Proof of Theorem undom
| Step | Hyp | Ref
| Expression |
| 1 | | endomtr 3325 |
. . . . . . . . . . 11
⊢ (((A
∪ C) ≈ (x ∪ y) ∧
(x ∪ y) ≼ (B
∪ D)) → (A ∪ C)
≼ (B ∪ D)) |
| 2 | | unen 3338 |
. . . . . . . . . . . . . . 15
⊢ (((A
≈ x ∧ (C ∖ A)
≈ y) ∧ ((A ∩ (C
∖ A)) = ∅ ∧ (x ∩ y) =
∅)) → (A ∪ (C ∖ A))
≈ (x ∪ y)) |
| 3 | | undif2 1762 |
. . . . . . . . . . . . . . . 16
⊢ (A
∪ (C ∖ A)) = (A ∪
C) |
| 4 | 3 | cleqcomi 1105 |
. . . . . . . . . . . . . . 15
⊢ (A
∪ C) = (A ∪ (C
∖ A)) |
| 5 | 2, 4 | syl5eqbr 2089 |
. . . . . . . . . . . . . 14
⊢ (((A
≈ x ∧ (C ∖ A)
≈ y) ∧ ((A ∩ (C
∖ A)) = ∅ ∧ (x ∩ y) =
∅)) → (A ∪ C) ≈ (x
∪ y)) |
| 6 | | sseq2 1522 |
. . . . . . . . . . . . . . . . . 18
⊢ ((B
∩ D) = ∅ → ((x ∩ y)
⊆ (B ∩ D) ↔ (x
∩ y) ⊆ ∅)) |
| 7 | | ss0b 1726 |
. . . . . . . . . . . . . . . . . 18
⊢ ((x
∩ y) ⊆ ∅ ↔ (x ∩ y) =
∅) |
| 8 | 6, 7 | syl6bb 414 |
. . . . . . . . . . . . . . . . 17
⊢ ((B
∩ D) = ∅ → ((x ∩ y)
⊆ (B ∩ D) ↔ (x
∩ y) = ∅)) |
| 9 | | ss2in 1663 |
. . . . . . . . . . . . . . . . 17
⊢ ((x
⊆ B ∧ y ⊆ D)
→ (x ∩ y) ⊆ (B
∩ D)) |
| 10 | 8, 9 | syl5bi 183 |
. . . . . . . . . . . . . . . 16
⊢ ((B
∩ D) = ∅ → ((x ⊆ B
∧ y ⊆ D) → (x
∩ y) = ∅)) |
| 11 | 10 | imp 277 |
. . . . . . . . . . . . . . 15
⊢ (((B
∩ D) = ∅ ∧ (x ⊆ B
∧ y ⊆ D)) → (x
∩ y) = ∅) |
| 12 | | difdisj 1758 |
. . . . . . . . . . . . . . 15
⊢ (A
∩ (C ∖ A)) = ∅ |
| 13 | 11, 12 | jctil 240 |
. . . . . . . . . . . . . 14
⊢ (((B
∩ D) = ∅ ∧ (x ⊆ B
∧ y ⊆ D)) → ((A
∩ (C ∖ A)) = ∅ ∧ (x ∩ y) =
∅)) |
| 14 | 5, 13 | sylan2 346 |
. . . . . . . . . . . . 13
⊢ (((A
≈ x ∧ (C ∖ A)
≈ y) ∧ ((B ∩ D) =
∅ ∧ (x ⊆ B ∧ y
⊆ D))) → (A ∪ C)
≈ (x ∪ y)) |
| 15 | 14 | anassrs 338 |
. . . . . . . . . . . 12
⊢ ((((A
≈ x ∧ (C ∖ A)
≈ y) ∧ (B ∩ D) =
∅) ∧ (x ⊆ B ∧ y
⊆ D)) → (A ∪ C)
≈ (x ∪ y)) |
| 16 | 15 | an1rs 373 |
. . . . . . . . . . 11
⊢ ((((A
≈ x ∧ (C ∖ A)
≈ y) ∧ (x ⊆ B
∧ y ⊆ D)) ∧ (B
∩ D) = ∅) → (A ∪ C)
≈ (x ∪ y)) |
| 17 | | unss12 1630 |
. . . . . . . . . . . . 13
⊢ ((x
⊆ B ∧ y ⊆ D)
→ (x ∪ y) ⊆ (B
∪ D)) |
| 18 | | undom.1 |
. . . . . . . . . . . . . . 15
⊢ B
∈ V |
| 19 | | undom.3 |
. . . . . . . . . . . . . . 15
⊢ D
∈ V |
| 20 | 18, 19 | unex 1949 |
. . . . . . . . . . . . . 14
⊢ (B
∪ D) ∈ V |
| 21 | | ssdom2g 3312 |
. . . . . . . . . . . . . 14
⊢ ((B
∪ D) ∈ V → ((x ∪ y)
⊆ (B ∪ D) → (x
∪ y) ≼ (B ∪ D))) |
| 22 | 20, 21 | ax-mp 6 |
. . . . . . . . . . . . 13
⊢ ((x
∪ y) ⊆ (B ∪ D)
→ (x ∪ y) ≼ (B
∪ D)) |
| 23 | 17, 22 | syl 12 |
. . . . . . . . . . . 12
⊢ ((x
⊆ B ∧ y ⊆ D)
→ (x ∪ y) ≼ (B
∪ D)) |
| 24 | 23 | ad2antlr 321 |
. . . . . . . . . . 11
⊢ ((((A
≈ x ∧ (C ∖ A)
≈ y) ∧ (x ⊆ B
∧ y ⊆ D)) ∧ (B
∩ D) = ∅) → (x ∪ y)
≼ (B ∪ D)) |
| 25 | 1, 16, 24 | sylanc 361 |
. . . . . . . . . 10
⊢ ((((A
≈ x ∧ (C ∖ A)
≈ y) ∧ (x ⊆ B
∧ y ⊆ D)) ∧ (B
∩ D) = ∅) → (A ∪ C)
≼ (B ∪ D)) |
| 26 | 25 | exp 291 |
. . . . . . . . 9
⊢ (((A
≈ x ∧ (C ∖ A)
≈ y) ∧ (x ⊆ B
∧ y ⊆ D)) → ((B
∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D))) |
| 27 | 26 | an4s 390 |
. . . . . . . 8
⊢ (((A
≈ x ∧ x ⊆ B)
∧ ((C ∖ A) ≈ y
∧ y ⊆ D)) → ((B
∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D))) |
| 28 | 27 | exp 291 |
. . . . . . 7
⊢ ((A
≈ x ∧ x ⊆ B)
→ (((C ∖ A) ≈ y
∧ y ⊆ D) → ((B
∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D)))) |
| 29 | 28 | 19.23aiv 952 |
. . . . . 6
⊢ (∃x(A ≈
x ∧ x ⊆ B)
→ (((C ∖ A) ≈ y
∧ y ⊆ D) → ((B
∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D)))) |
| 30 | 29 | 19.23adv 954 |
. . . . 5
⊢ (∃x(A ≈
x ∧ x ⊆ B)
→ (∃y((C ∖ A)
≈ y ∧ y ⊆ D)
→ ((B ∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D)))) |
| 31 | 30 | imp 277 |
. . . 4
⊢ ((∃x(A ≈
x ∧ x ⊆ B)
∧ ∃y((C ∖ A)
≈ y ∧ y ⊆ D))
→ ((B ∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D))) |
| 32 | 18 | domen 3284 |
. . . 4
⊢ (A
≼ B ↔ ∃x(A ≈
x ∧ x ⊆ B)) |
| 33 | 19 | domen 3284 |
. . . 4
⊢ ((C
∖ A) ≼ D ↔ ∃y((C ∖
A) ≈ y ∧ y
⊆ D)) |
| 34 | 31, 32, 33 | syl2anb 350 |
. . 3
⊢ ((A
≼ B ∧ (C ∖ A)
≼ D) → ((B ∩ D) =
∅ → (A ∪ C) ≼ (B
∪ D))) |
| 35 | | undom.2 |
. . . . 5
⊢ C
∈ V |
| 36 | | difss 1596 |
. . . . 5
⊢ (C
∖ A) ⊆ C |
| 37 | | ssdom2g 3312 |
. . . . 5
⊢ (C
∈ V → ((C ∖ A) ⊆ C
→ (C ∖ A) ≼ C)) |
| 38 | 35, 36, 37 | mp2 43 |
. . . 4
⊢ (C
∖ A) ≼ C |
| 39 | | domtr 3320 |
. . . 4
⊢ (((C
∖ A) ≼ C ∧ C
≼ D) → (C ∖ A)
≼ D) |
| 40 | 38, 39 | mpan 518 |
. . 3
⊢ (C
≼ D → (C ∖ A)
≼ D) |
| 41 | 34, 40 | sylan2 346 |
. 2
⊢ ((A
≼ B ∧ C ≼ D)
→ ((B ∩ D) = ∅ → (A ∪ C)
≼ (B ∪ D))) |
| 42 | 41 | imp 277 |
1
⊢ (((A
≼ B ∧ C ≼ D)
∧ (B ∩ D) = ∅) → (A ∪ C)
≼ (B ∪ D)) |