Statement List for Quantum Logic Explorer - 701-800 - Page 8 of 11
| Type | Label | Description |
| Statement |
| |
| Theorem | u5lemle2 701 |
Relevance implication to l.e.
|
| (a
→5 b) =
1 ⇒ a ≤ b |
| |
| Theorem | u1lembi 702 |
Sasaki implication and biconditional.
|
| ((a →1 b) ∩ (b
→1 a)) = (a ≡ b) |
| |
| Theorem | u2lembi 703 |
Dishkant implication and biconditional.
|
| ((a →2 b) ∩ (b
→2 a)) = (a ≡ b) |
| |
| Theorem | i2bi 704 |
Dishkant implication expressed with biconditional.
|
| (a
→2 b) = (b ∪ (a
≡ b)) |
| |
| Theorem | u3lembi 705 |
Kalmbach implication and biconditional.
|
| ((a →3 b) ∩ (b
→3 a)) = (a ≡ b) |
| |
| Theorem | u4lembi 706 |
Non-tollens implication and biconditional.
|
| ((a →4 b) ∩ (b
→4 a)) = (a ≡ b) |
| |
| Theorem | u5lembi 707 |
Relevance implication and biconditional.
|
| ((a →5 b) ∩ (b
→5 a)) = (a ≡ b) |
| |
| Theorem | u12lembi 708 |
Sasaki/Dishkant implication and biconditional.
|
| ((a →1 b) ∩ (b
→2 a)) = (a ≡ b) |
| |
| Theorem | u21lembi 709 |
Dishkant/Sasaki implication and biconditional.
|
| ((a →2 b) ∩ (b
→1 a)) = (a ≡ b) |
| |
| Theorem | ublemc1 710 |
Commutation theorem for biimplication.
|
| a C (a
≡ b) |
| |
| Theorem | ublemc2 711 |
Commutation theorem for biimplication.
|
| b C (a
≡ b) |
| |
| Theorem | u1lemn1b 712 |
This theorem continues the line of proofs such as u1lemnaa 622, ud1lem0b 248,
u1lemnanb 637, etc. (Contributed by Josiah Burroughs
26-May-04.)
|
| (a
→1 b) = ((a →1 b)⊥ →1 b) |
| |
| Theorem | u1lem3var1 713 |
A 3-variable formula. (Contributed by Josiah Burroughs 26-May-04.)
|
| (((a →1 c) ∩ (b
→1 c))⊥
∪ (((a →1 c)⊥ →1 c) ∩ ((b
→1 c)⊥
→1 c))) = 1 |
| |
| Theorem | oi3oa3lem1 714 |
An attempt at the OA3 conjecture, which is true if (a ≡ b) =
1.
(Contributed by Josiah Burroughs 27-May-04.)
|
| 1 = (b ≡ a)
⇒ (((a →1
c) ∩ (b →1 c)) ∪ (a
∩ b)) = 1 |
| |
| Theorem | oi3oa3 715 |
An attempt at the OA3 conjecture, which is true if (a ≡ b) =
1.
(Contributed by Josiah Burroughs 27-May-04.)
|
| 1 = (b ≡ a)
⇒ (((a →1
c) ∩ (b →1 c)) ∪ ((((a
→1 c) ∩ (((a →1 c) ∩ (b
→1 c)) ∪ (a ∩ b)))
→1 c) ∩ (((b →1 c) ∩ (((a
→1 c) ∩ (b →1 c)) ∪ (a
∩ b))) →1 c))) = 1 |
| |
| Theorem | u1lem1 716 |
Lemma for unified implication study.
|
| ((a →1 b) →1 a) = a |
| |
| Theorem | u2lem1 717 |
Lemma for unified implication study.
|
| ((a →2 b) →2 a) = a |
| |
| Theorem | u3lem1 718 |
Lemma for unified implication study.
|
| ((a →3 b) →3 a) = ((a ∪
b) ∩ (a ∪ b⊥ )) |
| |
| Theorem | u4lem1 719 |
Lemma for unified implication study.
|
| ((a →4 b) →4 a) = ((((a
∩ b) ∪ (a ∩ b⊥ )) ∪ a⊥ ) ∩ ((a ∪ b)
∩ (a ∪ b⊥ ))) |
| |
| Theorem | u5lem1 720 |
Lemma for unified implication study.
|
| ((a →5 b) →5 a) = ((a ∪
b) ∩ (a ∪ b⊥ )) |
| |
| Theorem | u1lem1n 721 |
Lemma for unified implication study.
|
| ((a →1 b) →1 a)⊥ = a⊥ |
| |
| Theorem | u2lem1n 722 |
Lemma for unified implication study.
|
| ((a →2 b) →2 a)⊥ = a⊥ |
| |
| Theorem | u3lem1n 723 |
Lemma for unified implication study.
|
| ((a →3 b) →3 a)⊥ = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) |
| |
| Theorem | u4lem1n 724 |
Lemma for unified implication study.
|
| ((a →4 b) →4 a)⊥ = ((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| |
| Theorem | u5lem1n 725 |
Lemma for unified implication study.
|
| ((a →5 b) →5 a)⊥ = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) |
| |
| Theorem | u1lem2 726 |
Lemma for unified implication study.
|
| (((a →1 b) →1 a) →1 a) = 1 |
| |
| Theorem | u2lem2 727 |
Lemma for unified implication study.
|
| (((a →2 b) →2 a) →2 a) = 1 |
| |
| Theorem | u3lem2 728 |
Lemma for unified implication study.
|
| (((a →3 b) →3 a) →3 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| |
| Theorem | u4lem2 729 |
Lemma for unified implication study.
|
| (((a →4 b) →4 a) →4 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| |
| Theorem | u5lem2 730 |
Lemma for unified implication study.
|
| (((a →5 b) →5 a) →5 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| |
| Theorem | u1lem3 731 |
Lemma for unified implication study.
|
| (a
→1 (b →1
a)) = (a⊥ ∪ ((a ∩ b)
∪ (a ∩ b⊥ ))) |
| |
| Theorem | u2lem3 732 |
Lemma for unified implication study.
|
| (a
→2 (b →2
a)) = 1 |
| |
| Theorem | u3lem3 733 |
Lemma for unified implication study.
|
| (a
→3 (b →3
a)) = (a ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| |
| Theorem | u4lem3 734 |
Lemma for unified implication study.
|
| (a
→4 (b →4
a)) = (a⊥ ∪ ((a ∩ b)
∪ (a ∩ b⊥ ))) |
| |
| Theorem | u5lem3 735 |
Lemma for unified implication study.
|
| (a
→5 (b →5
a)) = (a⊥ ∪ ((a ∩ b)
∪ (a ∩ b⊥ ))) |
| |
| Theorem | u3lem3n 736 |
Lemma for unified implication study.
|
| (a
→3 (b →3
a))⊥ = (a⊥ ∩ ((a ∪ b)
∩ (a ∪ b⊥ ))) |
| |
| Theorem | u4lem3n 737 |
Lemma for unified implication study.
|
| (a
→4 (b →4
a))⊥ = (a ∩ ((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ ))) |
| |
| Theorem | u5lem3n 738 |
Lemma for unified implication study.
|
| (a
→5 (b →5
a))⊥ = (a ∩ ((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ ))) |
| |
| Theorem | u1lem4 739 |
Lemma for unified implication study.
|
| (a
→1 (a →1
(b →1 a))) = (a
→1 (b →1
a)) |
| |
| Theorem | u3lem4 740 |
Lemma for unified implication study.
|
| (a
→3 (a →3
(b →3 a))) = 1 |
| |
| Theorem | u4lem4 741 |
Lemma for unified implication study.
|
| (a
→4 (a →4
(b →4 a))) = (a
→4 (b →4
a)) |
| |
| Theorem | u5lem4 742 |
Lemma for unified implication study.
|
| (a
→5 (a →5
(b →5 a))) = (a
→5 (b →5
a)) |
| |
| Theorem | u1lem5 743 |
Lemma for unified implication study.
|
| (a
→1 (a →1
b)) = (a →1 b) |
| |
| Theorem | u2lem5 744 |
Lemma for unified implication study.
|
| (a
→2 (a →2
b)) = (a →2 b) |
| |
| Theorem | u3lem5 745 |
Lemma for unified implication study.
|
| (a
→3 (a →3
b)) = (a⊥ ∪ b) |
| |
| Theorem | u4lem5 746 |
Lemma for unified implication study.
|
| (a
→4 (a →4
b)) = ((a⊥ ∩ b⊥ ) ∪ b) |
| |
| Theorem | u5lem5 747 |
Lemma for unified implication study.
|
| (a
→5 (a →5
b)) = (a⊥ ∪ (a ∩ b)) |
| |
| Theorem | u4lem5n 748 |
Lemma for unified implication study.
|
| (a
→4 (a →4
b))⊥ = ((a ∪ b)
∩ b⊥ ) |
| |
| Theorem | u3lem6 749 |
Lemma for unified implication study.
|
| (a
→3 (a →3
(a →3 b))) = (a
→3 (a →3
b)) |
| |
| Theorem | u4lem6 750 |
Lemma for unified implication study.
|
| (a
→4 (a →4
(a →4 b))) = (a
→4 b) |
| |
| Theorem | u5lem6 751 |
Lemma for unified implication study.
|
| (a
→5 (a →5
(a →5 b))) = (a
→5 (a →5
b)) |
| |
| Theorem | u24lem 752 |
Lemma for unified implication study.
|
| ((a →2 b) ∩ (a
→4 b)) = (a →5 b) |
| |
| Theorem | u12lem 753 |
Implication lemma.
|
| ((a →1 b) ∪ (a
→2 b)) = (a →0 b) |
| |
| Theorem | u1lem7 754 |
Lemma for unified implication study.
|
| (a
→1 (a⊥
→1 b)) = 1 |
| |
| Theorem | u2lem7 755 |
Lemma for unified implication study.
|
| (a
→2 (a⊥
→2 b)) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b) |
| |
| Theorem | u3lem7 756 |
Lemma for unified implication study.
|
| (a
→3 (a⊥
→3 b)) = (a⊥ ∪ ((a ∩ b)
∪ (a ∩ b⊥ ))) |
| |
| Theorem | u2lem7n 757 |
Lemma for unified implication study.
|
| (a
→2 (a⊥
→2 b))⊥ =
(((a ∪ b) ∩ (a⊥ ∪ b)) ∩ b⊥ ) |
| |
| Theorem | u1lem8 758 |
Lemma used in study of orthoarguesian law.
|
| ((a →1 b) ∩ (a⊥ →1 b)) = ((a ∩
b) ∪ (a⊥ ∩ b)) |
| |
| Theorem | u1lem9a 759 |
Lemma used in study of orthoarguesian law.
|
| (a⊥ →1 b)⊥ ≤ a⊥ |
| |
| Theorem | u1lem9b 760 |
Lemma used in study of orthoarguesian law.
|
| a⊥ ≤ (a →1 b) |
| |
| Theorem | u1lem9ab 761 |
Lemma used in study of orthoarguesian law.
|
| (a⊥ →1 b)⊥ ≤ (a →1 b) |
| |
| Theorem | u1lem11 762 |
Lemma used in study of orthoarguesian law.
|
| ((a⊥ →1 b) →1 b) = (a
→1 b) |
| |
| Theorem | u1lem12 763 |
Lemma used in study of orthoarguesian law.
|
| ((a →1 b) →1 b) = (a⊥ →1 b) |
| |
| Theorem | u2lem8 764 |
Lemma for unified implication study.
|
| (a⊥ →2 (a →2 (a⊥ →2 b))) = (a
→2 (a⊥
→2 b)) |
| |
| Theorem | u3lem8 765 |
Lemma for unified implication study.
|
| (a⊥ →3 (a →3 (a⊥ →3 b))) = 1 |
| |
| Theorem | u3lem9 766 |
Lemma for unified implication study.
|
| (a
→3 (a →3
(a⊥ →3
b))) = (a →3 (a⊥ →3 b)) |
| |
| Theorem | u3lem10 767 |
Lemma for unified implication study.
|
| (a
→3 (a⊥
∩ (a ∪ b))) = a⊥ |
| |
| Theorem | u3lem11 768 |
Lemma for unified implication study.
|
| (a
→3 (b⊥
∩ (a ∪ b))) = (a
→3 b⊥
) |
| |
| Theorem | u3lem11a 769 |
Lemma for unified implication study.
|
| (a
→3 ((b →3
a) →3 (a →3 b))⊥ ) = (a →3 b⊥ ) |
| |
| Theorem | u3lem12 770 |
Lemma for unified implication study.
|
| (a
→3 (a →3
b⊥
))⊥ = (a ∩ b) |
| |
| Theorem | u3lem13a 771 |
Lemma for unified implication study.
|
| (a
→3 (a →3
b⊥
)⊥ ) = (a →1
b) |
| |
| Theorem | u3lem13b 772 |
Lemma for unified implication study.
|
| ((a →3 b⊥ ) →3 a⊥ ) = (a →1 b) |
| |
| Theorem | u3lem14a 773 |
Lemma for unified implication study.
|
| (a
→3 ((b →3
a⊥ ) →3
b⊥ )) = (a →3 (b →3 a)) |
| |
| Theorem | u3lem14aa 774 |
Used to prove →1 "add antecedent" rule in
→3 system.
|
| (a
→3 (a →3
((b →3 a⊥ ) →3 b⊥ ))) = 1 |
| |
| Theorem | u3lem14aa2 775 |
Used to prove →1 "add antecedent" rule in
→3 system.
|
| (a
→3 (a →3
(b →3 (b →3 a⊥ )⊥ ))) =
1 |
| |
| Theorem | u3lem14mp 776 |
Used to prove →1 modus ponens rule in →3
system.
|
| ((a →3 b⊥ )⊥
→3 (a →3
(a →3 b))) = 1 |
| |
| Theorem | u3lem15 777 |
Lemma for Kalmbach implication.
|
| ((a →3 b) ∩ (a
∪ b)) = ((a⊥ ∪ b) ∩ (a
∪ (a⊥ ∩ b))) |
| |
| Theorem | u3lemax4 778 |
Possible axiom for Kalmbach implication system.
|
| ((a →3 b) →3 ((a →3 b) →3 ((b →3 a) →3 ((b →3 a) →3 ((c →3 (c →3 a)) →3 (c →3 (c →3 b))))))) = 1 |
| |
| Theorem | u3lemax5 779 |
Possible axiom for Kalmbach implication system.
|
| ((a →3 b) →3 ((a →3 b) →3 ((b →3 a) →3 ((b →3 a) →3 ((b →3 c) →3 ((b →3 c) →3 ((c →3 b) →3 ((c →3 b) →3 (a →3 c))))))))) = 1 |
| |
| Theorem | bi1o1a 780 |
Equivalence to biconditional.
|
| (a
≡ b) = ((a →1 (a ∩ b))
∩ ((a ∪ b) →1 a)) |
| |
| Theorem | biao 781 |
Equivalence to biconditional.
|
| (a
≡ b) = ((a ∩ b)
≡ (a ∪ b)) |
| |
| Theorem | i2i1i1 782 |
Equivalence to →2 .
|
| (a
→2 b) = ((a →1 (a ∪ b))
∩ ((a ∪ b) →1 b)) |
| |
| Theorem | i1abs 783 |
An absorption law for →1 .
|
| ((a →1 b)⊥ ∪ (a ∩ b)) =
a |
| |
| Theorem | test 784 |
Part of an attempt to crack a potential Kalmbach axiom.
|
| (((c ∪ (a⊥ ∪ b⊥ )) ∩ (c⊥ ∩ (c ∪ (a
∩ b)))) ∪ ((c⊥ ∩ (a ∩ b))
∪ (c ∩ (c⊥ ∪ (a ∩ b)))))
= ((c ∪ (a ∩ b))
∩ (c⊥ ∪ (a ∩ b))) |
| |
| Theorem | test2 785 |
Part of an attempt to crack a potential Kalmbach axiom.
|
| (a
∪ b) ≤ ((a ≡ b)⊥ ∪ ((c ∪ (a
∩ b)) ∩ (c⊥ ∪ (a ∩ b)))) |
| |
| Theorem | 3vth1 786 |
A 3-variable theorem. Equivalent to OML.
|
| ((a →2 b) ∩ (b
∪ c)⊥ ) ≤
(a →2 c) |
| |
| Theorem | 3vth2 787 |
A 3-variable theorem. Equivalent to OML.
|
| ((a →2 b) ∩ (b
∪ c)⊥ ) = ((a →2 c) ∩ (b
∪ c)⊥ ) |
| |
| Theorem | 3vth3 788 |
A 3-variable theorem. Equivalent to OML.
|
| ((a →2 c) ∪ ((a
→2 b) ∩ (b ∪ c)⊥ )) = (a →2 c) |
| |
| Theorem | 3vth4 789 |
A 3-variable theorem.
|
| ((a →2 b)⊥ →2 (b ∪ c)) =
((a →2 c)⊥ →2 (b ∪ c)) |
| |
| Theorem | 3vth5 790 |
A 3-variable theorem.
|
| ((a →2 b)⊥ →2 (b ∪ c)) =
(c ∪ ((a →2 b) ∩ (c
→2 b))) |
| |
| Theorem | 3vth6 791 |
A 3-variable theorem.
|
| ((a →2 b)⊥ →2 (b ∪ c)) =
(((a →2 b) ∩ (c
→2 b)) ∪ ((a →2 c) ∩ (b
→2 c))) |
| |
| Theorem | 3vth7 792 |
A 3-variable theorem.
|
| ((a →2 b)⊥ →2 (b ∪ c)) =
(a →2 (b ∪ c)) |
| |
| Theorem | 3vth8 793 |
A 3-variable theorem.
|
| (a
→2 (b ∪ c)) = (((a
→2 b) ∩ (c →2 b)) ∪ ((a
→2 c) ∩ (b →2 c))) |
| |
| Theorem | 3vth9 794 |
A 3-variable theorem.
|
| ((a ∪ b)
→1 (c →2
b)) = ((b ∪ c)
→2 (a →2
b)) |
| |
| Theorem | 3vcom 795 |
3-variable commutation theorem
|
| ((a →1 c) ∪ (b
→1 c)) C ((a⊥ →1 c) ∩ (b⊥ →1 c)) |
| |
| Theorem | 3vded11 796 |
A 3-variable theorem. Experiment with weak deduction theorem.
|
| b
≤ (c →1 (b →1 a))
⇒ c ≤ (b →1 a) |
| |
| Theorem | 3vded12 797 |
A 3-variable theorem. Experiment with weak deduction theorem.
|
| (a
∩ (c →1 a)) ≤ (c
→1 (b →1
a))
& c ≤ a
⇒ c ≤ (b →1 a) |
| |
| Theorem | 3vded13 798 |
A 3-variable theorem. Experiment with weak deduction theorem.
|
| (b
∩ (c →1 a)) ≤ (c
→1 (b →1
a))
& c ≤ a
⇒ c ≤ (b →1 a) |
| |
| Theorem | 3vded21 799 |
A 3-variable theorem. Experiment with weak deduction theorem.
|
| c
≤ ((a →0 b) →0 (c →2 b))
& c ≤ (a →0 b)
⇒ c ≤ b |
| |
| Theorem | 3vded22 800 |
A 3-variable theorem. Experiment with weak deduction theorem.
|
| c
≤ ( C (a, b) ∪ C (c, b))
& c ≤ a & c ≤ (a
→0 b)
⇒ c ≤ b |