[Lattice L46-7]Home PageHome Quantum Logic Explorer < Previous   Next >
Related theorems
GIF version

Theorem 3oa2 1004
Description: Alternate form for the 3-variable orthoarguesion law.
Assertion
Ref Expression
3oa2 ((a1 c) ∩ (((a1 c) ∩ (b1 c)) ∪ ((a1 c) ∩ (b1 c)))) ≤ (b1 c)

Proof of Theorem 3oa2
StepHypRef Expression
1 ax-3oa 978 . 2 (((a1 c) →1 c) ∩ (((a1 c) ∩ (b1 c)) ∪ (((a1 c) →1 c) ∩ ((b1 c) →1 c)))) ≤ ((b1 c) →1 c)
2 u1lem11 762 . . 3 ((a1 c) →1 c) = (a1 c)
3 ax-a2 30 . . . 4 (((a1 c) ∩ (b1 c)) ∪ (((a1 c) →1 c) ∩ ((b1 c) →1 c))) = ((((a1 c) →1 c) ∩ ((b1 c) →1 c)) ∪ ((a1 c) ∩ (b1 c)))
4 u1lem11 762 . . . . . 6 ((b1 c) →1 c) = (b1 c)
52, 42an 72 . . . . 5 (((a1 c) →1 c) ∩ ((b1 c) →1 c)) = ((a1 c) ∩ (b1 c))
65ax-r5 37 . . . 4 ((((a1 c) →1 c) ∩ ((b1 c) →1 c)) ∪ ((a1 c) ∩ (b1 c))) = (((a1 c) ∩ (b1 c)) ∪ ((a1 c) ∩ (b1 c)))
73, 6ax-r2 35 . . 3 (((a1 c) ∩ (b1 c)) ∪ (((a1 c) →1 c) ∩ ((b1 c) →1 c))) = (((a1 c) ∩ (b1 c)) ∪ ((a1 c) ∩ (b1 c)))
82, 72an 72 . 2 (((a1 c) →1 c) ∩ (((a1 c) ∩ (b1 c)) ∪ (((a1 c) →1 c) ∩ ((b1 c) →1 c)))) = ((a1 c) ∩ (((a1 c) ∩ (b1 c)) ∪ ((a1 c) ∩ (b1 c))))
91, 8, 4le3tr2 133 1 ((a1 c) ∩ (((a1 c) ∩ (b1 c)) ∪ ((a1 c) ∩ (b1 c)))) ≤ (b1 c)
Colors of variables: term
Syntax hints:   ≤ wle 2   wn 4   ∪ wo 6   ∩ wa 7   →1 wi1 13
This theorem is referenced by:  3oa3 1005
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421  ax-3oa 978
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123  df-c1 124  df-c2 125
metamath.org