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Theorem nom25 310
Description: Part of Lemma 3.3(14) from "Non-Orthomodular Models..." paper.
Assertion
Ref Expression
nom25 (a == (a ^ b)) = (a ->1 b)

Proof of Theorem nom25
StepHypRef Expression
1 anass 69 . . . . . 6 ((a ^ a) ^ b) = (a ^ (a ^ b))
21ax-r1 34 . . . . 5 (a ^ (a ^ b)) = ((a ^ a) ^ b)
3 anidm 103 . . . . . 6 (a ^ a) = a
43ran 71 . . . . 5 ((a ^ a) ^ b) = (a ^ b)
52, 4ax-r2 35 . . . 4 (a ^ (a ^ b)) = (a ^ b)
6 oran3 85 . . . . . . 7 (a_|_ v b_|_) = (a ^ b)_|_
76lan 70 . . . . . 6 (a_|_ ^ (a_|_ v b_|_)) = (a_|_ ^ (a ^ b)_|_)
87ax-r1 34 . . . . 5 (a_|_ ^ (a ^ b)_|_) = (a_|_ ^ (a_|_ v b_|_))
9 a5c 113 . . . . 5 (a_|_ ^ (a_|_ v b_|_)) = a_|_
108, 9ax-r2 35 . . . 4 (a_|_ ^ (a ^ b)_|_) = a_|_
115, 102or 67 . . 3 ((a ^ (a ^ b)) v (a_|_ ^ (a ^ b)_|_)) = ((a ^ b) v a_|_)
12 ax-a2 30 . . 3 ((a ^ b) v a_|_) = (a_|_ v (a ^ b))
1311, 12ax-r2 35 . 2 ((a ^ (a ^ b)) v (a_|_ ^ (a ^ b)_|_)) = (a_|_ v (a ^ b))
14 dfb 86 . 2 (a == (a ^ b)) = ((a ^ (a ^ b)) v (a_|_ ^ (a ^ b)_|_))
15 df-i1 43 . 2 (a ->1 b) = (a_|_ v (a ^ b))
1613, 14, 153tr1 60 1 (a == (a ^ b)) = (a ->1 b)
Colors of variables: term
Syntax hints:   = wb 1  _|_wn 4   == tb 5   v wo 6   ^ wa 7   ->1 wi1 13
This theorem is referenced by:  nom35 316  nom55 328
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43
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