Proof of Theorem unidif0
| Step | Hyp | Ref
| Expression |
| 1 | | uniun 1934 |
. . . 4
⊢ ∪((A ∖ {∅}) ∪ {∅}) = (∪(A ∖ {∅})
∪ ∪{∅}) |
| 2 | | undif1 1761 |
. . . . . 6
⊢ ((A
∖ {∅}) ∪ {∅}) = (A
∪ {∅}) |
| 3 | | uncom 1604 |
. . . . . 6
⊢ (A
∪ {∅}) = ({∅} ∪ A) |
| 4 | 2, 3 | eqtr2 1120 |
. . . . 5
⊢ ({∅} ∪ A) = ((A ∖
{∅}) ∪ {∅}) |
| 5 | 4 | unieqi 1928 |
. . . 4
⊢ ∪({∅}
∪ A) = ∪((A ∖
{∅}) ∪ {∅}) |
| 6 | | 0ex 1745 |
. . . . . . 7
⊢ ∅ ∈ V |
| 7 | 6 | unisn 1932 |
. . . . . 6
⊢ ∪{∅} =
∅ |
| 8 | 7 | uneq2i 1608 |
. . . . 5
⊢ (∪(A ∖ {∅}) ∪ ∪{∅}) = (∪(A ∖ {∅}) ∪ ∅) |
| 9 | | un0 1721 |
. . . . 5
⊢ (∪(A ∖ {∅}) ∪ ∅) = ∪(A ∖
{∅}) |
| 10 | 8, 9 | eqtr2 1120 |
. . . 4
⊢ ∪(A ∖ {∅}) = (∪(A ∖ {∅})
∪ ∪{∅}) |
| 11 | 1, 5, 10 | 3eqtr4r 1127 |
. . 3
⊢ ∪(A ∖ {∅}) = ∪({∅} ∪ A) |
| 12 | | uniun 1934 |
. . 3
⊢ ∪({∅}
∪ A) = (∪{∅} ∪ ∪A) |
| 13 | 7 | uneq1i 1607 |
. . 3
⊢ (∪{∅}
∪ ∪A) =
(∅ ∪ ∪A) |
| 14 | 11, 12, 13 | 3eqtr 1123 |
. 2
⊢ ∪(A ∖ {∅}) = (∅ ∪ ∪A) |
| 15 | | uncom 1604 |
. 2
⊢ (∅ ∪ ∪A) = (∪A ∪
∅) |
| 16 | | un0 1721 |
. 2
⊢ (∪A ∪ ∅) = ∪A |
| 17 | 14, 15, 16 | 3eqtr 1123 |
1
⊢ ∪(A ∖ {∅}) = ∪A |