Proof of Theorem 3vth2
| Step | Hyp | Ref
| Expression |
| 1 | | 3vth1 786 |
. . 3
((a →2 b) ∩ (b
∪ c)⊥ ) ≤ (a →2 c) |
| 2 | | lear 153 |
. . 3
((a →2 b) ∩ (b
∪ c)⊥ ) ≤ (b ∪ c)⊥ |
| 3 | 1, 2 | ler2an 165 |
. 2
((a →2 b) ∩ (b
∪ c)⊥ ) ≤
((a →2 c) ∩ (b
∪ c)⊥ ) |
| 4 | | ax-a2 30 |
. . . . . 6
(b ∪ c) = (c ∪
b) |
| 5 | 4 | ax-r4 36 |
. . . . 5
(b ∪ c)⊥ = (c ∪ b)⊥ |
| 6 | 5 | lan 70 |
. . . 4
((a →2 c) ∩ (b
∪ c)⊥ ) = ((a →2 c) ∩ (c
∪ b)⊥ ) |
| 7 | | 3vth1 786 |
. . . 4
((a →2 c) ∩ (c
∪ b)⊥ ) ≤ (a →2 b) |
| 8 | 6, 7 | bltr 130 |
. . 3
((a →2 c) ∩ (b
∪ c)⊥ ) ≤ (a →2 b) |
| 9 | | lear 153 |
. . 3
((a →2 c) ∩ (b
∪ c)⊥ ) ≤ (b ∪ c)⊥ |
| 10 | 8, 9 | ler2an 165 |
. 2
((a →2 c) ∩ (b
∪ c)⊥ ) ≤
((a →2 b) ∩ (b
∪ c)⊥ ) |
| 11 | 3, 10 | lebi 137 |
1
((a →2 b) ∩ (b
∪ c)⊥ ) = ((a →2 c) ∩ (b
∪ c)⊥ ) |