Proof of Theorem spansncol
| Step | Hyp | Ref
| Expression |
| 1 | | axmulcl 4068 |
. . . . . . . . . . . 12
⊢ ((y
∈ ℂ ∧ B ∈ ℂ)
→ (y · B) ∈ ℂ) |
| 2 | 1 | ancoms 334 |
. . . . . . . . . . 11
⊢ ((B
∈ ℂ ∧ y ∈ ℂ)
→ (y · B) ∈ ℂ) |
| 3 | 2 | adantll 309 |
. . . . . . . . . 10
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (y · B)
∈ ℂ) |
| 4 | 3 | a1d 14 |
. . . . . . . . 9
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (x = (y
·s (B
·s A))
→ (y · B) ∈ ℂ)) |
| 5 | | ax-hvmulass 4992 |
. . . . . . . . . . . . 13
⊢ ((y
∈ ℂ ∧ B ∈ ℂ ∧
A ∈ ℋ ) → ((y · B)
·s A) =
(y ·s
(B ·s
A))) |
| 6 | 5 | 3com13 615 |
. . . . . . . . . . . 12
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
y ∈ ℂ) → ((y · B)
·s A) =
(y ·s
(B ·s
A))) |
| 7 | 6 | 3expa 612 |
. . . . . . . . . . 11
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → ((y · B)
·s A) =
(y ·s
(B ·s
A))) |
| 8 | 7 | cleq2d 1112 |
. . . . . . . . . 10
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (x = ((y ·
B) ·s
A) ↔ x = (y
·s (B
·s A)))) |
| 9 | 8 | biimprd 136 |
. . . . . . . . 9
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (x = (y
·s (B
·s A))
→ x = ((y · B)
·s A))) |
| 10 | 4, 9 | jcad 455 |
. . . . . . . 8
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (x = (y
·s (B
·s A))
→ ((y · B) ∈ ℂ ∧ x = ((y ·
B) ·s
A)))) |
| 11 | | opreq1 3006 |
. . . . . . . . . 10
⊢ (z =
(y · B) → (z
·s A) =
((y · B) ·s A)) |
| 12 | 11 | cleq2d 1112 |
. . . . . . . . 9
⊢ (z =
(y · B) → (x =
(z ·s
A) ↔ x = ((y ·
B) ·s
A))) |
| 13 | 12 | rcla4ev 1403 |
. . . . . . . 8
⊢ (((y
· B) ∈ ℂ ∧ x = ((y ·
B) ·s
A)) → ∃z ∈ ℂ x = (z
·s A)) |
| 14 | 10, 13 | syl6 23 |
. . . . . . 7
⊢ (((A
∈ ℋ ∧ B ∈ ℂ)
∧ y ∈ ℂ) → (x = (y
·s (B
·s A))
→ ∃z ∈ ℂ x = (z
·s A))) |
| 15 | 14 | exp 291 |
. . . . . 6
⊢ ((A
∈ ℋ ∧ B ∈ ℂ)
→ (y ∈ ℂ → (x = (y
·s (B
·s A))
→ ∃z ∈ ℂ x = (z
·s A)))) |
| 16 | 15 | r19.23adv 1286 |
. . . . 5
⊢ ((A
∈ ℋ ∧ B ∈ ℂ)
→ (∃y ∈ ℂ x = (y
·s (B
·s A))
→ ∃z ∈ ℂ x = (z
·s A))) |
| 17 | 16 | 3adant3 599 |
. . . 4
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (∃y ∈ ℂ x = (y
·s (B
·s A))
→ ∃z ∈ ℂ x = (z
·s A))) |
| 18 | | divclt 4223 |
. . . . . . . . . . . . 13
⊢ (((z
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → (z / B) ∈
ℂ) |
| 19 | 18 | anasss 337 |
. . . . . . . . . . . 12
⊢ ((z
∈ ℂ ∧ (B ∈ ℂ
∧ B ≠ 0)) → (z / B) ∈
ℂ) |
| 20 | 19 | adantlr 310 |
. . . . . . . . . . 11
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (z / B) ∈
ℂ) |
| 21 | 20 | a1d 14 |
. . . . . . . . . 10
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (x = (z
·s A)
→ (z / B) ∈ ℂ)) |
| 22 | | ax-hvmulass 4992 |
. . . . . . . . . . . . . 14
⊢ (((z /
B) ∈ ℂ ∧ B ∈ ℂ ∧ A ∈ ℋ ) → (((z / B) ·
B) ·s
A) = ((z / B)
·s (B
·s A))) |
| 23 | | pm3.26 256 |
. . . . . . . . . . . . . . 15
⊢ ((B
∈ ℂ ∧ B ≠ 0) →
B ∈ ℂ) |
| 24 | 23 | adantl 305 |
. . . . . . . . . . . . . 14
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → B ∈ ℂ) |
| 25 | | pm3.27 260 |
. . . . . . . . . . . . . . 15
⊢ ((z
∈ ℂ ∧ A ∈ ℋ )
→ A ∈ ℋ ) |
| 26 | 25 | adantr 306 |
. . . . . . . . . . . . . 14
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → A ∈ ℋ ) |
| 27 | 22, 20, 24, 26 | syl3anc 629 |
. . . . . . . . . . . . 13
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (((z / B) ·
B) ·s
A) = ((z / B)
·s (B
·s A))) |
| 28 | | divcan1t 4228 |
. . . . . . . . . . . . . . . . . 18
⊢ (((B
∈ ℂ ∧ z ∈ ℂ)
∧ B ≠ 0) → ((z / B) ·
B) = z) |
| 29 | 28 | exp31 293 |
. . . . . . . . . . . . . . . . 17
⊢ (B
∈ ℂ → (z ∈ ℂ
→ (B ≠ 0 → ((z / B) ·
B) = z))) |
| 30 | 29 | com12 13 |
. . . . . . . . . . . . . . . 16
⊢ (z
∈ ℂ → (B ∈ ℂ
→ (B ≠ 0 → ((z / B) ·
B) = z))) |
| 31 | 30 | imp32 281 |
. . . . . . . . . . . . . . 15
⊢ ((z
∈ ℂ ∧ (B ∈ ℂ
∧ B ≠ 0)) → ((z / B) ·
B) = z) |
| 32 | 31 | adantlr 310 |
. . . . . . . . . . . . . 14
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → ((z / B) ·
B) = z) |
| 33 | 32 | opreq1d 3012 |
. . . . . . . . . . . . 13
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (((z / B) ·
B) ·s
A) = (z
·s A)) |
| 34 | 27, 33 | eqtr3d 1130 |
. . . . . . . . . . . 12
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → ((z / B)
·s (B
·s A)) =
(z ·s
A)) |
| 35 | 34 | cleq2d 1112 |
. . . . . . . . . . 11
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (x = ((z /
B) ·s
(B ·s
A)) ↔ x = (z
·s A))) |
| 36 | 35 | biimprd 136 |
. . . . . . . . . 10
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (x = (z
·s A)
→ x = ((z / B)
·s (B
·s A)))) |
| 37 | 21, 36 | jcad 455 |
. . . . . . . . 9
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (x = (z
·s A)
→ ((z / B) ∈ ℂ ∧ x = ((z /
B) ·s
(B ·s
A))))) |
| 38 | | opreq1 3006 |
. . . . . . . . . . 11
⊢ (y =
(z / B)
→ (y
·s (B
·s A)) =
((z / B) ·s (B ·s A))) |
| 39 | 38 | cleq2d 1112 |
. . . . . . . . . 10
⊢ (y =
(z / B)
→ (x = (y ·s (B ·s A)) ↔ x =
((z / B) ·s (B ·s A)))) |
| 40 | 39 | rcla4ev 1403 |
. . . . . . . . 9
⊢ (((z /
B) ∈ ℂ ∧ x = ((z /
B) ·s
(B ·s
A))) → ∃y ∈ ℂ x = (y
·s (B
·s A))) |
| 41 | 37, 40 | syl6 23 |
. . . . . . . 8
⊢ (((z
∈ ℂ ∧ A ∈ ℋ )
∧ (B ∈ ℂ ∧ B ≠ 0)) → (x = (z
·s A)
→ ∃y ∈ ℂ x = (y
·s (B
·s A)))) |
| 42 | 41 | exp43 301 |
. . . . . . 7
⊢ (z
∈ ℂ → (A ∈ ℋ
→ (B ∈ ℂ → (B ≠ 0 → (x = (z
·s A)
→ ∃y ∈ ℂ x = (y
·s (B
·s A))))))) |
| 43 | 42 | com4l 39 |
. . . . . 6
⊢ (A
∈ ℋ → (B ∈ ℂ
→ (B ≠ 0 → (z ∈ ℂ → (x = (z
·s A)
→ ∃y ∈ ℂ x = (y
·s (B
·s A))))))) |
| 44 | 43 | 3imp 608 |
. . . . 5
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (z ∈ ℂ → (x = (z
·s A)
→ ∃y ∈ ℂ x = (y
·s (B
·s A))))) |
| 45 | 44 | r19.23adv 1286 |
. . . 4
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (∃z ∈ ℂ x = (z
·s A)
→ ∃y ∈ ℂ x = (y
·s (B
·s A)))) |
| 46 | 17, 45 | impbid 397 |
. . 3
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (∃y ∈ ℂ x = (y
·s (B
·s A))
↔ ∃z ∈ ℂ x = (z
·s A))) |
| 47 | | ax-hvmulcl 4989 |
. . . . . 6
⊢ ((B
∈ ℂ ∧ A ∈ ℋ )
→ (B
·s A)
∈ ℋ ) |
| 48 | 47 | ancoms 334 |
. . . . 5
⊢ ((A
∈ ℋ ∧ B ∈ ℂ)
→ (B
·s A)
∈ ℋ ) |
| 49 | | elspansnt 5471 |
. . . . 5
⊢ ((B
·s A)
∈ ℋ → (x ∈ (span
‘{(B
·s A)})
↔ ∃y ∈ ℂ x = (y
·s (B
·s A)))) |
| 50 | 48, 49 | syl 12 |
. . . 4
⊢ ((A
∈ ℋ ∧ B ∈ ℂ)
→ (x ∈ (span ‘{(B ·s A)}) ↔ ∃y ∈ ℂ x = (y
·s (B
·s A)))) |
| 51 | 50 | 3adant3 599 |
. . 3
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (x ∈ (span ‘{(B ·s A)}) ↔ ∃y ∈ ℂ x = (y
·s (B
·s A)))) |
| 52 | | elspansnt 5471 |
. . . . 5
⊢ (A
∈ ℋ → (x ∈ (span
‘{A}) ↔ ∃z ∈ ℂ x = (z
·s A))) |
| 53 | 52 | adantr 306 |
. . . 4
⊢ ((A
∈ ℋ ∧ B ∈ ℂ)
→ (x ∈ (span ‘{A}) ↔ ∃z ∈ ℂ x = (z
·s A))) |
| 54 | 53 | 3adant3 599 |
. . 3
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (x ∈ (span ‘{A}) ↔ ∃z ∈ ℂ x = (z
·s A))) |
| 55 | 46, 51, 54 | 3bitr4d 424 |
. 2
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (x ∈ (span ‘{(B ·s A)}) ↔ x
∈ (span ‘{A}))) |
| 56 | 55 | cleqrd 1100 |
1
⊢ ((A
∈ ℋ ∧ B ∈ ℂ ∧
B ≠ 0) → (span ‘{(B ·s A)}) = (span ‘{A})) |