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Theorem tfrlem3 2951
Description: Lemma for transfinite recursion. Let A be the class of "acceptable" functions. The final thing we're interested in is the union of all these acceptable functions. This lemma just changes the bound variables in A for later use.
Hypothesis
Ref Expression
tfrlem3.1 A = {f∣∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy)))}
Assertion
Ref Expression
tfrlem3 A = {g∣∃z ∈ On (g Fn z ∧ ∀yz (gy) = (G ‘(gy)))}
Distinct variable group(s):   x,y,f,g   x,z,y,g   f,G,g,x   z,G

Proof of Theorem tfrlem3
StepHypRef Expression
1 tfrlem3.1 . 2 A = {f∣∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy)))}
2 visset 1350 . . . . 5 gV
3 fneq1 2718 . . . . . . 7 (f = g → (f Fn xg Fn x))
4 fveq1 2831 . . . . . . . . 9 (f = g → (fy) = (gy))
5 reseq1 2575 . . . . . . . . . 10 (f = g → (fy) = (gy))
65fveq2d 2836 . . . . . . . . 9 (f = g → (G ‘(fy)) = (G ‘(gy)))
74, 6cleq12d 1115 . . . . . . . 8 (f = g → ((fy) = (G ‘(fy)) ↔ (gy) = (G ‘(gy))))
87biraldv 1219 . . . . . . 7 (f = g → (∀yx (fy) = (G ‘(fy)) ↔ ∀yx (gy) = (G ‘(gy))))
93, 8anbi12d 476 . . . . . 6 (f = g → ((f Fn x ∧ ∀yx (fy) = (G ‘(fy))) ↔ (g Fn x ∧ ∀yx (gy) = (G ‘(gy)))))
109birexdv 1220 . . . . 5 (f = g → (∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy))) ↔ ∃x ∈ On (g Fn x ∧ ∀yx (gy) = (G ‘(gy)))))
112, 10elab 1415 . . . 4 (g ∈ {f∣∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy)))} ↔ ∃x ∈ On (g Fn x ∧ ∀yx (gy) = (G ‘(gy))))
12 fneq2 2719 . . . . . 6 (x = z → (g Fn xg Fn z))
13 raleq 1324 . . . . . 6 (x = z → (∀yx (gy) = (G ‘(gy)) ↔ ∀yz (gy) = (G ‘(gy))))
1412, 13anbi12d 476 . . . . 5 (x = z → ((g Fn x ∧ ∀yx (gy) = (G ‘(gy))) ↔ (g Fn z ∧ ∀yz (gy) = (G ‘(gy)))))
1514cbvrexv 1334 . . . 4 (∃x ∈ On (g Fn x ∧ ∀yx (gy) = (G ‘(gy))) ↔ ∃z ∈ On (g Fn z ∧ ∀yz (gy) = (G ‘(gy))))
1611, 15bitr 151 . . 3 (g ∈ {f∣∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy)))} ↔ ∃z ∈ On (g Fn z ∧ ∀yz (gy) = (G ‘(gy))))
1716biabri 1180 . 2 {f∣∃x ∈ On (f Fn x ∧ ∀yx (fy) = (G ‘(fy)))} = {g∣∃z ∈ On (g Fn z ∧ ∀yz (gy) = (G ‘(gy)))}
181, 17eqtr 1119 1 A = {g∣∃z ∈ On (g Fn z ∧ ∀yz (gy) = (G ‘(gy)))}
Colors of variables: wff set class
Syntax hints:   ∧ wa 196   = weq 797  {cab 1090   = wceq 1091   ∈ wcel 1092  ∀wral 1201  ∃wrex 1202  Oncon0 2199   ↾ cres 2412   Fn wfn 2417   ‘cfv 2422
This theorem is referenced by:  tfrlem4 2952  tfrlem5 2953  rdglem1 2975
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-eu 1009  df-mo 1010  df-clab 1093  df-cleq 1097  df-clel 1099  df-ral 1205  df-rex 1206  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-uni 1920  df-br 2063  df-opab 2098  df-id 2125  df-xp 2424  df-rel 2425  df-cnv 2426  df-co 2427  df-dm 2428  df-rn 2429  df-res 2430  df-ima 2431  df-fun 2432  df-fn 2433  df-fv 2438
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