 2, 4 | rcla42ev 1405 |
. . . . 5
⊢ (((x
∈ A ∧ 0v ∈
B) ∧ x = (x
+v 0v)) → ∃y ∈ A
∃z ∈ B x = (y +v z)) |
| 6 | | shincl.2 |
. . . . . . 7
⊢ B
∈ Sℋ |
| 7 | | sh0 5122 |
. . . . . . 7
⊢ (B
∈ Sℋ → 0v ∈ B) |
| 8 | 6, 7 | ax-mp 6 |
. . . . . 6
⊢ 0v ∈ B |
| 9 | 8 | jctr 239 |
. . . . 5
⊢ (x
∈ A → (x ∈ A ∧
0v ∈ B)) |
| 10 | | shincl.1 |
. . . . . . . 8
⊢ A
∈ Sℋ |
| 11 | 10 | shel 5120 |
. . . . . . 7
⊢ (x
∈ A → x ∈ ℋ ) |
| 12 | | ax-hvaddid 4988 |
. . . . . . 7
⊢ (x
∈ ℋ → (x
+v 0v) = x) |
| 13 | 11, 12 | syl 12 |
. . . . . 6
⊢ (x
∈ A → (x +v 0v) =
x) |
| 14 | 13 | cleqcomd 1106 |
. . . . 5
⊢ (x
∈ A → x = (x
+v 0v)) |
| 15 | 5, 9, 14 | sylanc 361 |
. . . 4
⊢ (x
∈ A → ∃y ∈ A
∃z ∈ B x = (y +v z)) |
| 16 | | opreq1 3006 |
. . . . . . 7
⊢ (y =
0v → (y
+v z) =
(0v +v z)) |
| 17 | 16 | cleq2d 1112 |
. . . . . 6
⊢ (y =
0v → (x = (y +v z) ↔ x =
(0v +v z))) |
| 18 | | opreq2 3007 |
. . . . . . 7
⊢ (z =
x → (0v
+v z) =
(0v +v x)) |
| 19 | 18 | cleq2d 1112 |
. . . . . 6
⊢ (z =
x → (x = (0v +v
z) ↔ x = (0v +v
x))) |
| 20 | 17, 19 | rcla42ev 1405 |
. . . . 5
⊢ (((0v ∈ A ∧ x ∈
B) ∧ x = (0v +v
x)) → ∃y ∈ A
∃z ∈ B x = (y +v z)) |
| 21 | | sh0 5122 |
. . . . . . 7
⊢ (A
∈ Sℋ → 0v ∈ A) |
| 22 | 10, 21 | ax-mp 6 |
. . . . . 6
⊢ 0v ∈ A |
| 23 | 22 | jctl 238 |
. . . . 5
⊢ (x
∈ B → (0v
∈ A ∧ x ∈ B)) |
| 24 | 6 | shel 5120 |
. . . . . . 7
⊢ (x
∈ B → x ∈ ℋ ) |
| 25 | | hvaddid2t 5003 |
. . . . . . 7
⊢ (x
∈ ℋ → (0v +v x) = x) |
| 26 | 24, 25 | syl 12 |
. . . . . 6
⊢ (x
∈ B → (0v
+v x) = x) |
| 27 | 26 | cleqcomd 1106 |
. . . . 5
⊢ (x
∈ B → x = (0v +v
x)) |
| 28 | 20, 23, 27 | sylanc 361 |
. . . 4
⊢ (x
∈ B → ∃y ∈ A
∃z ∈ B x = (y +v z)) |
| 29 | 15, 28 | jaoi 275 |
. . 3
⊢ ((x
∈ A ∨ x ∈ B)
→ ∃y ∈ A ∃z
∈ B x = (y
+v z)) |
| 30 | | elun 1601 |
. . 3
⊢ (x
∈ (A ∪ B) ↔ (x
∈ A ∨ x ∈ B)) |
| 31 | 10, 6 | shsel 5281 |
. . 3
⊢ (x
∈ (A +ℋ B) ↔ ∃y ∈ A
∃z ∈ B x = (y +v z)) |
| 32 | 29, 30, 31 | 3imtr4 192 |
. 2
⊢ (x
∈ (A ∪ B) → x
∈ (A +ℋ B)) |
| 33 | 32 | ssriv 1508 |
1
⊢ (A
∪ B) ⊆ (A +ℋ B) |