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Theorem ssconb 1598
Description: Contraposition law for subsets.
Assertion
Ref Expression
ssconb ((ACBC) → (A ⊆ (CB) ↔ B ⊆ (CA)))

Proof of Theorem ssconb
StepHypRef Expression
1 pm5.1 501 . . . . . . 7 (((xAxC) ∧ (xBxC)) → ((xAxC) ↔ (xBxC)))
2 ssel 1502 . . . . . . 7 (AC → (xAxC))
3 ssel 1502 . . . . . . 7 (BC → (xBxC))
41, 2, 3syl2an 349 . . . . . 6 ((ACBC) → ((xAxC) ↔ (xBxC)))
5 bi2.03 144 . . . . . . 7 ((xA → ¬ xB) ↔ (xB → ¬ xA))
65a1i 7 . . . . . 6 ((ACBC) → ((xA → ¬ xB) ↔ (xB → ¬ xA)))
74, 6anbi12d 476 . . . . 5 ((ACBC) → (((xAxC) ∧ (xA → ¬ xB)) ↔ ((xBxC) ∧ (xB → ¬ xA))))
8 jcab 454 . . . . 5 ((xA → (xC ∧ ¬ xB)) ↔ ((xAxC) ∧ (xA → ¬ xB)))
9 jcab 454 . . . . 5 ((xB → (xC ∧ ¬ xA)) ↔ ((xBxC) ∧ (xB → ¬ xA)))
107, 8, 93bitr4g 428 . . . 4 ((ACBC) → ((xA → (xC ∧ ¬ xB)) ↔ (xB → (xC ∧ ¬ xA))))
11 eldif 1496 . . . . 5 (x ∈ (CB) ↔ (xC ∧ ¬ xB))
1211imbi2i 160 . . . 4 ((xAx ∈ (CB)) ↔ (xA → (xC ∧ ¬ xB)))
13 eldif 1496 . . . . 5 (x ∈ (CA) ↔ (xC ∧ ¬ xA))
1413imbi2i 160 . . . 4 ((xBx ∈ (CA)) ↔ (xB → (xC ∧ ¬ xA)))
1510, 12, 143bitr4g 428 . . 3 ((ACBC) → ((xAx ∈ (CB)) ↔ (xBx ∈ (CA))))
1615bialdv 935 . 2 ((ACBC) → (∀x(xAx ∈ (CB)) ↔ ∀x(xBx ∈ (CA))))
17 dfss2 1497 . 2 (A ⊆ (CB) ↔ ∀x(xAx ∈ (CB)))
18 dfss2 1497 . 2 (B ⊆ (CA) ↔ ∀x(xBx ∈ (CA)))
1916, 17, 183bitr4g 428 1 ((ACBC) → (A ⊆ (CB) ↔ B ⊆ (CA)))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ↔ wb 127   ∧ wa 196  ∀wal 672   ∈ wcel 1092   ∖ cdif 1484   ⊆ wss 1487
This theorem is referenced by:  sbthlem1 3349  sbthlem2 3350
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-in 1491  df-ss 1492
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