Proof of Theorem suppr
| Step | Hyp | Ref
| Expression |
| 1 | | eleq1 1149 |
. . . 4
⊢ (x =
∪A →
(x ∈ P ↔ ∪A ∈
P)) |
| 2 | | breq1 2065 |
. . . . . . . . 9
⊢ (x =
∪A →
(x<P y ↔ ∪A<P y)) |
| 3 | 2 | negbid 463 |
. . . . . . . 8
⊢ (x =
∪A → (¬
x<P y ↔ ¬ ∪A<P y)) |
| 4 | 3 | imbi2d 464 |
. . . . . . 7
⊢ (x =
∪A →
((y ∈ A → ¬ x<P y) ↔ (y
∈ A → ¬ ∪A<P y))) |
| 5 | | breq2 2066 |
. . . . . . . 8
⊢ (x =
∪A →
(y<P x ↔ y<P ∪A)) |
| 6 | 5 | imbi1d 465 |
. . . . . . 7
⊢ (x =
∪A →
((y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z))) ↔ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z))))) |
| 7 | 4, 6 | anbi12d 476 |
. . . . . 6
⊢ (x =
∪A →
(((y ∈ A → ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z)))) ↔ ((y
∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))) |
| 8 | 7 | imbi2d 464 |
. . . . 5
⊢ (x =
∪A →
((y ∈ P →
((y ∈ A → ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z))))) ↔ (y
∈ P → ((y ∈
A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z))))))) |
| 9 | 8 | bialdv 935 |
. . . 4
⊢ (x =
∪A →
(∀y(y ∈ P → ((y ∈ A
→ ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z))))) ↔ ∀y(y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z))))))) |
| 10 | 1, 9 | anbi12d 476 |
. . 3
⊢ (x =
∪A →
((x ∈ P ∧
∀y(y ∈ P → ((y ∈ A
→ ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z)))))) ↔ (∪A ∈ P ∧ ∀y(y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))))) |
| 11 | 10 | cla4egv 1397 |
. 2
⊢ (∪A ∈ P → ((∪A ∈
P ∧ ∀y(y ∈ P → ((y ∈ A
→ ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))) → ∃x(x ∈
P ∧ ∀y(y ∈ P → ((y ∈ A
→ ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z)))))))) |
| 12 | | suplem1pr 3955 |
. 2
⊢ (((A
⊆ P ∧ ¬ A =
∅) ∧ ∃x(x ∈ P ∧ ∀y(y ∈
P → (y ∈ A → y<P x)))) → ∪A ∈ P) |
| 13 | | suplem2pr 3956 |
. . . . . 6
⊢ (A
⊆ P → ((y ∈
A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z))))) |
| 14 | 13 | a1d 14 |
. . . . 5
⊢ (A
⊆ P → (y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))) |
| 15 | 14 | 19.21aiv 943 |
. . . 4
⊢ (A
⊆ P → ∀y(y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))) |
| 16 | 15 | ad2antll 320 |
. . 3
⊢ (((A
⊆ P ∧ ¬ A =
∅) ∧ ∃x(x ∈ P ∧ ∀y(y ∈
P → (y ∈ A → y<P x)))) → ∀y(y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z)))))) |
| 17 | 12, 16 | jca 236 |
. 2
⊢ (((A
⊆ P ∧ ¬ A =
∅) ∧ ∃x(x ∈ P ∧ ∀y(y ∈
P → (y ∈ A → y<P x)))) → (∪A ∈ P ∧ ∀y(y ∈
P → ((y ∈ A → ¬ ∪A<P y) ∧ (y<P ∪A →
∃z(z ∈ P ∧ (z ∈ A ∧
y<P z))))))) |
| 18 | 11, 12, 17 | sylc 62 |
1
⊢ (((A
⊆ P ∧ ¬ A =
∅) ∧ ∃x(x ∈ P ∧ ∀y(y ∈
P → (y ∈ A → y<P x)))) → ∃x(x ∈
P ∧ ∀y(y ∈ P → ((y ∈ A
→ ¬ x<P y) ∧ (y<P x → ∃z(z ∈
P ∧ (z ∈ A ∧ y<P z))))))) |