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GIF version

Theorem comi1 691
Description: Commutation expressed with →1 .
Hypothesis
Ref Expression
comi1.1 a C b
Assertion
Ref Expression
comi1 b ≤ (a1 b)

Proof of Theorem comi1
StepHypRef Expression
1 ancom 68 . . . . 5 (ba) = (ab)
21ax-r5 37 . . . 4 ((ba) ∪ (ba )) = ((ab) ∪ (ba ))
3 ax-a2 30 . . . 4 ((ab) ∪ (ba )) = ((ba ) ∪ (ab))
42, 3ax-r2 35 . . 3 ((ba) ∪ (ba )) = ((ba ) ∪ (ab))
5 lear 153 . . . 4 (ba ) ≤ a
65leror 144 . . 3 ((ba ) ∪ (ab)) ≤ (a ∪ (ab))
74, 6bltr 130 . 2 ((ba) ∪ (ba )) ≤ (a ∪ (ab))
8 comi1.1 . . . 4 a C b
98comcom 435 . . 3 b C a
109df-c2 125 . 2 b = ((ba) ∪ (ba ))
11 df-i1 43 . 2 (a1 b) = (a ∪ (ab))
127, 10, 11le3tr1 132 1 b ≤ (a1 b)
Colors of variables: term
Syntax hints:   ≤ wle 2   C wc 3   wn 4   ∪ wo 6   ∩ wa 7   →1 wi1 13
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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