Proof of Theorem znnenlem
| Step | Hyp | Ref
| Expression |
| 1 | | pm5.21 502 |
. 2
⊢ ((¬ y = x ∧
¬ (2 · x) = ((-2 ·
y) + 1)) → (y = x ↔ (2
· x) = ((-2 · y) + 1))) |
| 2 | | ax0re 4063 |
. . . . . . . . . . . . 13
⊢ 0 ∈ ℝ |
| 3 | | leltt 4278 |
. . . . . . . . . . . . 13
⊢ ((0 ∈ ℝ ∧ y ∈ ℝ) → (0 ≤ y ↔ ¬ y
< 0)) |
| 4 | 2, 3 | mpan 518 |
. . . . . . . . . . . 12
⊢ (y
∈ ℝ → (0 ≤ y ↔
¬ y < 0)) |
| 5 | 4 | bicon2d 404 |
. . . . . . . . . . 11
⊢ (y
∈ ℝ → (y < 0 ↔
¬ 0 ≤ y)) |
| 6 | 5 | adantr 306 |
. . . . . . . . . 10
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ (y < 0 ↔ ¬ 0 ≤
y)) |
| 7 | | ltletrt 4290 |
. . . . . . . . . . . 12
⊢ ((y
∈ ℝ ∧ 0 ∈ ℝ ∧ x ∈ ℝ) → ((y < 0 ∧ 0 ≤ x) → y <
x)) |
| 8 | 2, 7 | mp3an2 640 |
. . . . . . . . . . 11
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ ((y < 0 ∧ 0 ≤ x) → y <
x)) |
| 9 | 8 | exp3a 292 |
. . . . . . . . . 10
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ (y < 0 → (0 ≤ x → y <
x))) |
| 10 | 6, 9 | sylbird 180 |
. . . . . . . . 9
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ (¬ 0 ≤ y → (0 ≤
x → y < x))) |
| 11 | 10 | com23 32 |
. . . . . . . 8
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ (0 ≤ x → (¬ 0 ≤
y → y < x))) |
| 12 | 11 | imp3a 279 |
. . . . . . 7
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ ((0 ≤ x ∧ ¬ 0 ≤
y) → y < x)) |
| 13 | | ltnet 4282 |
. . . . . . 7
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ (y < x → ¬ y
= x)) |
| 14 | 12, 13 | syld 27 |
. . . . . 6
⊢ ((y
∈ ℝ ∧ x ∈ ℝ)
→ ((0 ≤ x ∧ ¬ 0 ≤
y) → ¬ y = x)) |
| 15 | 14 | ancoms 334 |
. . . . 5
⊢ ((x
∈ ℝ ∧ y ∈ ℝ)
→ ((0 ≤ x ∧ ¬ 0 ≤
y) → ¬ y = x)) |
| 16 | | zret 4567 |
. . . . 5
⊢ (x
∈ ℤ → x ∈
ℝ) |
| 17 | | zret 4567 |
. . . . 5
⊢ (y
∈ ℤ → y ∈
ℝ) |
| 18 | 15, 16, 17 | syl2an 349 |
. . . 4
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ ((0 ≤ x ∧ ¬ 0 ≤
y) → ¬ y = x)) |
| 19 | 18 | imp 277 |
. . 3
⊢ (((x
∈ ℤ ∧ y ∈ ℤ)
∧ (0 ≤ x ∧ ¬ 0 ≤ y)) → ¬ y = x) |
| 20 | 19 | ancoms 334 |
. 2
⊢ (((0 ≤ x ∧ ¬ 0 ≤ y) ∧ (x
∈ ℤ ∧ y ∈ ℤ))
→ ¬ y = x) |
| 21 | | zneo 4601 |
. . . . 5
⊢ ((x
∈ ℤ ∧ -y ∈ ℤ)
→ ¬ (2 · x) = ((2 ·
-y) + 1)) |
| 22 | | znegclt 4588 |
. . . . 5
⊢ (y
∈ ℤ → -y ∈
ℤ) |
| 23 | 21, 22 | sylan2 346 |
. . . 4
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ ¬ (2 · x) = ((2 ·
-y) + 1)) |
| 24 | | zcnt 4568 |
. . . . . . . 8
⊢ (y
∈ ℤ → y ∈
ℂ) |
| 25 | | 2cn 4471 |
. . . . . . . . 9
⊢ 2 ∈ ℂ |
| 26 | | mulneg12t 4198 |
. . . . . . . . 9
⊢ ((2 ∈ ℂ ∧ y ∈ ℂ) → (-2 · y) = (2 · -y)) |
| 27 | 25, 26 | mpan 518 |
. . . . . . . 8
⊢ (y
∈ ℂ → (-2 · y) = (2
· -y)) |
| 28 | 24, 27 | syl 12 |
. . . . . . 7
⊢ (y
∈ ℤ → (-2 · y) = (2
· -y)) |
| 29 | 28 | adantl 305 |
. . . . . 6
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ (-2 · y) = (2 ·
-y)) |
| 30 | 29 | opreq1d 3012 |
. . . . 5
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ ((-2 · y) + 1) = ((2 ·
-y) + 1)) |
| 31 | 30 | cleq2d 1112 |
. . . 4
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ ((2 · x) = ((-2 ·
y) + 1) ↔ (2 · x) = ((2 · -y) + 1))) |
| 32 | 23, 31 | mtbird 537 |
. . 3
⊢ ((x
∈ ℤ ∧ y ∈ ℤ)
→ ¬ (2 · x) = ((-2 ·
y) + 1)) |
| 33 | 32 | adantl 305 |
. 2
⊢ (((0 ≤ x ∧ ¬ 0 ≤ y) ∧ (x
∈ ℤ ∧ y ∈ ℤ))
→ ¬ (2 · x) = ((-2 ·
y) + 1)) |
| 34 | 1, 20, 33 | sylanc 361 |
1
⊢ (((0 ≤ x ∧ ¬ 0 ≤ y) ∧ (x
∈ ℤ ∧ y ∈ ℤ))
→ (y = x ↔ (2 · x) = ((-2 · y) + 1))) |