Statement List for Quantum Logic Explorer - 201-300 - Page 3 of 11
| Type | Label | Description |
| Statement |
| |
| Theorem | wcon3 201 |
Weak contraposition.
|
| (a⊥ ≡ b) = 1
⇒ (a ≡
b⊥ ) = 1 |
| |
| Theorem | wlem3.1 202 |
Weak analogue to lemma used in proof of Th. 3.1 of Pavicic 1993.
|
| (a
∪ b) = b
& (b⊥ ∪ a) = 1
⇒ (a ≡
b) = 1 |
| |
| Theorem | woml 203 |
Theorem structurally similar to orthomodular law but does not require
R3.
|
| ((a ∪ (a⊥ ∩ (a ∪ b)))
≡ (a ∪ b)) = 1 |
| |
| Theorem | wwoml2 204 |
Weak orthomodular law.
|
| a
≤ b
⇒ ((a ∪
(a⊥ ∩ b)) ≡ b)
= 1 |
| |
| Theorem | wwoml3 205 |
Weak orthomodular law.
|
| a
≤ b
& (b ∩ a⊥ ) = 0
⇒ (a ≡
b) = 1 |
| |
| Theorem | wwcomd 206 |
Commutation dual (weak). Kalmbach 83 p. 23.
|
| a⊥ C b
⇒ a = ((a ∪ b)
∩ (a ∪ b⊥ )) |
| |
| Theorem | wwcom3ii 207 |
Lemma 3(ii) (weak) of Kalmbach 83 p. 23.
|
| b⊥ C a
⇒ (a ∩
(a⊥ ∪ b)) = (a ∩
b) |
| |
| Theorem | wwfh1 208 |
Foulis-Holland Theorem (weak).
|
| b C a & c C a
⇒ ((a ∩
(b ∪ c)) ≡ ((a
∩ b) ∪ (a ∩ c))) =
1 |
| |
| Theorem | wwfh2 209 |
Foulis-Holland Theorem (weak).
|
| a C b & c⊥ C a
⇒ ((b ∩
(a ∪ c)) ≡ ((b
∩ a) ∪ (b ∩ c))) =
1 |
| |
| Theorem | wwfh3 210 |
Foulis-Holland Theorem (weak).
|
| b⊥ C a & c⊥ C a
⇒ ((a ∪
(b ∩ c)) ≡ ((a
∪ b) ∩ (a ∪ c))) =
1 |
| |
| Theorem | wwfh4 211 |
Foulis-Holland Theorem (weak).
|
| a⊥ C b & c C a
⇒ ((b ∪
(a ∩ c)) ≡ ((b
∪ a) ∩ (b ∪ c))) =
1 |
| |
| Theorem | womao 212 |
Weak OM-like absorption law for ortholattices.
|
| (a⊥ ∩ (a ∪ (a⊥ ∩ (a ∪ b)))) =
(a⊥ ∩ (a ∪ b)) |
| |
| Theorem | womaon 213 |
Weak OM-like absorption law for ortholattices.
|
| (a
∩ (a⊥ ∪ (a ∩ (a⊥ ∪ b)))) = (a
∩ (a⊥ ∪ b)) |
| |
| Theorem | womaa 214 |
Weak OM-like absorption law for ortholattices.
|
| (a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) =
(a⊥ ∪ (a ∩ b)) |
| |
| Theorem | womaan 215 |
Weak OM-like absorption law for ortholattices.
|
| (a
∪ (a⊥ ∩ (a ∪ (a⊥ ∩ b)))) = (a
∪ (a⊥ ∩ b)) |
| |
| Theorem | anorabs2 216 |
Absorption law for ortholattices.
|
| (a
∩ (b ∪ (a ∩ (b
∪ c)))) = (a ∩ (b
∪ c)) |
| |
| Theorem | anorabs 217 |
Absorption law for ortholattices.
|
| (a⊥ ∩ (b ∪ (a⊥ ∩ (a ∪ b)))) =
(a⊥ ∩ (a ∪ b)) |
| |
| Theorem | ska2a 218 |
Axiom KA2a in Pavicic and Megill, 1998
|
| (((a ∪ c)
≡ (b ∪ c)) ≡ ((c
∪ a) ≡ (c ∪ b))) =
1 |
| |
| Theorem | ska2b 219 |
Axiom KA2b in Pavicic and Megill, 1998
|
| (((a ∪ c)
≡ (b ∪ c)) ≡ ((a⊥ ∩ c⊥ )⊥ ≡
(b⊥ ∩ c⊥ )⊥ )) =
1 |
| |
| Theorem | ka4lemo 220 |
Lemma for KA4 soundness (OR version) - uses OL only.
|
| ((a ∪ b)
∪ ((a ∪ c) ≡ (b
∪ c))) = 1 |
| |
| Theorem | ka4lem 221 |
Lemma for KA4 soundness (AND version) - uses OL only.
|
| ((a ∩ b)⊥ ∪ ((a ∩ c)
≡ (b ∩ c))) = 1 |
| |
| Theorem | sklem 222 |
Soundness lemma.
|
| a
≤ b
⇒ (a⊥ ∪ b) = 1 |
| |
| Theorem | ska1 223 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA1.
|
| (a
≡ a) = 1 |
| |
| Theorem | ska3 224 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA3.
|
| ((a ≡ b)⊥ ∪ (a⊥ ≡ b⊥ )) = 1 |
| |
| Theorem | ska5 225 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA5.
|
| ((a ∩ b)
≡ (b ∩ a)) = 1 |
| |
| Theorem | ska6 226 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA6.
|
| ((a ∩ (b
∩ c)) ≡ ((a ∩ b)
∩ c)) = 1 |
| |
| Theorem | ska7 227 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA7.
|
| ((a ∩ (a
∪ b)) ≡ a) = 1 |
| |
| Theorem | ska8 228 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA8.
|
| ((a⊥ ∩ a) ≡ ((a⊥ ∩ a) ∩ b)) =
1 |
| |
| Theorem | ska9 229 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA9.
|
| (a
≡ a⊥
⊥ ) = 1 |
| |
| Theorem | ska10 230 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA10.
|
| ((a ∪ b)⊥ ≡ (a⊥ ∩ b⊥ )) = 1 |
| |
| Theorem | ska11 231 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA11.
|
| ((a ∪ (a⊥ ∩ (a ∪ b)))
≡ (a ∪ b)) = 1 |
| |
| Theorem | ska12 232 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA12.
|
| ((a ≡ b)
≡ (b ≡ a)) = 1 |
| |
| Theorem | ska13 233 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA13.
|
| ((a ≡ b)⊥ ∪ (a⊥ ∪ b)) = 1 |
| |
| Theorem | skr0 234 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KR0.
|
| a
= 1 & (a⊥ ∪ b) = 1
⇒ b = 1 |
| |
| Theorem | wlem1 235 |
Lemma for 2-variable WOML proof.
|
| ((a ≡ b)⊥ ∪ ((a →1 b) ∩ (b
→1 a))) = 1 |
| |
| Theorem | ska15 236 |
Soundness theorem for Kalmbach's quantum propositional logic axiom KA15.
|
| ((a →3 b)⊥ ∪ (a⊥ ∪ b)) = 1 |
| |
| Theorem | skmp3 237 |
Soundness proof for KMP3.
|
| a
= 1 & (a →3 b) = 1
⇒ b = 1 |
| |
| Theorem | lei3 238 |
L.e. to Kalmbach implication.
|
| a
≤ b
⇒ (a →3
b) = 1 |
| |
| Theorem | mccune2 239 |
E2 - OL theorem proved by EQP
|
| (a
∪ ((a⊥ ∩
((a ∪ b⊥ ) ∩ (a ∪ b)))
∪ (a⊥ ∩
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))))) = 1 |
| |
| Theorem | mccune3 240 |
E3 - OL theorem proved by EQP
|
| ((((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ (a ∩ (a⊥ ∪ b)))⊥ ∪ (a⊥ ∪ b)) = 1 |
| |
| Theorem | i3n1 241 |
Equivalence for Kalmbach implication.
|
| (a⊥ →3 b⊥ ) = (((a ∩ b⊥ ) ∪ (a ∩ b))
∪ (a⊥ ∩ (a ∪ b⊥ ))) |
| |
| Theorem | ni31 242 |
Equivalence for Kalmbach implication.
|
| (a
→3 b)⊥ =
(((a ∪ b⊥ ) ∩ (a ∪ b))
∩ (a⊥ ∪ (a ∩ b⊥ ))) |
| |
| Theorem | i3id 243 |
Identity for Kalmbach implication.
|
| (a
→3 a) = 1 |
| |
| Theorem | li3 244 |
Introduce Kalmbach implication to the left.
|
| a
= b
⇒ (c →3
a) = (c →3 b) |
| |
| Theorem | ri3 245 |
Introduce Kalmbach implication to the right.
|
| a
= b
⇒ (a →3
c) = (b →3 c) |
| |
| Theorem | 2i3 246 |
Join both sides with Kalmbach implication.
|
| a
= b
& c = d
⇒ (a →3
c) = (b →3 d) |
| |
| Theorem | ud1lem0a 247 |
Introduce →1 to the left.
|
| a
= b
⇒ (c →1
a) = (c →1 b) |
| |
| Theorem | ud1lem0b 248 |
Introduce →1 to the right.
|
| a
= b
⇒ (a →1
c) = (b →1 c) |
| |
| Theorem | ud1lem0ab 249 |
Join both sides of hypotheses with →1 .
|
| a
= b
& c = d
⇒ (a →1
c) = (b →1 d) |
| |
| Theorem | ud2lem0a 250 |
Introduce →2 to the left.
|
| a
= b
⇒ (c →2
a) = (c →2 b) |
| |
| Theorem | ud2lem0b 251 |
Introduce →2 to the right.
|
| a
= b
⇒ (a →2
c) = (b →2 c) |
| |
| Theorem | ud3lem0a 252 |
Introduce Kalmbach implication to the left.
|
| a
= b
⇒ (c →3
a) = (c →3 b) |
| |
| Theorem | ud3lem0b 253 |
Introduce Kalmbach implication to the right.
|
| a
= b
⇒ (a →3
c) = (b →3 c) |
| |
| Theorem | ud4lem0a 254 |
Introduce →4 to the left.
|
| a
= b
⇒ (c →4
a) = (c →4 b) |
| |
| Theorem | ud4lem0b 255 |
Introduce →4 to the right.
|
| a
= b
⇒ (a →4
c) = (b →4 c) |
| |
| Theorem | ud5lem0a 256 |
Introduce →5 to the left.
|
| a
= b
⇒ (c →5
a) = (c →5 b) |
| |
| Theorem | ud5lem0b 257 |
Introduce →5 to the right.
|
| a
= b
⇒ (a →5
c) = (b →5 c) |
| |
| Theorem | i1i2 258 |
Correspondence between Sasaki and Dishkant conditionals.
|
| (a
→1 b) = (b⊥ →2 a⊥ ) |
| |
| Theorem | i2i1 259 |
Correspondence between Sasaki and Dishkant conditionals.
|
| (a
→2 b) = (b⊥ →1 a⊥ ) |
| |
| Theorem | i1i2con1 260 |
Correspondence between Sasaki and Dishkant conditionals.
|
| (a
→1 b⊥ ) =
(b →2 a⊥ ) |
| |
| Theorem | i1i2con2 261 |
Correspondence between Sasaki and Dishkant conditionals.
|
| (a⊥ →1 b) = (b⊥ →2 a) |
| |
| Theorem | i3i4 262 |
Correspondence between Kalmbach and non-tollens conditionals.
|
| (a
→3 b) = (b⊥ →4 a⊥ ) |
| |
| Theorem | i4i3 263 |
Correspondence between Kalmbach and non-tollens conditionals.
|
| (a
→4 b) = (b⊥ →3 a⊥ ) |
| |
| Theorem | i5con 264 |
Converse of →5 .
|
| (a
→5 b) = (b⊥ →5 a⊥ ) |
| |
| Theorem | 0i1 265 |
Antecedent of 0 on Sasaki conditional.
|
| (0 →1 a) = 1 |
| |
| Theorem | 1i1 266 |
Antecedent of 1 on Sasaki conditional.
|
| (1 →1 a) = a |
| |
| Theorem | i1id 267 |
Identity law for Sasaki conditional.
|
| (a
→1 a) = 1 |
| |
| Theorem | i2id 268 |
Identity law for Dishkant conditional.
|
| (a
→2 a) = 1 |
| |
| Theorem | ud1lem0c 269 |
Lemma for unified disjunction.
|
| (a
→1 b)⊥ =
(a ∩ (a⊥ ∪ b⊥ )) |
| |
| Theorem | ud2lem0c 270 |
Lemma for unified disjunction.
|
| (a
→2 b)⊥ =
(b⊥ ∩ (a ∪ b)) |
| |
| Theorem | ud3lem0c 271 |
Lemma for unified disjunction.
|
| (a
→3 b)⊥ =
(((a ∪ b⊥ ) ∩ (a ∪ b))
∩ (a⊥ ∪ (a ∩ b⊥ ))) |
| |
| Theorem | ud4lem0c 272 |
Lemma for unified disjunction.
|
| (a
→4 b)⊥ =
(((a⊥ ∪ b⊥ ) ∩ (a ∪ b⊥ )) ∩ ((a ∩ b⊥ ) ∪ b)) |
| |
| Theorem | ud5lem0c 273 |
Lemma for unified disjunction.
|
| (a
→5 b)⊥ =
(((a⊥ ∪ b⊥ ) ∩ (a ∪ b⊥ )) ∩ (a ∪ b)) |
| |
| Theorem | bina1 274 |
Pavicic binary logic ax-a1 analog.
|
| (a
→3 a⊥
⊥ ) = 1 |
| |
| Theorem | bina2 275 |
Pavicic binary logic ax-a2 analog.
|
| (a⊥ ⊥ →3
a) = 1 |
| |
| Theorem | bina3 276 |
Pavicic binary logic ax-a3 analog.
|
| (a
→3 (a ∪ b)) = 1 |
| |
| Theorem | bina4 277 |
Pavicic binary logic ax-a4 analog.
|
| (b
→3 (a ∪ b)) = 1 |
| |
| Theorem | bina5 278 |
Pavicic binary logic ax-a5 analog.
|
| (b
→3 (a ∪ a⊥ )) = 1 |
| |
| Theorem | wql1lem 279 |
Classical implication inferred from Sakaki implication.
|
| (a
→1 b) =
1 ⇒ (a⊥ ∪ b) = 1 |
| |
| Theorem | wql2lem 280 |
Classical implication inferred from Dishkant implication.
|
| (a
→2 b) =
1 ⇒ (a⊥ ∪ b) = 1 |
| |
| Theorem | wql2lem2 281 |
Lemma for →2 WQL axiom.
|
| ((a ∪ c)
→2 (b ∪ c)) = 1
⇒ ((a ∪
(b ∪ c))⊥ ∪ (b ∪ c)) =
1 |
| |
| Theorem | wql2lem3 282 |
Lemma for →2 WQL axiom.
|
| (a
→2 b) =
1 ⇒ ((a ∩ b⊥ ) →2 a⊥ ) = 1 |
| |
| Theorem | wql2lem4 283 |
Lemma for →2 WQL axiom.
|
| (((a ∩ b⊥ ) ∪ (a ∩ b))
→2 (a⊥
∪ (a ∩ b))) = 1
& ((a →1
b) ∪ (a ∩ b⊥ )) = 1
⇒ (a →1
b) = 1 |
| |
| Theorem | wql2lem5 284 |
Lemma for →2 WQL axiom.
|
| (a
→2 b) =
1 ⇒ ((b⊥ ∩ (a ∪ b))
→2 a⊥ ) =
1 |
| |
| Theorem | wql1 285 |
The 2nd hypothesis is the first →1 WQL axiom. We show it
implies the WOM law.
|
| (a
→1 b) =
1 & ((a ∪ c)
→1 (b ∪ c)) = 1
& c = b
⇒ (a →2
b) = 1 |
| |
| Theorem | oaidlem1 286 |
Lemma for OA identity-like law.
|
| (a
∩ b) ≤ c
⇒ (a⊥ ∪ (b →1 c)) = 1 |
| |
| Theorem | womle2a 287 |
An equivalent to the WOM law.
|
| (a
∩ (a →2 b)) ≤ ((a
→2 b)⊥
∪ (a →1 b))
⇒ ((a →2
b)⊥ ∪ (a →1 b)) = 1 |
| |
| Theorem | womle2b 288 |
An equivalent to the WOM law.
|
| ((a →2 b)⊥ ∪ (a →1 b)) = 1
⇒ (a ∩
(a →2 b)) ≤ ((a
→2 b)⊥
∪ (a →1 b)) |
| |
| Theorem | womle3b 289 |
Implied by the WOM law.
|
| ((a →1 b)⊥ ∪ (a →2 b)) = 1
⇒ (a ∩
(a →1 b)) ≤ ((a
→1 b)⊥
∪ (a →2 b)) |
| |
| Theorem | womle 290 |
An equality implying the WOM law.
|
| (a
∩ (a →1 b)) = (a ∩
(a →2 b))
⇒ ((a →2
b)⊥ ∪ (a →1 b)) = 1 |
| |
| Theorem | nomb41 291 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡4 b) = (b ≡1 a) |
| |
| Theorem | nomb32 292 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡3 b) = (b ≡2 a) |
| |
| Theorem | nomcon0 293 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡0 b) = (b⊥ ≡0 a⊥ ) |
| |
| Theorem | nomcon1 294 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡1 b) = (b⊥ ≡2 a⊥ ) |
| |
| Theorem | nomcon2 295 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡2 b) = (b⊥ ≡1 a⊥ ) |
| |
| Theorem | nomcon3 296 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡3 b) = (b⊥ ≡4 a⊥ ) |
| |
| Theorem | nomcon4 297 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡4 b) = (b⊥ ≡3 a⊥ ) |
| |
| Theorem | nomcon5 298 |
Lemma for "Non-Orthomodular Models..." paper.
|
| (a
≡ b) = (b⊥ ≡ a⊥ ) |
| |
| Theorem | nom10 299 |
Part of Lemma 3.3(14) from "Non-Orthomodular Models..." paper.
|
| (a
→0 (a ∩ b)) = (a
→1 b) |
| |
| Theorem | nom11 300 |
Part of Lemma 3.3(14) from "Non-Orthomodular Models..." paper.
|
| (a
→1 (a ∩ b)) = (a
→1 b) |