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Theorem gsth 471
Description: Gudder-Schelp's Theorem. Beran, p. 262, Th. 4.1.
Hypotheses
Ref Expression
gsth.1 a C b
gsth.2 b C c
gsth.3 a C (bc)
Assertion
Ref Expression
gsth (ab) C c

Proof of Theorem gsth
StepHypRef Expression
1 gsth.2 . . . . . 6 b C c
2 gsth.1 . . . . . . 7 a C b
32comcom 435 . . . . . 6 b C a
41, 3fh4rc 464 . . . . 5 ((ab) ∪ c) = ((ac) ∩ (bc))
51comcom2 175 . . . . . 6 b C c
65, 3fh4rc 464 . . . . 5 ((ab) ∪ c ) = ((ac ) ∩ (bc ))
74, 62an 72 . . . 4 (((ab) ∪ c) ∩ ((ab) ∪ c )) = (((ac) ∩ (bc)) ∩ ((ac ) ∩ (bc )))
8 an4 78 . . . 4 (((ac) ∩ (bc)) ∩ ((ac ) ∩ (bc ))) = (((ac) ∩ (ac )) ∩ ((bc) ∩ (bc )))
9 an32 76 . . . . 5 (((ac) ∩ (ac )) ∩ b) = (((ac) ∩ b) ∩ (ac ))
101comd 438 . . . . . 6 b = ((bc) ∩ (bc ))
1110lan 70 . . . . 5 (((ac) ∩ (ac )) ∩ b) = (((ac) ∩ (ac )) ∩ ((bc) ∩ (bc )))
123, 1fh1r 455 . . . . . . 7 ((ac) ∩ b) = ((ab) ∪ (cb))
1312ran 71 . . . . . 6 (((ac) ∩ b) ∩ (ac )) = (((ab) ∪ (cb)) ∩ (ac ))
14 lea 152 . . . . . . . . . 10 (ab) ≤ a
15 leo 150 . . . . . . . . . 10 a ≤ (ac )
1614, 15letr 129 . . . . . . . . 9 (ab) ≤ (ac )
1716lecom 172 . . . . . . . 8 (ab) C (ac )
1817comcom 435 . . . . . . 7 (ac ) C (ab)
19 gsth.3 . . . . . . . . . . 11 a C (bc)
2019comcom 435 . . . . . . . . . 10 (bc) C a
21 coman2 178 . . . . . . . . . . 11 (bc) C c
2221comcom2 175 . . . . . . . . . 10 (bc) C c
2320, 22com2or 465 . . . . . . . . 9 (bc) C (ac )
2423comcom 435 . . . . . . . 8 (ac ) C (bc)
25 ancom 68 . . . . . . . 8 (bc) = (cb)
2624, 25cbtr 174 . . . . . . 7 (ac ) C (cb)
2718, 26fh1r 455 . . . . . 6 (((ab) ∪ (cb)) ∩ (ac )) = (((ab) ∩ (ac )) ∪ ((cb) ∩ (ac )))
2816df2le2 128 . . . . . . . 8 ((ab) ∩ (ac )) = (ab)
29 ancom 68 . . . . . . . . . 10 (cb) = (bc)
3029ran 71 . . . . . . . . 9 ((cb) ∩ (ac )) = ((bc) ∩ (ac ))
3120, 22fh1 451 . . . . . . . . 9 ((bc) ∩ (ac )) = (((bc) ∩ a) ∪ ((bc) ∩ c ))
32 anass 69 . . . . . . . . . . . 12 ((bc) ∩ c ) = (b ∩ (cc ))
33 dff 93 . . . . . . . . . . . . . 14 0 = (cc )
3433ax-r1 34 . . . . . . . . . . . . 13 (cc ) = 0
3534lan 70 . . . . . . . . . . . 12 (b ∩ (cc )) = (b ∩ 0)
36 an0 100 . . . . . . . . . . . 12 (b ∩ 0) = 0
3732, 35, 363tr 62 . . . . . . . . . . 11 ((bc) ∩ c ) = 0
3837lor 66 . . . . . . . . . 10 (((bc) ∩ a) ∪ ((bc) ∩ c )) = (((bc) ∩ a) ∪ 0)
39 or0 94 . . . . . . . . . 10 (((bc) ∩ a) ∪ 0) = ((bc) ∩ a)
4038, 39ax-r2 35 . . . . . . . . 9 (((bc) ∩ a) ∪ ((bc) ∩ c )) = ((bc) ∩ a)
4130, 31, 403tr 62 . . . . . . . 8 ((cb) ∩ (ac )) = ((bc) ∩ a)
4228, 412or 67 . . . . . . 7 (((ab) ∩ (ac )) ∪ ((cb) ∩ (ac ))) = ((ab) ∪ ((bc) ∩ a))
43 ax-a2 30 . . . . . . 7 ((ab) ∪ ((bc) ∩ a)) = (((bc) ∩ a) ∪ (ab))
44 ancom 68 . . . . . . . . 9 ((bc) ∩ a) = (a ∩ (bc))
45 lea 152 . . . . . . . . . 10 (bc) ≤ b
4645lelan 159 . . . . . . . . 9 (a ∩ (bc)) ≤ (ab)
4744, 46bltr 130 . . . . . . . 8 ((bc) ∩ a) ≤ (ab)
4847df-le2 123 . . . . . . 7 (((bc) ∩ a) ∪ (ab)) = (ab)
4942, 43, 483tr 62 . . . . . 6 (((ab) ∩ (ac )) ∪ ((cb) ∩ (ac ))) = (ab)
5013, 27, 493tr 62 . . . . 5 (((ac) ∩ b) ∩ (ac )) = (ab)
519, 11, 503tr2 61 . . . 4 (((ac) ∩ (ac )) ∩ ((bc) ∩ (bc ))) = (ab)
527, 8, 513tr 62 . . 3 (((ab) ∪ c) ∩ ((ab) ∪ c )) = (ab)
5352ax-r1 34 . 2 (ab) = (((ab) ∪ c) ∩ ((ab) ∪ c ))
5453df2c1 450 1 (ab) C c
Colors of variables: term
Syntax hints:   C wc 3   wn 4   ∪ wo 6   ∩ wa 7  0wf 10
This theorem is referenced by:  gsth2 472
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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