Proof of Theorem zneo
| Step | Hyp | Ref
| Expression |
| 1 | | halfnz 4586 |
. . . . 5
⊢ ¬ (1 / 2) ∈ ℤ |
| 2 | | zcnt 4568 |
. . . . . . 7
⊢ (B
∈ ℤ → B ∈
ℂ) |
| 3 | | 1cn 4101 |
. . . . . . . . . . 11
⊢ 1 ∈ ℂ |
| 4 | | 2cn 4471 |
. . . . . . . . . . 11
⊢ 2 ∈ ℂ |
| 5 | | 2re 4470 |
. . . . . . . . . . . 12
⊢ 2 ∈ ℝ |
| 6 | | 2pos 4479 |
. . . . . . . . . . . 12
⊢ 0 < 2 |
| 7 | 5, 6 | gt0ne0i 4345 |
. . . . . . . . . . 11
⊢ 2 ≠ 0 |
| 8 | 3, 4, 7 | divcl 4221 |
. . . . . . . . . 10
⊢ (1 / 2) ∈ ℂ |
| 9 | | axaddcom 4070 |
. . . . . . . . . 10
⊢ ((B
∈ ℂ ∧ (1 / 2) ∈ ℂ) → (B + (1 / 2)) = ((1 / 2) + B)) |
| 10 | 8, 9 | mpan2 519 |
. . . . . . . . 9
⊢ (B
∈ ℂ → (B + (1 / 2)) = ((1 /
2) + B)) |
| 11 | 10 | opreq1d 3012 |
. . . . . . . 8
⊢ (B
∈ ℂ → ((B + (1 / 2))
− B) = (((1 / 2) + B) − B)) |
| 12 | | pncant 4161 |
. . . . . . . . 9
⊢ (((1 / 2) ∈ ℂ ∧ B ∈ ℂ) → (((1 / 2) + B) − B) =
(1 / 2)) |
| 13 | 8, 12 | mpan 518 |
. . . . . . . 8
⊢ (B
∈ ℂ → (((1 / 2) + B)
− B) = (1 / 2)) |
| 14 | 11, 13 | eqtrd 1128 |
. . . . . . 7
⊢ (B
∈ ℂ → ((B + (1 / 2))
− B) = (1 / 2)) |
| 15 | 2, 14 | syl 12 |
. . . . . 6
⊢ (B
∈ ℤ → ((B + (1 / 2))
− B) = (1 / 2)) |
| 16 | 15 | eleq1d 1155 |
. . . . 5
⊢ (B
∈ ℤ → (((B + (1 / 2))
− B) ∈ ℤ ↔ (1 / 2)
∈ ℤ)) |
| 17 | 1, 16 | mtbiri 539 |
. . . 4
⊢ (B
∈ ℤ → ¬ ((B + (1 / 2))
− B) ∈ ℤ) |
| 18 | | zsubclt 4591 |
. . . . . 6
⊢ (((B +
(1 / 2)) ∈ ℤ ∧ B ∈
ℤ) → ((B + (1 / 2)) −
B) ∈ ℤ) |
| 19 | 18 | ancoms 334 |
. . . . 5
⊢ ((B
∈ ℤ ∧ (B + (1 / 2)) ∈
ℤ) → ((B + (1 / 2)) −
B) ∈ ℤ) |
| 20 | 19 | exp 291 |
. . . 4
⊢ (B
∈ ℤ → ((B + (1 / 2)) ∈
ℤ → ((B + (1 / 2)) −
B) ∈ ℤ)) |
| 21 | 17, 20 | mtod 95 |
. . 3
⊢ (B
∈ ℤ → ¬ (B + (1 / 2))
∈ ℤ) |
| 22 | 21 | adantl 305 |
. 2
⊢ ((A
∈ ℤ ∧ B ∈ ℤ)
→ ¬ (B + (1 / 2)) ∈
ℤ) |
| 23 | | divcan3t 4251 |
. . . . . . . . . . . . . 14
⊢ (((2 ∈ ℂ ∧ A ∈ ℂ) ∧ 2 ≠ 0) → ((2
· A) / 2) = A) |
| 24 | 7, 23 | mpan2 519 |
. . . . . . . . . . . . 13
⊢ ((2 ∈ ℂ ∧ A ∈ ℂ) → ((2 · A) / 2) = A) |
| 25 | 4, 24 | mpan 518 |
. . . . . . . . . . . 12
⊢ (A
∈ ℂ → ((2 · A) / 2)
= A) |
| 26 | | axmulcl 4068 |
. . . . . . . . . . . . . . 15
⊢ ((2 ∈ ℂ ∧ B ∈ ℂ) → (2 · B) ∈ ℂ) |
| 27 | 4, 26 | mpan 518 |
. . . . . . . . . . . . . 14
⊢ (B
∈ ℂ → (2 · B) ∈
ℂ) |
| 28 | | divdistrt 4246 |
. . . . . . . . . . . . . . . . 17
⊢ ((((2 · B) ∈ ℂ ∧ 1 ∈ ℂ ∧ 2
∈ ℂ) ∧ 2 ≠ 0) → (((2 · B) + 1) / 2) = (((2 · B) / 2) + (1 / 2))) |
| 29 | 7, 28 | mpan2 519 |
. . . . . . . . . . . . . . . 16
⊢ (((2 · B) ∈ ℂ ∧ 1 ∈ ℂ ∧ 2
∈ ℂ) → (((2 · B) +
1) / 2) = (((2 · B) / 2) + (1 /
2))) |
| 30 | 4, 29 | mp3an3 641 |
. . . . . . . . . . . . . . 15
⊢ (((2 · B) ∈ ℂ ∧ 1 ∈ ℂ) →
(((2 · B) + 1) / 2) = (((2 ·
B) / 2) + (1 / 2))) |
| 31 | 3, 30 | mpan2 519 |
. . . . . . . . . . . . . 14
⊢ ((2 · B) ∈ ℂ → (((2 · B) + 1) / 2) = (((2 · B) / 2) + (1 / 2))) |
| 32 | 27, 31 | syl 12 |
. . . . . . . . . . . . 13
⊢ (B
∈ ℂ → (((2 · B) + 1)
/ 2) = (((2 · B) / 2) + (1 /
2))) |
| 33 | | divcan3t 4251 |
. . . . . . . . . . . . . . . 16
⊢ (((2 ∈ ℂ ∧ B ∈ ℂ) ∧ 2 ≠ 0) → ((2
· B) / 2) = B) |
| 34 | 7, 33 | mpan2 519 |
. . . . . . . . . . . . . . 15
⊢ ((2 ∈ ℂ ∧ B ∈ ℂ) → ((2 · B) / 2) = B) |
| 35 | 4, 34 | mpan 518 |
. . . . . . . . . . . . . 14
⊢ (B
∈ ℂ → ((2 · B) / 2)
= B) |
| 36 | 35 | opreq1d 3012 |
. . . . . . . . . . . . 13
⊢ (B
∈ ℂ → (((2 · B) / 2)
+ (1 / 2)) = (B + (1 / 2))) |
| 37 | 32, 36 | eqtrd 1128 |
. . . . . . . . . . . 12
⊢ (B
∈ ℂ → (((2 · B) + 1)
/ 2) = (B + (1 / 2))) |
| 38 | 25, 37 | cleqan12d 1116 |
. . . . . . . . . . 11
⊢ ((A
∈ ℂ ∧ B ∈ ℂ)
→ (((2 · A) / 2) = (((2
· B) + 1) / 2) ↔ A = (B + (1 /
2)))) |
| 39 | | opreq1 3006 |
. . . . . . . . . . 11
⊢ ((2 · A) = ((2 · B) + 1) → ((2 · A) / 2) = (((2 · B) + 1) / 2)) |
| 40 | 38, 39 | syl5bi 183 |
. . . . . . . . . 10
⊢ ((A
∈ ℂ ∧ B ∈ ℂ)
→ ((2 · A) = ((2 ·
B) + 1) → A = (B + (1 /
2)))) |
| 41 | | zcnt 4568 |
. . . . . . . . . 10
⊢ (A
∈ ℤ → A ∈
ℂ) |
| 42 | 40, 41, 2 | syl2an 349 |
. . . . . . . . 9
⊢ ((A
∈ ℤ ∧ B ∈ ℤ)
→ ((2 · A) = ((2 ·
B) + 1) → A = (B + (1 /
2)))) |
| 43 | 42 | imp 277 |
. . . . . . . 8
⊢ (((A
∈ ℤ ∧ B ∈ ℤ)
∧ (2 · A) = ((2 ·
B) + 1)) → A = (B + (1 /
2))) |
| 44 | 43 | eleq1d 1155 |
. . . . . . 7
⊢ (((A
∈ ℤ ∧ B ∈ ℤ)
∧ (2 · A) = ((2 ·
B) + 1)) → (A ∈ ℤ ↔ (B + (1 / 2)) ∈ ℤ)) |
| 45 | 44 | exp31 293 |
. . . . . 6
⊢ (A
∈ ℤ → (B ∈ ℤ
→ ((2 · A) = ((2 ·
B) + 1) → (A ∈ ℤ ↔ (B + (1 / 2)) ∈ ℤ)))) |
| 46 | 45 | com3l 34 |
. . . . 5
⊢ (B
∈ ℤ → ((2 · A) = ((2
· B) + 1) → (A ∈ ℤ → (A ∈ ℤ ↔ (B + (1 / 2)) ∈ ℤ)))) |
| 47 | | ibib 448 |
. . . . 5
⊢ ((A
∈ ℤ → (B + (1 / 2)) ∈
ℤ) ↔ (A ∈ ℤ →
(A ∈ ℤ ↔ (B + (1 / 2)) ∈ ℤ))) |
| 48 | 46, 47 | syl6ibr 186 |
. . . 4
⊢ (B
∈ ℤ → ((2 · A) = ((2
· B) + 1) → (A ∈ ℤ → (B + (1 / 2)) ∈ ℤ))) |
| 49 | 48 | com3r 35 |
. . 3
⊢ (A
∈ ℤ → (B ∈ ℤ
→ ((2 · A) = ((2 ·
B) + 1) → (B + (1 / 2)) ∈ ℤ))) |
| 50 | 49 | imp 277 |
. 2
⊢ ((A
∈ ℤ ∧ B ∈ ℤ)
→ ((2 · A) = ((2 ·
B) + 1) → (B + (1 / 2)) ∈ ℤ)) |
| 51 | 22, 50 | mtod 95 |
1
⊢ ((A
∈ ℤ ∧ B ∈ ℤ)
→ ¬ (2 · A) = ((2 ·
B) + 1)) |