Theorem u1lemnana 627

Description: Lemma for Sasaki implication study.

Assertion

Ref	Expression
u1lemnana	((a ->1 b)_|_ ^ a_|_) = 0

Proof of Theorem u1lemnana

Step	Hyp	Ref	Expression
1		anor3 82	. . 3 ((a ->1 b)_|_ ^ a_|_) = ((a ->1 b) v a)_|_
2		u1lemoa 602	. . . 4 ((a ->1 b) v a) = 1
3	2	ax-r4 36	. . 3 ((a ->1 b) v a)_|_ = 1_|_
4	1, 3	ax-r2 35	. 2 ((a ->1 b)_|_ ^ a_|_) = 1_|_
5		df-f 41	. . 3 0 = 1_|_
6	5	ax-r1 34	. 2 1_|_ = 0
7	4, 6	ax-r2 35	1 ((a ->1 b)_|_ ^ a_|_) = 0

Syntax hints:   = wb 1  _|_wn 4   v wo 6   ^ wa 7  1wt 9  0wf 10   ->1 wi1 13

This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37

This theorem depends on definitions:  df-a 39  df-t 40  df-f 41  df-i1 43

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