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Theorem u1lem5 743
Description: Lemma for unified implication study.
Assertion
Ref Expression
u1lem5 (a ->1 (a ->1 b)) = (a ->1 b)

Proof of Theorem u1lem5
StepHypRef Expression
1 df-i1 43 . 2 (a ->1 (a ->1 b)) = (a_|_ v (a ^ (a ->1 b)))
2 ancom 68 . . . . 5 (a ^ (a ->1 b)) = ((a ->1 b) ^ a)
3 u1lemaa 582 . . . . 5 ((a ->1 b) ^ a) = (a ^ b)
42, 3ax-r2 35 . . . 4 (a ^ (a ->1 b)) = (a ^ b)
54lor 66 . . 3 (a_|_ v (a ^ (a ->1 b))) = (a_|_ v (a ^ b))
6 df-i1 43 . . . 4 (a ->1 b) = (a_|_ v (a ^ b))
76ax-r1 34 . . 3 (a_|_ v (a ^ b)) = (a ->1 b)
85, 7ax-r2 35 . 2 (a_|_ v (a ^ (a ->1 b))) = (a ->1 b)
91, 8ax-r2 35 1 (a ->1 (a ->1 b)) = (a ->1 b)
Colors of variables: term
Syntax hints:   = wb 1  _|_wn 4   v wo 6   ^ wa 7   ->1 wi1 13
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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