Proof of Theorem symdif2
| Step | Hyp | Ref
| Expression |
| 1 | | elun 1601 |
. . 3
⊢ (x
∈ ((A ∖ B) ∪ (B
∖ A)) ↔ (x ∈ (A
∖ B) ∨ x ∈ (B
∖ A))) |
| 2 | | eldif 1496 |
. . . . 5
⊢ (x
∈ (A ∖ B) ↔ (x
∈ A ∧ ¬ x ∈ B)) |
| 3 | | pm4.13 142 |
. . . . . 6
⊢ (x
∈ A ↔ ¬ ¬ x ∈ A) |
| 4 | 3 | anbi1i 368 |
. . . . 5
⊢ ((x
∈ A ∧ ¬ x ∈ B)
↔ (¬ ¬ x ∈ A ∧ ¬ x
∈ B)) |
| 5 | 2, 4 | bitr 151 |
. . . 4
⊢ (x
∈ (A ∖ B) ↔ (¬ ¬ x ∈ A ∧
¬ x ∈ B)) |
| 6 | | eldif 1496 |
. . . . 5
⊢ (x
∈ (B ∖ A) ↔ (x
∈ B ∧ ¬ x ∈ A)) |
| 7 | | ancom 333 |
. . . . 5
⊢ ((x
∈ B ∧ ¬ x ∈ A)
↔ (¬ x ∈ A ∧ x ∈
B)) |
| 8 | 6, 7 | bitr 151 |
. . . 4
⊢ (x
∈ (B ∖ A) ↔ (¬ x ∈ A ∧
x ∈ B)) |
| 9 | 5, 8 | orbi12i 216 |
. . 3
⊢ ((x
∈ (A ∖ B) ∨ x ∈
(B ∖ A)) ↔ ((¬ ¬ x ∈ A ∧
¬ x ∈ B) ∨ (¬ x
∈ A ∧ x ∈ B))) |
| 10 | | orcom 209 |
. . . . 5
⊢ (((¬ ¬ x ∈ A ∧
¬ x ∈ B) ∨ (¬ x
∈ A ∧ x ∈ B))
↔ ((¬ x ∈ A ∧ x ∈
B) ∨ (¬ ¬ x ∈ A ∧
¬ x ∈ B))) |
| 11 | | dfbi 499 |
. . . . 5
⊢ ((¬ x ∈ A
↔ x ∈ B) ↔ ((¬ x ∈ A ∧
x ∈ B) ∨ (¬ ¬ x ∈ A ∧
¬ x ∈ B))) |
| 12 | 10, 11 | bitr4 154 |
. . . 4
⊢ (((¬ ¬ x ∈ A ∧
¬ x ∈ B) ∨ (¬ x
∈ A ∧ x ∈ B))
↔ (¬ x ∈ A ↔ x
∈ B)) |
| 13 | | nbbn 498 |
. . . 4
⊢ ((¬ x ∈ A
↔ x ∈ B) ↔ ¬ (x ∈ A
↔ x ∈ B)) |
| 14 | 12, 13 | bitr 151 |
. . 3
⊢ (((¬ ¬ x ∈ A ∧
¬ x ∈ B) ∨ (¬ x
∈ A ∧ x ∈ B))
↔ ¬ (x ∈ A ↔ x
∈ B)) |
| 15 | 1, 9, 14 | 3bitr 155 |
. 2
⊢ (x
∈ ((A ∖ B) ∪ (B
∖ A)) ↔ ¬ (x ∈ A
↔ x ∈ B)) |
| 16 | 15 | biabri 1180 |
1
⊢ ((A
∖ B) ∪ (B ∖ A)) =
{x∣ ¬ (x ∈ A
↔ x ∈ B)} |