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Theorem cancellem 873
Description: Lemma for cancellation law eliminating →1 consequent.
Hypothesis
Ref Expression
cancel.1 ((d ∪ (a1 c)) →1 c) = ((d ∪ (b1 c)) →1 c)
Assertion
Ref Expression
cancellem (d ∪ (a1 c)) ≤ (d ∪ (b1 c))

Proof of Theorem cancellem
StepHypRef Expression
1 i1abs 783 . . 3 (((d ∪ (a1 c)) →1 c) ∪ ((d ∪ (a1 c)) ∩ c)) = (d ∪ (a1 c))
21ax-r1 34 . 2 (d ∪ (a1 c)) = (((d ∪ (a1 c)) →1 c) ∪ ((d ∪ (a1 c)) ∩ c))
3 leo 150 . . . . 5 (d ∪ (b1 c)) ≤ ((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c))
4 cancel.1 . . . . . . 7 ((d ∪ (a1 c)) →1 c) = ((d ∪ (b1 c)) →1 c)
5 df-i1 43 . . . . . . 7 ((d ∪ (b1 c)) →1 c) = ((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c))
64, 5ax-r2 35 . . . . . 6 ((d ∪ (a1 c)) →1 c) = ((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c))
76ax-r1 34 . . . . 5 ((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c)) = ((d ∪ (a1 c)) →1 c)
83, 7lbtr 131 . . . 4 (d ∪ (b1 c)) ≤ ((d ∪ (a1 c)) →1 c)
98lecon2 148 . . 3 ((d ∪ (a1 c)) →1 c) ≤ (d ∪ (b1 c))
10 leor 151 . . . . . 6 ((d ∪ (a1 c)) ∩ c) ≤ ((d ∪ (a1 c)) ∪ ((d ∪ (a1 c)) ∩ c))
11 df-i1 43 . . . . . . . 8 ((d ∪ (a1 c)) →1 c) = ((d ∪ (a1 c)) ∪ ((d ∪ (a1 c)) ∩ c))
1211ax-r1 34 . . . . . . 7 ((d ∪ (a1 c)) ∪ ((d ∪ (a1 c)) ∩ c)) = ((d ∪ (a1 c)) →1 c)
1312, 4ax-r2 35 . . . . . 6 ((d ∪ (a1 c)) ∪ ((d ∪ (a1 c)) ∩ c)) = ((d ∪ (b1 c)) →1 c)
1410, 13lbtr 131 . . . . 5 ((d ∪ (a1 c)) ∩ c) ≤ ((d ∪ (b1 c)) →1 c)
15 lear 153 . . . . 5 ((d ∪ (a1 c)) ∩ c) ≤ c
1614, 15ler2an 165 . . . 4 ((d ∪ (a1 c)) ∩ c) ≤ (((d ∪ (b1 c)) →1 c) ∩ c)
17 coman2 178 . . . . . . 7 ((d ∪ (b1 c)) ∩ c) C c
18 coman1 177 . . . . . . . 8 ((d ∪ (b1 c)) ∩ c) C (d ∪ (b1 c))
1918comcom2 175 . . . . . . 7 ((d ∪ (b1 c)) ∩ c) C (d ∪ (b1 c))
2017, 19fh2rc 462 . . . . . 6 (((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c)) ∩ c) = (((d ∪ (b1 c))c) ∪ (((d ∪ (b1 c)) ∩ c) ∩ c))
215ran 71 . . . . . 6 (((d ∪ (b1 c)) →1 c) ∩ c) = (((d ∪ (b1 c)) ∪ ((d ∪ (b1 c)) ∩ c)) ∩ c)
22 id 58 . . . . . 6 (((d ∪ (b1 c))c) ∪ (((d ∪ (b1 c)) ∩ c) ∩ c)) = (((d ∪ (b1 c))c) ∪ (((d ∪ (b1 c)) ∩ c) ∩ c))
2320, 21, 223tr1 60 . . . . 5 (((d ∪ (b1 c)) →1 c) ∩ c) = (((d ∪ (b1 c))c) ∪ (((d ∪ (b1 c)) ∩ c) ∩ c))
24 leao4 157 . . . . . . . 8 ((d ∩ (bc) ) ∩ (bc)) ≤ (b ∪ (bc))
2524lerr 142 . . . . . . 7 ((d ∩ (bc) ) ∩ (bc)) ≤ (d ∪ (b ∪ (bc)))
26 df-i1 43 . . . . . . . . . . . 12 (b1 c) = (b ∪ (bc))
2726lor 66 . . . . . . . . . . 11 (d ∪ (b1 c)) = (d ∪ (b ∪ (bc)))
2827ax-r4 36 . . . . . . . . . 10 (d ∪ (b1 c)) = (d ∪ (b ∪ (bc)))
29 an12 74 . . . . . . . . . . . 12 (b ∩ (d ∩ (bc) )) = (d ∩ (b ∩ (bc) ))
30 anor1 80 . . . . . . . . . . . . 13 (b ∩ (bc) ) = (b ∪ (bc))
3130lan 70 . . . . . . . . . . . 12 (d ∩ (b ∩ (bc) )) = (d ∩ (b ∪ (bc)) )
32 anor3 82 . . . . . . . . . . . 12 (d ∩ (b ∪ (bc)) ) = (d ∪ (b ∪ (bc)))
3329, 31, 323tr 62 . . . . . . . . . . 11 (b ∩ (d ∩ (bc) )) = (d ∪ (b ∪ (bc)))
3433ax-r1 34 . . . . . . . . . 10 (d ∪ (b ∪ (bc))) = (b ∩ (d ∩ (bc) ))
35 ancom 68 . . . . . . . . . 10 (b ∩ (d ∩ (bc) )) = ((d ∩ (bc) ) ∩ b)
3628, 34, 353tr 62 . . . . . . . . 9 (d ∪ (b1 c)) = ((d ∩ (bc) ) ∩ b)
3736ran 71 . . . . . . . 8 ((d ∪ (b1 c))c) = (((d ∩ (bc) ) ∩ b) ∩ c)
38 anass 69 . . . . . . . 8 (((d ∩ (bc) ) ∩ b) ∩ c) = ((d ∩ (bc) ) ∩ (bc))
3937, 38ax-r2 35 . . . . . . 7 ((d ∪ (b1 c))c) = ((d ∩ (bc) ) ∩ (bc))
4025, 39, 27le3tr1 132 . . . . . 6 ((d ∪ (b1 c))c) ≤ (d ∪ (b1 c))
41 lea 152 . . . . . . 7 ((d ∪ (b1 c)) ∩ c) ≤ (d ∪ (b1 c))
4241lel 143 . . . . . 6 (((d ∪ (b1 c)) ∩ c) ∩ c) ≤ (d ∪ (b1 c))
4340, 42lel2or 162 . . . . 5 (((d ∪ (b1 c))c) ∪ (((d ∪ (b1 c)) ∩ c) ∩ c)) ≤ (d ∪ (b1 c))
4423, 43bltr 130 . . . 4 (((d ∪ (b1 c)) →1 c) ∩ c) ≤ (d ∪ (b1 c))
4516, 44letr 129 . . 3 ((d ∪ (a1 c)) ∩ c) ≤ (d ∪ (b1 c))
469, 45lel2or 162 . 2 (((d ∪ (a1 c)) →1 c) ∪ ((d ∪ (a1 c)) ∩ c)) ≤ (d ∪ (b1 c))
472, 46bltr 130 1 (d ∪ (a1 c)) ≤ (d ∪ (b1 c))
Colors of variables: term
Syntax hints:   = wb 1   ≤ wle 2   wn 4   ∪ wo 6   ∩ wa 7   →1 wi1 13
This theorem is referenced by:  cancel 874
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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