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Theorem 3vded22 800
Description: A 3-variable theorem. Experiment with weak deduction theorem.
Hypotheses
Ref Expression
3vded22.1 c ≤ ( C (a, b) ∪ C (c, b))
3vded22.2 ca
3vded22.3 c ≤ (a0 b)
Assertion
Ref Expression
3vded22 cb

Proof of Theorem 3vded22
StepHypRef Expression
1 3vded22.1 . . . 4 c ≤ ( C (a, b) ∪ C (c, b))
2 df-cmtr 126 . . . . . . 7 C (a, b) = (((ab) ∪ (ab )) ∪ ((ab) ∪ (ab )))
3 or4 77 . . . . . . 7 (((ab) ∪ (ab )) ∪ ((ab) ∪ (ab ))) = (((ab) ∪ (ab)) ∪ ((ab ) ∪ (ab )))
42, 3ax-r2 35 . . . . . 6 C (a, b) = (((ab) ∪ (ab)) ∪ ((ab ) ∪ (ab )))
5 lear 153 . . . . . . . 8 (ab) ≤ b
6 lear 153 . . . . . . . 8 (ab) ≤ b
75, 6lel2or 162 . . . . . . 7 ((ab) ∪ (ab)) ≤ b
8 3vded22.2 . . . . . . . . . 10 ca
98lecon 146 . . . . . . . . 9 ac
109leran 145 . . . . . . . 8 (ab ) ≤ (cb )
1110lelor 158 . . . . . . 7 ((ab ) ∪ (ab )) ≤ ((ab ) ∪ (cb ))
127, 11le2or 160 . . . . . 6 (((ab) ∪ (ab)) ∪ ((ab ) ∪ (ab ))) ≤ (b ∪ ((ab ) ∪ (cb )))
134, 12bltr 130 . . . . 5 C (a, b) ≤ (b ∪ ((ab ) ∪ (cb )))
14 df-cmtr 126 . . . . . . 7 C (c, b) = (((cb) ∪ (cb )) ∪ ((cb) ∪ (cb )))
15 or4 77 . . . . . . 7 (((cb) ∪ (cb )) ∪ ((cb) ∪ (cb ))) = (((cb) ∪ (cb)) ∪ ((cb ) ∪ (cb )))
1614, 15ax-r2 35 . . . . . 6 C (c, b) = (((cb) ∪ (cb)) ∪ ((cb ) ∪ (cb )))
17 lear 153 . . . . . . . 8 (cb) ≤ b
18 lear 153 . . . . . . . 8 (cb) ≤ b
1917, 18lel2or 162 . . . . . . 7 ((cb) ∪ (cb)) ≤ b
208leran 145 . . . . . . . 8 (cb ) ≤ (ab )
2120leror 144 . . . . . . 7 ((cb ) ∪ (cb )) ≤ ((ab ) ∪ (cb ))
2219, 21le2or 160 . . . . . 6 (((cb) ∪ (cb)) ∪ ((cb ) ∪ (cb ))) ≤ (b ∪ ((ab ) ∪ (cb )))
2316, 22bltr 130 . . . . 5 C (c, b) ≤ (b ∪ ((ab ) ∪ (cb )))
2413, 23le2or 160 . . . 4 ( C (a, b) ∪ C (c, b)) ≤ ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb ))))
251, 24letr 129 . . 3 c ≤ ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb ))))
26 df-i0 42 . . . . 5 ((a0 b) →0 (c2 b)) = ((a0 b) ∪ (c2 b))
27 or12 73 . . . . . 6 ((ab ) ∪ (b ∪ (cb ))) = (b ∪ ((ab ) ∪ (cb )))
28 df-i0 42 . . . . . . . . 9 (a0 b) = (ab)
2928ax-r4 36 . . . . . . . 8 (a0 b) = (ab)
30 anor1 80 . . . . . . . . 9 (ab ) = (ab)
3130ax-r1 34 . . . . . . . 8 (ab) = (ab )
3229, 31ax-r2 35 . . . . . . 7 (a0 b) = (ab )
33 df-i2 44 . . . . . . 7 (c2 b) = (b ∪ (cb ))
3432, 332or 67 . . . . . 6 ((a0 b) ∪ (c2 b)) = ((ab ) ∪ (b ∪ (cb )))
35 oridm 102 . . . . . 6 ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb )))) = (b ∪ ((ab ) ∪ (cb )))
3627, 34, 353tr1 60 . . . . 5 ((a0 b) ∪ (c2 b)) = ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb ))))
3726, 36ax-r2 35 . . . 4 ((a0 b) →0 (c2 b)) = ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb ))))
3837ax-r1 34 . . 3 ((b ∪ ((ab ) ∪ (cb ))) ∪ (b ∪ ((ab ) ∪ (cb )))) = ((a0 b) →0 (c2 b))
3925, 38lbtr 131 . 2 c ≤ ((a0 b) →0 (c2 b))
40 3vded22.3 . 2 c ≤ (a0 b)
4139, 403vded21 799 1 cb
Colors of variables: term
Syntax hints:   ≤ wle 2   wn 4   ∪ wo 6   ∩ wa 7   →0 wi0 12   →2 wi2 14   C wcmtr 28
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i0 42  df-i2 44  df-le1 122  df-le2 123  df-c1 124  df-c2 125  df-cmtr 126
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