Proof of Theorem comi31
| Step | Hyp | Ref
| Expression |
| 1 | | coman1 177 |
. . . . . . 7
(a⊥ ∩ b) C a⊥ |
| 2 | 1 | comcom 435 |
. . . . . 6
a⊥ C (a⊥ ∩ b) |
| 3 | 2 | comcom2 175 |
. . . . 5
a⊥ C (a⊥ ∩ b)⊥ |
| 4 | 3 | comcom5 440 |
. . . 4
a C (a⊥ ∩ b) |
| 5 | | coman1 177 |
. . . . . . 7
(a⊥ ∩ b⊥ ) C a⊥ |
| 6 | 5 | comcom 435 |
. . . . . 6
a⊥ C (a⊥ ∩ b⊥ ) |
| 7 | 6 | comcom2 175 |
. . . . 5
a⊥ C (a⊥ ∩ b⊥ )⊥ |
| 8 | 7 | comcom5 440 |
. . . 4
a C (a⊥ ∩ b⊥ ) |
| 9 | 4, 8 | com2or 465 |
. . 3
a C ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) |
| 10 | | coman1 177 |
. . . 4
(a ∩ (a⊥ ∪ b)) C a |
| 11 | 10 | comcom 435 |
. . 3
a C (a ∩ (a⊥ ∪ b)) |
| 12 | 9, 11 | com2or 465 |
. 2
a C (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ (a ∩ (a⊥ ∪ b))) |
| 13 | | df-i3 45 |
. . 3
(a →3 b) = (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ (a ∩ (a⊥ ∪ b))) |
| 14 | 13 | ax-r1 34 |
. 2
(((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ (a ∩ (a⊥ ∪ b))) = (a
→3 b) |
| 15 | 12, 14 | cbtr 174 |
1
a C (a →3 b) |