Proof of Theorem ssin
| Step | Hyp | Ref
| Expression |
| 1 | | ineq12 1640 |
. . . . 5
⊢ (((A
∩ B) = A ∧ (A ∩
C) = A)
→ ((A ∩ B) ∩ (A
∩ C)) = (A ∩ A)) |
| 2 | | inindi 1654 |
. . . . 5
⊢ (A
∩ (B ∩ C)) = ((A ∩
B) ∩ (A ∩ C)) |
| 3 | 1, 2 | syl5eq 1136 |
. . . 4
⊢ (((A
∩ B) = A ∧ (A ∩
C) = A)
→ (A ∩ (B ∩ C)) =
(A ∩ A)) |
| 4 | | inidm 1649 |
. . . 4
⊢ (A
∩ A) = A |
| 5 | 3, 4 | syl6eq 1140 |
. . 3
⊢ (((A
∩ B) = A ∧ (A ∩
C) = A)
→ (A ∩ (B ∩ C)) =
A) |
| 6 | | df-ss 1492 |
. . . 4
⊢ (A
⊆ B ↔ (A ∩ B) =
A) |
| 7 | | df-ss 1492 |
. . . 4
⊢ (A
⊆ C ↔ (A ∩ C) =
A) |
| 8 | 6, 7 | anbi12i 369 |
. . 3
⊢ ((A
⊆ B ∧ A ⊆ C)
↔ ((A ∩ B) = A ∧
(A ∩ C) = A)) |
| 9 | | df-ss 1492 |
. . 3
⊢ (A
⊆ (B ∩ C) ↔ (A
∩ (B ∩ C)) = A) |
| 10 | 5, 8, 9 | 3imtr4 192 |
. 2
⊢ ((A
⊆ B ∧ A ⊆ C)
→ A ⊆ (B ∩ C)) |
| 11 | | inss1 1657 |
. . . 4
⊢ (B
∩ C) ⊆ B |
| 12 | | sstr2 1510 |
. . . 4
⊢ (A
⊆ (B ∩ C) → ((B
∩ C) ⊆ B → A
⊆ B)) |
| 13 | 11, 12 | mpi 44 |
. . 3
⊢ (A
⊆ (B ∩ C) → A
⊆ B) |
| 14 | | inss2 1658 |
. . . 4
⊢ (B
∩ C) ⊆ C |
| 15 | | sstr2 1510 |
. . . 4
⊢ (A
⊆ (B ∩ C) → ((B
∩ C) ⊆ C → A
⊆ C)) |
| 16 | 14, 15 | mpi 44 |
. . 3
⊢ (A
⊆ (B ∩ C) → A
⊆ C) |
| 17 | 13, 16 | jca 236 |
. 2
⊢ (A
⊆ (B ∩ C) → (A
⊆ B ∧ A ⊆ C)) |
| 18 | 10, 17 | impbi 139 |
1
⊢ ((A
⊆ B ∧ A ⊆ C)
↔ A ⊆ (B ∩ C)) |